Problem 17
Question
Answer each question. For which of the following cases is \(\sqrt{a b}=\sqrt{a} \cdot \sqrt{b}\) a true statement? A. \(a\) and \(b\) both positive B. \(a\) and \(b\) both negative
Step-by-Step Solution
Verified Answer
The equation is true for Case A: both \(a\) and \(b\) positive.
1Step 1: Understand square root properties
The equation \(\sqrt{a b} = \sqrt{a} \cdot \sqrt{b}\) is generally true when both \(a\) and \(b\) are non-negative. This is based on the property of square roots that allows the splitting of the square root of a product into the product of square roots.
2Step 2: Analyze Case A
In Case A, both \(a\) and \(b\) are positive. Since both numbers are non-negative, the equation \(\sqrt{a b} = \sqrt{a} \cdot \sqrt{b}\) holds true by the properties of square roots.
3Step 3: Analyze Case B
In Case B, both \(a\) and \(b\) are negative. The square root of a negative number is not defined in the real number system. Therefore, \(\sqrt{a} \) or \( \sqrt{b} \) do not exist in real numbers, making this scenario impossible to satisfy the equation in real numbers.
Key Concepts
Properties of Square RootsReal NumbersNegative Numbers
Properties of Square Roots
Square roots have a unique set of properties that define how they interact with numbers. One of the fundamental properties is that the square root of a product can be decomposed into the product of individual square roots. Mathematically, this is expressed as:
- **Positive Numbers**: When both numbers are positive, you can safely apply this property. For instance, \(\sqrt{3 \cdot 4} = \sqrt{3} \cdot \sqrt{4}\) holds true. - **Negative Numbers**: If either \(a\) or \(b\) is negative, or both, the property fails because the square root of a negative number isn't addressed in the realm of real numbers.
Understanding this allows you to simplify and solve square root expressions more effectively.
- \(\sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b}\)
- **Positive Numbers**: When both numbers are positive, you can safely apply this property. For instance, \(\sqrt{3 \cdot 4} = \sqrt{3} \cdot \sqrt{4}\) holds true. - **Negative Numbers**: If either \(a\) or \(b\) is negative, or both, the property fails because the square root of a negative number isn't addressed in the realm of real numbers.
Understanding this allows you to simplify and solve square root expressions more effectively.
Real Numbers
The real number system consists of a wide array of numbers including integers, fractions, and decimals, that can be positive, negative, or zero. Real numbers are what we use in everyday mathematics and when dealing with square roots in this domain, it is important to remember:
This fundamental distinction greatly influences how we calculate and understand square roots within real numbers.
- Square roots of non-negative numbers always result in real numbers.
- Negative numbers, within the scope of real numbers, do not have real square roots, as their square roots fall into the imaginary number category.
This fundamental distinction greatly influences how we calculate and understand square roots within real numbers.
Negative Numbers
Negative numbers are a vital part of the number system representing values less than zero. While you can perform many arithmetic operations such as addition and subtraction with them, square roots introduce a unique challenge.
Understanding this concept is fundamental when exploring more advanced mathematics or when dealing with equations where negative roots might arise. It explains why equations like \(\sqrt{a \cdot b} = \sqrt{a}\cdot\sqrt{b}\) do not hold true when involving negative numbers, making imaginary numbers a necessary consideration.
- The square root of a negative number isn't defined within the real numbers.
- Such numbers require the use of imaginary numbers to describe their square roots.
Understanding this concept is fundamental when exploring more advanced mathematics or when dealing with equations where negative roots might arise. It explains why equations like \(\sqrt{a \cdot b} = \sqrt{a}\cdot\sqrt{b}\) do not hold true when involving negative numbers, making imaginary numbers a necessary consideration.
Other exercises in this chapter
Problem 16
Write each rational expression in lowest terms. $$\frac{36 y^{2}+72 y}{9 y}$$
View solution Problem 16
Identify each expression as a polynomial or not a polynomial. For each polynomial, give the degree and identify it as a monomial, binomial, trinomial, or none o
View solution Problem 17
Simplify each expression. Assume that all variables represent positive real numbers. $$27^{-2 / 3}$$
View solution Problem 17
Factor each polynomial by grouping. $$t^{3}+2 t^{2}-3 t-6$$
View solution