Problem 17
Question
a. Write each expression as a single logarithm. b. Find the value of each expression. \(\log _{3} 243-\log _{3} 729\)
Step-by-Step Solution
Verified Answer
\( \log_{3} 243 - \log_{3} 729 = -1 \).
1Step 1: Understanding the Expression
We have the expression \( \log_{3} 243 - \log_{3} 729 \). This is a difference of logarithms with the same base, allowing us to use properties of logarithms.
2Step 2: Applying Logarithm Properties
Use the property \( \log_{a} b - \log_{a} c = \log_{a} \left( \frac{b}{c} \right) \). This means we can rewrite \( \log_{3} 243 - \log_{3} 729 \) as a single logarithm: \( \log_{3} \left( \frac{243}{729} \right) \).
3Step 3: Simplifying the Fraction
Calculate \( \frac{243}{729} \). Both numbers divide exactly, as 243 is \( 3^5 \) and 729 is \( 3^6 \). Thus, \( \frac{3^5}{3^6} \) simplifies to \( 3^{-1} \), or \( \frac{1}{3} \).
4Step 4: Express as Single Logarithm
The expression simplifies further to \( \log_{3} \left( \frac{1}{3} \right) \), which according to the properties of logarithms, simplifies to \( -1 \) because it represents the exponent needed to raise 3 to get \( \frac{1}{3} \).
5Step 5: Calculating the Value
Thus, the value of the expression \( \log_{3} \left( \frac{1}{3} \right) \) is \(-1\).
Key Concepts
Properties of LogarithmsSimplification of ExpressionsLogarithmic Expressions
Properties of Logarithms
Logarithms have several useful properties that allow us to manipulate and simplify expressions. Understanding these properties makes it easier to solve problems involving logarithms. Let's break down some of the main properties:
- **Product Property**: \( \log_{a}(b \times c) = \log_{a}b + \log_{a}c \). This tells us that the logarithm of a product is the sum of the logarithms.
- **Quotient Property**: \( \log_{a} \left( \frac{b}{c} \right) = \log_{a}b - \log_{a}c \). We use this property when dealing with expressions where one logarithm is subtracted from another with the same base.
- **Power Property**: \( \log_{a}(b^c) = c \times \log_{a}b \). This property allows you to bring the exponent in front, turning multiplication into a simpler addition operation.
Simplification of Expressions
Simplification is about making expressions as basic as possible by using mathematical rules and properties. For logarithmic expressions, simplification frequently involves breaking down complex parts into singular forms. This process often uses prime factorization, as seen in the given problem.
In the exercise, we calculated \( \frac{243}{729} \) to simplify. Observing that 243 and 729 can be represented as powers of 3, specifically \(3^5\) and \(3^6\) respectively, allowed us to turn the fraction into \( \frac{3^5}{3^6} \). Then, we further simplified it by applying exponent subtraction, resulting in the simpler \(3^{-1} = \frac{1}{3} \).
Simplifying also helps us express a logarithm with a single term, making calculations direct and easier to interpret.
In the exercise, we calculated \( \frac{243}{729} \) to simplify. Observing that 243 and 729 can be represented as powers of 3, specifically \(3^5\) and \(3^6\) respectively, allowed us to turn the fraction into \( \frac{3^5}{3^6} \). Then, we further simplified it by applying exponent subtraction, resulting in the simpler \(3^{-1} = \frac{1}{3} \).
Simplifying also helps us express a logarithm with a single term, making calculations direct and easier to interpret.
Logarithmic Expressions
A logarithmic expression is an important tool in mathematics that represents exponents. In dealing with logs, it's crucial to recognize how these expressions convert complex multiplicative tasks into manageable additive terms or transform divisions into subtractions.
- **Base**: The small number acting as the foundation for the expression, determining the factor of multiplication.
- **Argument**: The number we are interested in getting through repeated multiplication using the base.
Other exercises in this chapter
Problem 17
In \(15-23,\) evaluate each logarithm to the nearest hundredth. $$ \log 0.002 $$
View solution Problem 17
In \(15-26,\) write each logarithmic equation in exponential form. $$ \log _{4} 16=2 $$
View solution Problem 17
In \(11-22,\) solve each equation for \(y\) in terms of \(x\) $$ x=12^{-y} $$
View solution Problem 18
In \(15-20,\) evaluate each logarithm to the nearest hundredth. $$ \ln 1,000^{2} $$
View solution