Problem 17
Question
Compare and contrast bonding molecular orbitals with antibonding molecular orbitals.
Step-by-Step Solution
Verified Answer
Bonding molecular orbitals (BMOs) form due to in-phase overlapping of atomic orbitals, resulting in lower energy levels and electron density between atomic nuclei. This stabilizes the molecule. Antibonding molecular orbitals (ABMOs) form due to out-of-phase overlapping of atomic orbitals, resulting in higher energy levels and decreased electron density between atomic nuclei. This destabilizes the molecule. Electrons fill bonding orbitals before antibonding orbitals, according to the Aufbau principle. The bond order is determined by \(\dfrac{(n_{BMO} - n_{ABMO})}{2}\) and indicates a stable molecule when positive.
1Step 1: 1. Formation of Molecular Orbitals
Bonding and antibonding molecular orbitals are formed due to the overlapping of atomic orbitals in a molecule. When two atomic orbitals overlap in-phase (constructive interference), a bonding molecular orbital is formed. When two atomic orbitals overlap out-of-phase (destructive interference), an antibonding molecular orbital is formed.
2Step 2: 2. Energy Levels
Bonding molecular orbitals (BMOs) are formed due to constructive interference and are lower in energy than the individual atomic orbitals (AOs) contributing to the BMO. Antibonding molecular orbitals (ABMOs) are formed due to destructive interference and are higher in energy than the individual atomic orbitals contributing to the ABMO.
3Step 3: 3. Electron Occupancy
Electrons in a molecule occupy molecular orbitals according to the Aufbau principle, which states that electrons fill orbitals in order of increasing energy. Since bonding molecular orbitals have lower energy than antibonding molecular orbitals, they are filled with electrons before the antibonding orbitals are filled.
4Step 4: 4. Effects on Bond Order
The bond order of a molecule is determined by the difference between the number of electrons in bonding orbitals and the number of electrons in antibonding orbitals, divided by 2: \(Bond\: order = \dfrac{(n_{BMO} - n_{ABMO})}{2}\). A positive bond order indicates a stable molecule, whereas a negative or zero bond order indicates an unstable or non-existent molecule. Bonding molecular orbitals stabilize the molecule by increasing the electron density between the atomic nuclei, which causes an attractive force between the positively charged nuclei of both atoms. Antibonding molecular orbitals destabilize the molecule by decreasing the electron density between the atomic nuclei, causing a repulsive force between the positively charged nuclei of both atoms.
Other exercises in this chapter
Problem 15
Why are \(d\) orbitals sometimes used to form hybrid orbitals? Which period of elements does not use \(d\) orbitals for hybridization? If necessary, which \(d\)
View solution Problem 16
The atoms in a single bond can rotate about the internuclear axis without breaking the bond. The atoms in a double and triple bond cannot rotate about the inter
View solution Problem 19
Why does the molecular orbital model do a better job in explaining the bonding in \(\mathrm{NO}^{-}\) and \(\mathrm{NO}\) than the hybrid orbital model?
View solution Problem 20
The three NO bonds in \(\mathrm{NO}_{3}^{-}\) are all equivalent in length and strength. How is this explained even though any valid Lewis structure for \(\math
View solution