Problem 17
Question
A circular ring of diameter \(20 \mathrm{~cm}\) has a resistance of \(0.01 \Omega\). The charge that will flow through the ring if it is turned from a position perpendicular to a uniform magnetic field of \(2.0 \mathrm{~T}\) to a position parallel to the field is about (a) \(63 \mathrm{C}\) (b) \(0.63 \mathrm{C}\) [c) \(6.3 \mathrm{C}\) (d) \(0.063 \mathrm{C}\)
Step-by-Step Solution
Verified Answer
The charge that will flow through the ring is approximately 6.3 C (option c).
1Step 1: Calculate the area of the ring
The area of a circle is given by the formula \( A = \pi r^2 \). Since the diameter of the ring is 20 cm, its radius \( r \) is \( \frac{20}{2} = 10 \) cm or \( 0.1 \) m. Thus, the area \( A \) is \( \pi \times (0.1)^2 = 0.01\pi \) square meters.
2Step 2: Calculate the magnetic flux initially and finally
The magnetic flux \( \Phi \) through an area \( A \) in a magnetic field \( B \) is given by \( \Phi = B \cdot A \cdot \cos \theta \). Initially, the ring is perpendicular to the field, \( \theta = 90^\circ \), so the initial flux \( \Phi_i = B \times A \times \cos 90^\circ = 0 \). Finally, the ring is parallel to the field, \( \theta = 0^\circ \), so the final flux \( \Phi_f = B \times A \times \cos 0^\circ = 2 \pi \times 0.01 = 0.02 \pi \).
3Step 3: Calculate the change in magnetic flux
The change in magnetic flux \( \Delta \Phi \) is the difference between the final and initial flux. Thus, \( \Delta \Phi = \Phi_f - \Phi_i = 0.02 \pi - 0 = 0.02 \pi \).
4Step 4: Use Faraday's law to find the induced EMF
According to Faraday's law, the induced electromotive force (EMF) \( \mathcal{E} \) is equal to the rate of change of magnetic flux, \( \mathcal{E} = - \frac{d\Phi}{dt} \). Since there are no time details provided, we consider the total change \( \mathcal{E} = \Delta \Phi \). So, \( \mathcal{E} = 0.02 \pi \).
5Step 5: Calculate the charge using Ohm's Law
Ohm's law relates the EMF to the current and resistance by \( \mathcal{E} = I \times R \). The charge \( q \) flowing is related by \( q = I \times t \), and since \( \mathcal{E} = q \times \frac{R}{t} \), we simplify it to \( q = \frac{\mathcal{E}}{R} \). Thus, substituting the EMF and resistance values, \( q = \frac{0.02 \pi}{0.01} = 2 \pi = 6.28 \).
6Step 6: Compare the answer with given options
The calculated charge \( q = 6.28 \) is approximately equal to the option (c) \( 6.3 \mathrm{C} \).
Key Concepts
Magnetic FluxFaraday's LawOhm's Law
Magnetic Flux
Magnetic flux is a crucial concept in electromagnetic induction. It represents the measure of the amount of magnetic field passing through a given area. Imagine a surface exposed to a magnetic field; the number of magnetic field lines passing through it constitutes the magnetic flux. Mathematically, magnetic flux \( \Phi \) is given by the formula \( \Phi = B \cdot A \cdot \cos \theta \), where:
- \( B \) is the magnetic field strength,
- \( A \) is the area of the surface,
- \( \theta \) is the angle between the field lines and the normal (perpendicular) to the surface.
Faraday's Law
Faraday's Law is a cornerstone of electromagnetic induction. It explains how changing magnetic flux induces an electromotive force (EMF) or voltage in a conductor. This law is especially crucial in understanding the behavior of electrical circuits exposed to varying magnetic fields. The law is mathematically expressed as \( \mathcal{E} = - \frac{d\Phi}{dt} \), where:
- \( \mathcal{E} \) is the induced EMF,
- \( \Phi \) is the magnetic flux,
- \( \frac{d\Phi}{dt} \) represents the rate of change of magnetic flux.
Ohm's Law
Ohm's Law is a simple yet vital law in understanding electrical circuits. It describes the relationship between voltage, current, and resistance. Expressed mathematically, Ohm's Law is \( V = I \cdot R \), where:
- \( V \) is the voltage or EMF in volts,
- \( I \) is the current in amperes,
- \( R \) is the resistance in ohms.
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