Problem 17
Question
calculate the area of the circle by the indicated method. The lengths of parallel chords of a circle that are 0.250 in. apart are given in the following table. The diameter of the circle is 2.000 in. The distance shown is the distance from one end of a diameter. $$\begin{array}{l|l|l|l|l|l|l|l} \text {Distance (in.) } & 0.000 & 0.250 & 0.500 & 0.750 & 1.000 & 1.250 & 1.500 & 1.750 & 2.000 \\ \hline \text {Length (in.) } & 0.000 & 1.323 & 1.732 & 1.936 & 2.000 & 1.936 & 1.732 & 1.323 & 0.000 \end{array}$$ Using the formula \(A=\pi r^{2},\) the area of the circle is 3.14 in. Find the area of the circle using the trapezoidal rule and only the values of distance of 0.000 in., 0.500 in. 1.000 in., 1.500 in., and 2.000 in. with the corresponding values of the chord lengths. Explain why the value found is less than 3.14 in. \(^{2}\)
Step-by-Step Solution
VerifiedKey Concepts
Trapezoidal Rule
The formula for the trapezoidal rule is: \[ A \approx \frac{d}{2} \left(L_0 + 2L_1 + 2L_2 + \ldots + 2L_{n-1}+ L_n\right) \]
- \(d\) is the distance between data points. In this example, it is 0.5 inches.
- \(L_i\) represents the lengths of the chords at these distances.
Circle Area Calculation
Thus, the area could be computed as:\[ A = \pi \times (1)^2 = \pi \approx 3.14\text{ in}^2 \].
- We use \(\pi\) in this formula as it accounts for the curved nature of the circle.
- Each unit, both radius and area, is represented in inches, which provides a consistent measurement basis.
Chord Lengths
We use these lengths at various points to estimate the circle's area indirectly.
Here are some important points about chord lengths in this context:
- Chords are parallel and equidistant, positioned 0.250 inches apart.
- They vary in length as they move across the circle, achieving the longest length at the circle's center.
- The symmetry of chord lengths relative to the circle’s center helps improve the accuracy of the trapezoidal approximation.
Integral Approximation
Here are a few key points:
- This approximation is essential for curves, like our circle, where traditional integration may be complex or infeasible directly.
- Methods like the trapezoidal rule provide a simpler way to estimate areas, though they can lead to underestimation if intervals are too wide or the curve is too complex.
- With a smooth curve, more data points distributed evenly will often yield a more accurate integral approximation.