Problem 17
Question
Determine the following limits. $$\lim _{\theta \rightarrow \infty} \frac{\cos \theta}{\theta^{2}}$$
Step-by-Step Solution
Verified Answer
Answer: The limit of the function \(\frac{\cos{\theta}}{\theta^2}\) as \(\theta\) approaches infinity is 0.
1Step 1: Determine if the Limit is Indeterminate
First, let's determine if the given limit is indeterminate. As \(\theta\) approaches infinity, the denominator \(\theta^2\) approaches infinity. The numerator \(\cos \theta\) is a trigonometric function that oscillates between -1 and 1. The given limit is of the form \(\frac{f(\theta)}{g(\theta)}\), where \(f(\theta)=\cos\theta\) and \(g(\theta)=\theta^2\). Since \(g(\theta)\rightarrow\infty\) as \(\theta\rightarrow\infty\), the function is indeterminate of the form \(\frac{1}{\infty}\).
2Step 2: Apply L'Hôpital's Rule
As the expression is indeterminate, we apply L'Hôpital's rule which states:
$$\lim_{\theta\rightarrow\infty}\frac{f(\theta)}{g(\theta)}=\lim_{\theta \rightarrow \infty} \frac{f'(\theta)}{g'(\theta)}$$
if the resulting limit exists or is an indeterminate form of either \(0\cdot\infty, \frac{0}{0},\) or \(\frac{\infty}{\infty}\).
Differentiate the numerator and denominator of the expression with respect to \(\theta\).
Derivative of the numerator with respect to \(\theta\) is:
$$\frac{d}{d\theta}(\cos \theta)= -\sin \theta$$
Derivative of the denominator with respect to \(\theta\) is:
$$\frac{d}{d\theta}(\theta^2)= 2\theta$$
Now, let's rewrite the limit using the derivatives above.
3Step 3: Evaluate the Limit of the New Expression
We have the new expression as:
$$\lim_{\theta \rightarrow \infty} \frac{-\sin \theta}{2\theta}$$
Observe that \(-\sin \theta\) is bounded between -1 and 1. As \(\theta\) approaches infinity, the denominator \(2\theta\) approaches infinity. Hence, this limit is also of the form \(\frac{1}{\infty}\), which is equal to 0.
Answer:
$$\lim_{\theta \rightarrow \infty} \frac{\cos \theta}{\theta^2} = 0$$
Key Concepts
L'Hôpital's RuleIndeterminate FormsTrigonometric Limits
L'Hôpital's Rule
L'Hôpital's Rule is a crucial method in calculus used to find limits of indeterminate forms. Imagine you're approaching infinity or zero, and your limit doesn't lead to a straightforward solution. This is when L'Hôpital's Rule becomes incredibly useful. It helps us simplify complex expressions by differentiating the numerator and the denominator of a fraction.Here's how it works:
- Identify if the limit is of form \(\frac{0}{0}\) or \(\frac{\infty}{\infty}\). If so, L'Hôpital's Rule can be applied.
- Derivate both the numerator and the denominator separately.
- Recalculate the limit using the derivatives. Repeat the process if the indeterminate form persists.
Indeterminate Forms
Indeterminate forms arise when calculating limits that seem undefined or ambiguous at first glance. In calculus, these forms usually look like fractions or expressions that lead us to confusion, such as \(\frac{0}{0}\) or \(\frac{\infty}{\infty}\).These are common indeterminate forms:
- \(\frac{0}{0}\)
- \(\frac{\infty}{\infty}\)
- \(\infty - \infty\)
- \(0 \cdot \infty\)
- \(0^0, \infty^0, \text{and } 1^\infty\)
Trigonometric Limits
Trigonometric limits involve functions like sine, cosine, and tangent, which often show oscillating behavior. The key to understanding these limits is recognizing how these functions change as they approach certain angles or tend towards infinity.Consider these aspects:
- Functions such as \(\sin \theta\) and \(\cos \theta\) are bounded between -1 and 1 regardless of \(\theta\). This bounded nature aids in simplifying complex fractions when calculating limits.
- Trigonometric identities and known limits, such as \(\lim_{\theta \to 0}\frac{\sin \theta}{\theta} = 1\), are helpful tools.
Other exercises in this chapter
Problem 17
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