Problem 166
Question
Consider 5 independent Bernoulli's trials each with probability of failure \(1-p .\) If the probability of at least one failure is greater than or equal to \(\frac{31}{32}\), then \(p\) lies in the interval (A) \(\left(\frac{3}{4}, \frac{11}{12}\right)\) (B) \(\left[0, \frac{1}{2}\right]\)(C) \(\left[\frac{11}{12}, 1\right]\) (D) \(\left[\frac{1}{2}, \frac{3}{4}\right]\)
Step-by-Step Solution
Verified Answer
(B) \([0, \frac{1}{2}]\)
1Step 1: Identify Probability of Failure
Each Bernoulli trial has a probability of failure of \[ 1 - p. \]
2Step 2: Calculate Probability of At Least One Failure
The probability of having at least one failure in 5 trials is computed using the complement rule.\[ P(\text{at least one failure}) = 1 - P(\text{zero failures}). \]
3Step 3: Calculate Probability of Zero Failures
The probability of zero failures (all trials are successes) is\[ P(\text{zero failures}) = p^5. \]
4Step 4: Set Up Inequality for At Least One Failure
Given the probability of at least one failure is greater than or equal to \( \frac{31}{32} \), we write:\[ 1 - p^5 \geq \frac{31}{32}. \]
5Step 5: Solve the Inequality
Rearrange the inequality to solve for \( p^5 \):\[ p^5 \leq 1 - \frac{31}{32} = \frac{1}{32}. \]
6Step 6: Find the Range for p
To get the range for \( p \), we solve:\[ p \leq \left(\frac{1}{32}\right)^{1/5}. \]Calculating, we find: \[ \left(\frac{1}{32}\right)^{1/5} \approx 0.5. \] Thus, \( p \leq 0.5 \).
7Step 7: Determine the Correct Interval
The correct interval based on our answer that \( p \leq 0.5 \) is\[ \left[0, \frac{1}{2}\right]. \]Therefore, the correct option is (B).
Key Concepts
Bernoulli TrialsInequality SolvingComplement Rule
Bernoulli Trials
In probability theory, a Bernoulli trial is a random experiment that has exactly two possible outcomes: "success" and "failure." Each outcome is given a constant probability, which does not change between trials. Bernoulli trials are named after the Swiss mathematician Jacob Bernoulli, who studied permutations and combinations.
A Bernoulli trial can be imagined as flipping a coin where each flip (trial) results in either heads (success) or tails (failure). When dealing with a series of Bernoulli trials, each trial is independent of one another. This means the outcome of one trial does not influence the outcome of another.
A Bernoulli trial can be imagined as flipping a coin where each flip (trial) results in either heads (success) or tails (failure). When dealing with a series of Bernoulli trials, each trial is independent of one another. This means the outcome of one trial does not influence the outcome of another.
- In the context of our exercise, if each trial has a probability of failure of \( 1 - p \), then the probability of success in a single trial is \( p \).
- If we consider 5 such trials, we look at the total probability cloud of these trials collectively to find the solution.
Inequality Solving
In our exercise, inequality solving involves manipulating equations to find the range of possible values for a variable that satisfies a given condition. Here, we are trying to find the range of \( p \) using inequality solving techniques.
The problem asks for the probability that at least one failure occurs out of 5 independent Bernoulli trials to be greater than or equal to \( \frac{31}{32} \). The inequality is derived from the complement rule:
The problem asks for the probability that at least one failure occurs out of 5 independent Bernoulli trials to be greater than or equal to \( \frac{31}{32} \). The inequality is derived from the complement rule:
- First, find the probability of zero failures, which is \( p^5 \). This represents the situation where all trials are successful.
- Then, express the inequality for at least one failure: \( 1 - p^5 \geq \frac{31}{32} \). This relation indicates that the probability of obtaining at least one failed trial must be at least \( \frac{31}{32} \).
Complement Rule
The complement rule is a fundamental concept in probability theory. It helps in finding the probability of at least one event happening by calculating the probability of the complementary event not happening and subtracting it from 1.
In this exercise, the event of interest is "at least one failure." Its complement is "zero failures," meaning all trials are successful. This is represented as \( p^5 \) in mathematical terms.
The complement rule is then applied:
In this exercise, the event of interest is "at least one failure." Its complement is "zero failures," meaning all trials are successful. This is represented as \( p^5 \) in mathematical terms.
The complement rule is then applied:
- The probability of zero failures is calculated first: \( p^5 \).
- Then, the probability of at least one failure is \( 1 - p^5 \).
Other exercises in this chapter
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