Problem 165
Question
A sample of \(11.4 \mathrm{L}\) of an ideal gas at \(25.0^{\circ} \mathrm{C}\) and 735 torr is compressed and heated so that the volume is \(7.9 \mathrm{L}\) and the temperature is \(72.0^{\circ} \mathrm{C} .\) What is the pressure in the container?
Step-by-Step Solution
Verified Answer
Answer: The final pressure in the container is 1.45 atm.
1Step 1: Convert the given temperatures to Kelvin
To work with the Ideal Gas Law, we need to convert the given temperatures from Celsius to Kelvin. The conversion is done using the following relation: T(K) = T(°C) + 273.15
Initial temperature, T1 = 25.0°C + 273.15 = 298.15 K
Final temperature, T2 = 72.0°C + 273.15 = 345.15 K
2Step 2: Convert the given pressure from torr to atm
We also need to convert the given pressure from torr to atm for consistency with the Ideal Gas Law formula. The conversion factor is 1 atm = 760 torr.
Initial pressure, P1 = 735 torr * (1 atm / 760 torr) = 0.967 atm
3Step 3: Use the combined gas law equation to find the final pressure
Now, we can plug in the values into the combined gas law equation: P1V1/T1 = P2V2/T2
0.967 atm * 11.4 L / 298.15 K = P2 * 7.9 L / 345.15 K
Now, we just need to solve for P2 (final pressure).
P2 = 0.967 atm * 11.4 L / 298.15 K * 345.15 K / 7.9 L
P2 = 1.45 atm
The final pressure in the container is 1.45 atm.
Key Concepts
Combined Gas Law EquationGas Pressure ConversionKelvin Temperature ScaleGas Volume and Temperature Relationship
Combined Gas Law Equation
The combined gas law is a fundamental equation that blends the three gas laws: Boyle's Law, Charles's Law, and Gay-Lussac's Law. It is useful when dealing with scenarios where pressure, volume, and temperature of a gas are changing simultaneously.
The combined gas law can be represented as:
\[ \frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} \]
where:
The combined gas law can be represented as:
\[ \frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} \]
where:
- \(P_1\) and \(P_2\) are the initial and final pressures,
- \(V_1\) and \(V_2\) are the initial and final volumes, and
- \(T_1\) and \(T_2\) are the initial and final temperatures in Kelvin.
Gas Pressure Conversion
When working with gasses, pressure can be measured in multiple units such as atmospheres (atm), torr, or Pascals (Pa). The Ideal Gas Law requires a consistent set of units, typically atmospheres for pressure.
Conversion between units is straightforward but essential for accurate calculations. The conversion factor between torr and atmosphere is that 1 atm equals 760 torr.To convert from torr to atm, you would divide the pressure in torr by 760. Similarly, to convert from atm to torr, you multiply by 760.
Mathematically, the conversion formulas are:
Conversion between units is straightforward but essential for accurate calculations. The conversion factor between torr and atmosphere is that 1 atm equals 760 torr.To convert from torr to atm, you would divide the pressure in torr by 760. Similarly, to convert from atm to torr, you multiply by 760.
Mathematically, the conversion formulas are:
- \( P(atm) = \frac{P(torr)}{760} \)
- \( P(torr) = P(atm) \times 760 \)
Kelvin Temperature Scale
The Kelvin temperature scale is an absolute temperature scale, utilizing the same increment size as the Celsius scale, but with its zero point at absolute zero, the theoretical lowest temperature possible. Absolute zero equates to -273.15°C.
For gas law calculations, temperatures must be converted to the Kelvin scale because gas volumes are directly proportional to temperature in Kelvins and pressures are due to particle collisions, which increase with temperature. The Kelvin scale ensures that these relationships remain linear and proportional.
To convert from Celsius to Kelvin, the formula is:
For gas law calculations, temperatures must be converted to the Kelvin scale because gas volumes are directly proportional to temperature in Kelvins and pressures are due to particle collisions, which increase with temperature. The Kelvin scale ensures that these relationships remain linear and proportional.
To convert from Celsius to Kelvin, the formula is:
- \(T(K) = T(°C) + 273.15\)
Gas Volume and Temperature Relationship
The relationship between gas volume and temperature is described by Charles's Law, which states that, at a constant pressure, the volume of a gas is directly proportional to its temperature in Kelvins. This means that if the temperature increases, the volume of the gas increases as well, if pressure remains unchanged.
The mathematical representation of Charles's Law is:
Understanding this relationship is crucial in various scientific fields, such as meteorology and aeronautics, and is foundational in gas law problems. It’s a concept that is not only theoretically important but also practically observable in everyday life.
The mathematical representation of Charles's Law is:
- \( \frac{V_1}{T_1} = \frac{V_2}{T_2} \)
Understanding this relationship is crucial in various scientific fields, such as meteorology and aeronautics, and is foundational in gas law problems. It’s a concept that is not only theoretically important but also practically observable in everyday life.
Other exercises in this chapter
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A sample of argon gas at STP occupies \(15.0 \mathrm{L} .\) What mass of argon is present in the container?
View solution Problem 167
A sample of a gas has a mass of \(2.889 \mathrm{g}\) and a volume of \(940 \mathrm{mL}\) at 735 torr and \(31^{\circ} \mathrm{C} .\) What is its molar mass?
View solution