Problem 163
Question
If a quadratic equation has imaginary solutions, how is this shown on the graph of \(y=a x^{2}+b x+c ?\)
Step-by-Step Solution
Verified Answer
The graph of a quadratic equation with imaginary solutions does not intersect the x-axis.
1Step 1: Understand Imaginary Solutions
Firstly, it's important to understand what imaginary solutions mean in a quadratic equation. Imaginary solutions occur when the discriminant \(b^{2}-4ac\) in the quadratic formula \(-\frac{b\pm \sqrt{b^{2}-4ac}}{2a}\) is negative, meaning there are no real solutions.
2Step 2: Relation to Graph
On the graph of a quadratic equation, solutions are represented as points where the graph intersects with the x-axis. If the quadratic equation generates real solutions, the graph will intersect the x-axis at the points representing these solutions. However, having no real solutions (i.e., having imaginary solutions) effectively means that the graph of the quadratic equation does not intersect the x-axis at all.
3Step 3: Conclusion
Hence, when a quadratic equation has imaginary solutions, it is graphically represented by the parabola not intersecting the x-axis at all.
Other exercises in this chapter
Problem 161
If you are given a quadratic equation, how do you determine which method to use to solve it?
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Describe the relationship between the real solutions of \(a x^{2}+b x+c=0\) and the graph of \(y=a x^{2}+b x+c\)
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Determine whether each statement makes sense or does not make sense, and explain your reasoning. Because I want to solve \(25 x^{2}-169=0\) fairly quickly, I'll
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Determine whether each statement makes sense or does not make sense, and explain your reasoning. I obtained \(-17\) for the discriminant, so there are two imagi
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