Problem 17
Question
Choose a solution method to solve the linear system. Explain your choice, but do not solve the system. $$ \begin{aligned} &x+2 y=2\\\ &x+4 y=-2 \end{aligned} $$
Step-by-Step Solution
Verified Answer
The most optimal method to solve this system of linear equations is the elimination method. Using this method will easily lead to the elimination of the variable x, leaving a simplified equation with only the y-variable.
1Step 1: Identifying the System of Equations
The given system of equations is: \(x + 2y = 2\) and \(x + 4y = -2\). Note that the coefficients of x are the same in both equations.
2Step 2: Analysing the Equations
By observing the equations, it can be seen that the x is the same in both equations. So, if one equation is subtracted from the other, the variable x will be eliminated, resulting in a single equation with only the variable y.
3Step 3: Choosing the Solution Method
As deduced from the analysis, the elimination method will be the fitting choice here. By subtracting the second equation from the first one, the x-variable gets cancelled or eliminated, making the calculation much simpler.
Key Concepts
Elimination MethodSystem of EquationsAlgebraic MethodsLinear Algebra
Elimination Method
The elimination method is a fundamental technique in solving a system of linear equations. This algebraic approach involves manipulating the equations in a way that eliminates one variable, allowing you to solve for the other. The key is to create a scenario where adding or subtracting the equations results in one of the variables canceling itself out.
For example, if we are presented with equations like \(x + 2y = 2\) and \(x + 4y = -2\), we notice that the coefficients of \(x\) are the same. If one equation is subtracted from the other, we will have successfully eliminated \(x\), making it possible to find the value of \(y\) with ease. The elimination method is particularly useful when the system is made up of two or three equations; it provides a clear and strategic way to simplify complex systems.
For example, if we are presented with equations like \(x + 2y = 2\) and \(x + 4y = -2\), we notice that the coefficients of \(x\) are the same. If one equation is subtracted from the other, we will have successfully eliminated \(x\), making it possible to find the value of \(y\) with ease. The elimination method is particularly useful when the system is made up of two or three equations; it provides a clear and strategic way to simplify complex systems.
System of Equations
A system of equations consists of two or more equations that share a common set of variables. The goal when solving such a system is to find the values of the variables that satisfy all equations simultaneously. Systems of equations can be linear or non-linear, and the solutions can vary: one unique solution, infinitely many solutions, or no solution at all.
In the instance of \(x + 2y = 2\) and \(x + 4y = -2\), we are dealing with a linear system because each equation represents a straight line on a graph. The intersection of these lines, if it exists, would represent the solution to the system. Understanding the behaviors of these lines is crucial to determining the right method of solution and anticipating the type of solution set.
In the instance of \(x + 2y = 2\) and \(x + 4y = -2\), we are dealing with a linear system because each equation represents a straight line on a graph. The intersection of these lines, if it exists, would represent the solution to the system. Understanding the behaviors of these lines is crucial to determining the right method of solution and anticipating the type of solution set.
Algebraic Methods
Algebraic methods offer a structured way to solve systems of equations without relying on graphing. The most common algebraic methods include substitution, elimination, and the matrix method (also known as the row reduction method). Each method has its own best-use scenario, such as the substitution method being particularly effective for systems where one equation is easily expressed in terms of one variable.
The elimination method shines in situations like our original problem. By altering one or both equations to have a common coefficient for one variable, you can add or subtract the equations to eliminate that variable, thus breaking down the system to a simpler one-variable equation that can be easily solved.
The elimination method shines in situations like our original problem. By altering one or both equations to have a common coefficient for one variable, you can add or subtract the equations to eliminate that variable, thus breaking down the system to a simpler one-variable equation that can be easily solved.
Linear Algebra
Linear algebra is a branch of mathematics that deals with vectors, vector spaces, linear mappings, and systems of linear equations. It provides a powerful framework for handling multiple dimensions and is fundamental in various applications, including computer graphics, engineering, and physics.
In the context of our exercise, linear algebra principles facilitate insights into the behavior of systems of equations. The concept of linear independence, dimension, and basis are all relevant in understanding the solutions to linear systems. Additionally, advanced techniques from linear algebra such as matrix inversion or determinants can also be applied to find solutions in a more systematic and scalable way, especially for larger systems.
In the context of our exercise, linear algebra principles facilitate insights into the behavior of systems of equations. The concept of linear independence, dimension, and basis are all relevant in understanding the solutions to linear systems. Additionally, advanced techniques from linear algebra such as matrix inversion or determinants can also be applied to find solutions in a more systematic and scalable way, especially for larger systems.
Other exercises in this chapter
Problem 17
Graph the system of linear inequalities. $$ \begin{aligned} &x-3 y \geq 12\\\ &x-6 y
View solution Problem 17
Use the graphing method to tell how many solutions the system has. $$\begin{aligned} &x+y=8\\\ &x+y=-1 \end{aligned}$$
View solution Problem 17
Use linear combinations to solve the linear system. Then check your solution. \(2 g-3 h=0\) \(3 g-2 h=5\)
View solution Problem 18
Estimate the solution of the linear system graphically. Then check the solution algebraically. $$ \begin{array}{c} {y=2 x-4} \\ {2 y=-x} \end{array} $$
View solution