Problem 17
Question
According to the 2010 census, the U.S. population was 309 million with an estimated growth rate of \(0.8 \% / \mathrm{yr}\). a. Based on these figures, find the doubling time and project the population in 2050 . b. Suppose the actual growth rate is just 0.2 percentage point lower than \(0.8 \% / \mathrm{yr}(0.6 \%) .\) What are the resulting doubling time and projected 2050 population? Repeat these calculations assuming the growth rate is 0.2 percentage point higher than \(0.8 \% / \mathrm{yr}\). c. Comment on the sensitivity of these projections to the growth rate.
Step-by-Step Solution
Verified Answer
Short Answer: At a growth rate of 0.8%, the doubling time is approximately 87.15 years, and the projected population in 2050 is 431.25 million. For a growth rate of 0.6%, the doubling time increases to around 115.53 years, and the projected population decreases to 400.47 million. On the other hand, for a growth rate of 1.0%, the doubling time decreases to about 69.66 years, and the projected population increases to 461.37 million. These changes in growth rate by 0.2% result in significant differences in doubling time and projected population, indicating that population projections and doubling time are sensitive to changes in the growth rate assumption.
1Step 1: Doubling Time Formula
The formula to find the doubling time is given by:
Doubling time (t) = \(\frac{ln(2)}{ln(1 + r)}\)
where 'r' is the growth rate (as a decimal).
2Step 2: Population Growth Formula
The formula to project population in the future is given by:
Future Population (P) = Initial Population (P₀) * \((1 + r)^{t}\)
P₀ = Initial Population
t = years passed
r = growth rate (as a decimal)
3Step 3: PART a: Doubling Time & Population Projection for 0.8% Growth Rate
Given data:
Initial Population (P₀) = 309 million
Growth Rate (r) = 0.8% = 0.008
Step 1: Calculate Doubling Time (t)
Doubling time (t) = \(\frac{ln(2)}{ln(1 + 0.008)}\) ≈ 87.15 years
Step 2: Project Population in 2050
Years passed (t) = 2050 - 2010 = 40 years
Future Population (P) = 309 * \((1 + 0.008)^{40}\) = 309 * 1.3953 = 431.25 million
4Step 4: PART b: Doubling Time & Population Projections for 0.6% and 1.0% Growth Rates
Case 1: Growth rate (r) = 0.6% = 0.006
Doubling time (t) = \(\frac{ln(2)}{ln(1 + 0.006)}\) ≈ 115.53 years
Future Population (P) = 309 * \((1 + 0.006)^{40}\) = 309 * 1.2955 = 400.47 million
Case 2: Growth rate (r) = 1.0% = 0.010
Doubling time (t) = \(\frac{ln(2)}{ln(1 + 0.010)}\) ≈ 69.66 years
Future Population (P) = 309 * \((1 + 0.010)^{40}\) = 309 * 1.4918 = 461.37 million
5Step 5: PART c: Comment on Sensitivity of Projections to Growth Rate
As the growth rate changes by 0.2%, the doubling time and projected population also change significantly. For a decrease of 0.2% in growth rate, doubling time increases by around 28.38 years, and the projected population decreases by 30.78 million people. Conversely, for an increase of 0.2% in the growth rate, doubling time decreases by about 17.49 years, and the projected population increases by 30.12 million people. This shows that population projections and doubling time are sensitive to changes in the growth rate assumption.
Key Concepts
Doubling TimePopulation ProjectionGrowth Rate Sensitivity
Doubling Time
In exponential growth, the concept of doubling time can be quite intriguing. This is the period it takes for a quantity to double in size or value. Often, it's associated with populations or investments. In mathematical terms, doubling time is determined by the formula:\[\text{Doubling time} = \frac{\ln(2)}{\ln(1 + r)}\]Here, \(r\) represents the growth rate expressed as a decimal. This formula reflects how quickly population or other metrics can escalate over time. For instance, at a growth rate of 0.8%, the U.S. population doubling time is approximately 87.15 years. Moreover, subtle alterations in the growth rate immensely impact doubling time. Lowering the rate to 0.6% lengthens the doubling time to approximately 115.53 years. Conversely, a 1.0% growth rate shortens it to about 69.66 years. Understanding these dynamics is crucial, especially for making accurate long-term projections.
Population Projection
Population projection is a mathematical estimation of future population sizes based on current data and assumed growth rates. Using the formula:\[P = P_0 \times (1 + r)^t\]where \(P_0\) is the initial population, \(r\) is the growth rate, and \(t\) is the number of years into the future we wish to project, one can estimate future population sizes.Taking the 2010 U.S. data as an example:
- Initial population \(P_0\) was 309 million.
- Estimated growth rate \(r\) was 0.8% or 0.008.
- For projections up to 2050, \(t\) is 40 years.
Growth Rate Sensitivity
The sensitivity of growth projections to changes in the growth rate is a pivotal aspect of population demographics. Small alterations in growth rates substantially influence doubling times and future population projections. Consider the U.S. population scenario:
- A mere 0.2% decrease in \(r\) from 0.8% to 0.6% extends the doubling time by almost 28.38 years.
- The estimated population in 2050 decreases by about 30.78 million people.
- An increase of 0.2% to 1.0% reduces the doubling time by around 17.49 years, increasing the projected population by roughly 30.12 million people.
Other exercises in this chapter
Problem 16
Let \(R\) be the region bounded by the following curves. Use the shell method to find the volume of the solid generated when \(R\) is revolved about the \(x\) -
View solution Problem 16
Sketch each region (if a figure is not given) and then find its total area. The regions between \(y=\sin x\) and \(y=\sin 2 x,\) for \(0 \leq x \leq \pi\)
View solution Problem 17
Consider an object moving along a line with the following velocities and initial positions. a. Graph the velocity function on the given interval and determine w
View solution Problem 17
Let \(R\) be the region bounded by the following curves. Use the shell method to find the volume of the solid generated when \(R\) is revolved about the \(x\) -
View solution