Problem 17
Question
A closed container contains equal number of oxygen and hydrogen molecules at a total pressure of \(740 \mathrm{~mm}\). If oxygen is removed from the system then pressure will (a) become double of \(740 \mathrm{~mm}\) (b) become half of \(740 \mathrm{~mm}\) (c) become \(1 / 9\) of \(740 \mathrm{~mm}\) (d) remain unchanged
Step-by-Step Solution
Verified Answer
Pressure becomes half of 740 mm, so the answer is (b).
1Step 1: Understand the Composition
The container initially contains equal numbers of oxygen and hydrogen molecules. Hence, the total pressure of 740 mm is due to the combined partial pressures of both gases.
2Step 2: Determine Initial Partial Pressures
Since there are equal numbers of oxygen and hydrogen molecules, they contribute equally to the total pressure. Thus, the partial pressure of the oxygen gas is half of the total: \( P_{O_2} = \frac{740}{2} = 370 \mathrm{~mm} \). Similarly, the partial pressure of hydrogen gas is \( P_{H_2} = 370 \mathrm{~mm} \).
3Step 3: Consider the Effect of Removing Oxygen
After removing oxygen from the container, only hydrogen remains to exert pressure. Hence, the new total pressure is solely the partial pressure of the hydrogen molecules.
4Step 4: Calculate New Pressure
Without the oxygen, the new total pressure in the container, exerted only by hydrogen, will be \( 370 \mathrm{~mm} \).
5Step 5: Determine the Correct Option
Given the remaining pressure of 370 mm, which is half of the original total pressure, the pressure will be half of \( 740 \mathrm{~mm} \). This aligns with option (b).
Key Concepts
Ideal Gas LawGas MixturesDalton's Law of Partial Pressures
Ideal Gas Law
The Ideal Gas Law is a fundamental concept in chemistry and physics that describes the behavior of gases under various conditions. This law is succinctly captured by the equation \( PV = nRT \), where:
However, it is important to note that this law assumes gases are ideal—the interactions between the gas molecules are negligible and the molecules occupy no volume.
In reality, gases deviate from ideal behavior at high pressures and low temperatures.
In the context of the exercise, understanding the Ideal Gas Law helps explain why the pressure changes when oxygen is removed from the container. The law indicates how pressure is directly proportional to the number of gas particles, assuming constant volume and temperature.
- \( P \) is the pressure of the gas,
- \( V \) is the volume it occupies,
- \( n \) is the number of moles of gas,
- \( R \) is the ideal gas constant,
- \( T \) is the temperature in Kelvin.
However, it is important to note that this law assumes gases are ideal—the interactions between the gas molecules are negligible and the molecules occupy no volume.
In reality, gases deviate from ideal behavior at high pressures and low temperatures.
In the context of the exercise, understanding the Ideal Gas Law helps explain why the pressure changes when oxygen is removed from the container. The law indicates how pressure is directly proportional to the number of gas particles, assuming constant volume and temperature.
Gas Mixtures
Gas mixtures consist of two or more gases that are not chemically combined. They can exist in any proportion and retain their individual properties.
This concept is vital in understanding the behavior of gases in a closed environment, like the container in our example with both oxygen and hydrogen.
When looking at gas mixtures, each type of gas in the mixture will exert its own pressure, known as its partial pressure, irrespective of the other gases present.
A gas mixture behaves according to the combined properties of each individual gas. This means each gas in a mixture will follow the Ideal Gas Law.
In our exercise, both oxygen and hydrogen have equal contributions to the overall pressure initially because the number of molecules for both gases is the same.
This equal contribution directly explains why, after the removal of one, the pressure exerted by the remaining gas is half of the total initial pressure.
This concept is vital in understanding the behavior of gases in a closed environment, like the container in our example with both oxygen and hydrogen.
When looking at gas mixtures, each type of gas in the mixture will exert its own pressure, known as its partial pressure, irrespective of the other gases present.
A gas mixture behaves according to the combined properties of each individual gas. This means each gas in a mixture will follow the Ideal Gas Law.
In our exercise, both oxygen and hydrogen have equal contributions to the overall pressure initially because the number of molecules for both gases is the same.
This equal contribution directly explains why, after the removal of one, the pressure exerted by the remaining gas is half of the total initial pressure.
Dalton's Law of Partial Pressures
Dalton's Law of Partial Pressures is a principle that is exceptionally useful when dealing with gas mixtures. This law states that the total pressure of a gas mixture is equal to the sum of the partial pressures of all the gases within it.
Mathematically, this is expressed as:
In our scenario, before oxygen is removed, the total pressure of the container is the sum of the pressures exerted by both the oxygen and hydrogen gases.
When Dalton's Law is applied, it predicts the pressure change when one gas is removed.
As illustrated in the exercise, once the oxygen is removed, Dalton's Law indicates that only the partial pressure of hydrogen remains.
Hence, the total pressure drops to half of the original, clearly showing the practical application of Dalton's Law.
Mathematically, this is expressed as:
- \( P_{total} = P_1 + P_2 + P_3 + \, ... \)
In our scenario, before oxygen is removed, the total pressure of the container is the sum of the pressures exerted by both the oxygen and hydrogen gases.
When Dalton's Law is applied, it predicts the pressure change when one gas is removed.
As illustrated in the exercise, once the oxygen is removed, Dalton's Law indicates that only the partial pressure of hydrogen remains.
Hence, the total pressure drops to half of the original, clearly showing the practical application of Dalton's Law.
Other exercises in this chapter
Problem 15
At what Centigrade temperature will be the volume of a gas at \(0^{\circ} \mathrm{C}\) double of itself, when pressure remains constant? (a) \(0^{\circ} \mathrm
View solution Problem 16
Pressure of a mixture of \(4 \mathrm{~g}\) of \(\mathrm{O}_{2}\) and \(2 \mathrm{~g}\) of \(\mathrm{H}_{2}\) confined in a bulb of \(1.0 \mathrm{~L}\) capacity
View solution Problem 19
What are the conditions under which the relation between volume (V) and number of moles (n) of gas is plotted? \((\mathrm{P}=\) pressure; \(\mathrm{T}=\) temper
View solution Problem 20
The rms velocity of \(\mathrm{CO}_{2}\) at a temperature \(\mathrm{T}\) (in Kelvin) is \(\times \mathrm{cm} \mathrm{sec}^{-1}\). At what temperature (in Kelvin)
View solution