Problem 17
Question
\(15-20\) Identify the curve by finding a Cartesian equation for the curve. $$r=3 \sin \theta$$
Step-by-Step Solution
Verified Answer
The Cartesian equation is \( x^2 + y^2 - 3y = 0 \), representing a circle.
1Step 1: Understand the Polar Equation
The polar equation given is \( r = 3 \sin \theta \). This is a representation of a curve using polar coordinates, where \( r \) is the radius (distance from the origin) and \( \theta \) is the angle with the positive x-axis.
2Step 2: Recall Conversion Formulas
To convert a polar equation to a Cartesian equation, we use the relationships: \( x = r \cos \theta \) and \( y = r \sin \theta \). Also, note that \( r^2 = x^2 + y^2 \).
3Step 3: Express \( r \) in Terms of \( y \)
Since \( r = 3 \sin \theta \), we can multiply both sides by \( r \) to obtain: \( r^2 = 3r \sin \theta \). We can replace \( r \sin \theta \) with \( y \), giving \( r^2 = 3y \).
4Step 4: Substitute \( r^2 \) with \( x^2 + y^2 \)
Using the identity \( r^2 = x^2 + y^2 \), substitute into the equation from Step 3 to obtain: \( x^2 + y^2 = 3y \).
5Step 5: Rearrange and Simplify
Rearrange the equation \( x^2 + y^2 = 3y \) to \( x^2 + y^2 - 3y = 0 \). This is the Cartesian equation of the curve.
Key Concepts
Polar CoordinatesCoordinate ConversionCurve Identification
Polar Coordinates
In mathematics, polar coordinates offer a different method for describing points on a plane compared to the traditional Cartesian coordinate system. Instead of using an ordered pair \(x, y\), polar coordinates use \(r\) and \(\theta\). What makes it unique is how it emphasizes distance and direction:
- \(r\): This is the radius or the direct distance of the point from the origin.
- \(\theta\): This represents the angle formed with the positive x-axis. It's typically measured in radians, but degrees are also used at times.
Coordinate Conversion
Converting between polar and Cartesian coordinates may sound tricky initially, but it's based on some simple trigonometric relationships. The process involves linking the polar variables \(r\) and \(\theta\) with Cartesian variables \(x\) and \(y\), which define points on the Cartesian plane. Here's how the conversion works:
This seamless conversion allows us to express polar curves in Cartesian format, making it simpler to integrate them into functions or equations that require Cartesian coordinates.
- \(x = r \cos \theta\)
- \(y = r \sin \theta\)
- Using Pythagoras’s theorem, \(r^2 = x^2 + y^2\)
This seamless conversion allows us to express polar curves in Cartesian format, making it simpler to integrate them into functions or equations that require Cartesian coordinates.
Curve Identification
Identifying curves involves translating their polar representations into Cartesian equations, which can make them easier to recognize and classify. In the process of converting from polar to Cartesian form, we aim to rediscover curves familiar in algebraic studies.
For instance, with an equation like \(r = 3 \sin \theta\), by converting it, we found an equivalent Cartesian form: \(x^2 + y^2 = 3y\). Upon rearranging, \(x^2 + y^2 - 3y = 0\) emerges, which is a circle shifted along the y-axis.
This specific manipulation helps reveal the type of curve, in this case, a circle with a center at \(0, \frac{3}{2}\) and a radius of \(\frac{3}{2}\). Curve identification is crucial for revealing the geometric nature or the symmetry of the original shape, which might not be immediately apparent from its polar form. This step is essential, especially in calculus or engineering tasks, where interpreting the shape can influence how we approach problems involving the curve.
For instance, with an equation like \(r = 3 \sin \theta\), by converting it, we found an equivalent Cartesian form: \(x^2 + y^2 = 3y\). Upon rearranging, \(x^2 + y^2 - 3y = 0\) emerges, which is a circle shifted along the y-axis.
This specific manipulation helps reveal the type of curve, in this case, a circle with a center at \(0, \frac{3}{2}\) and a radius of \(\frac{3}{2}\). Curve identification is crucial for revealing the geometric nature or the symmetry of the original shape, which might not be immediately apparent from its polar form. This step is essential, especially in calculus or engineering tasks, where interpreting the shape can influence how we approach problems involving the curve.
Other exercises in this chapter
Problem 17
(a) Find the eccentricity and directrix of the conic \(r=1 /(1-2 \sin \theta)\) and graph the conic and its directrix. (b) If this conic is rotated counterclock
View solution Problem 17
Find the points on the curve where the tangent is horizontal or vertical. If you have a graphing device, graph the curve to check your work. $$x=10-t^{2}, \quad
View solution Problem 17
(a) Eliminate the parameter to find a Cartesian equation of the curve. (b) Sketch the curve and indicate with an arrow the direction in which the curve is trace
View solution Problem 18
Graph the conic \(r=4 /(5+6 \cos \theta)\) and its directrix. Also graph the conic obtained by rotating this curve about the origin through an angle \(\pi / 3\)
View solution