Problem 163
Question
Identify the correct statements. (a) \(\mathrm{C}_{2} \mathrm{H}_{5}-\mathrm{O}-\mathrm{CH}_{3}\) on cleavage with \(\mathrm{PCl}_{5}\) gives equimolar mixture of ethyl chloride and methyl chloride (b) \(\mathrm{ClCH}_{2} \mathrm{CH}=\mathrm{CH}_{2}\) is more reactive than \(\mathrm{Br} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}\) to prepare ether using Williamson's synthesis (c) Anisole can be prepared by the reaction of \(\mathrm{CH}_{3} \mathrm{ONa}\) on chlorobenzene (d) Sodium metal can be used to dry diethyl ether, benzene and ethyl alcohol.
Step-by-Step Solution
Verified Answer
Statements (a) and (b) are correct.
1Step 1: Analyzing Statement (a)
The compound \( \mathrm{C}_{2} \mathrm{H}_{5}-\mathrm{O}-\mathrm{CH}_{3} \) is ethyl methyl ether. Upon reaction with \( \mathrm{PCl}_{5} \), it cleaves to form different products. The cleavage results in the formation of ethyl chloride (\( \mathrm{C}_{2} \mathrm{H}_{5}\mathrm{Cl} \)) and methyl chloride (\( \mathrm{CH}_{3}\mathrm{Cl} \)). Therefore, statement (a) is correct as both chlorides are formed in equimolar amounts.
2Step 2: Analyzing Statement (b)
To determine the reactivity for ether preparation, in Williamson's synthesis, the order of reactivity is typically allyl halides > benzyl halides > primary alkyl halides. Here \((\mathrm{ClCH}_{2} \mathrm{CH}=\mathrm{CH}_{2})\), an allylic halide, is more reactive than \(\mathrm{Br} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}\), a primary alkyl halide. Therefore, statement (b) is correct.
3Step 3: Analyzing Statement (c)
Anisole (methoxybenzene) cannot be prepared by the reaction of \( \mathrm{CH}_{3} \mathrm{ONa} \) on chlorobenzene due to the lack of reactivity of chlorobenzene with nucleophiles. Chlorobenzene's ring is stable and resistant to nucleophilic substitution, so statement (c) is incorrect.
4Step 4: Analyzing Statement (d)
Sodium metal can indeed be used to dry diethyl ether and benzene due to their lack of reactivity with sodium. However, sodium cannot be used to dry ethyl alcohol because it reacts vigorously with alcohols, forming hydrogen gas and alkoxides. Therefore, statement (d) is incorrect.
Key Concepts
Ether CleavageReactivity in Williamson's SynthesisNucleophilic Substitution ResistanceDrying Solvents with Sodium Metal
Ether Cleavage
Ether cleavage is a core concept in organic chemistry, focusing on the breaking of an ether bond to form smaller molecules. In the case of ethyl methyl ether, the reaction with phosphorus pentachloride (\( \mathrm{PCl}_{5} \)) leads to cleavage.
- Cleavage occurs between the oxygen and one of the carbon atoms, resulting in different alkyl halides depending on the ether involved.
- For ethyl methyl ether (\( \mathrm{C}_{2} \mathrm{H}_{5}-\mathrm{O}-\mathrm{CH}_{3} \)), cleavage results in equimolar amounts of ethyl chloride (\( \mathrm{C}_{2} \mathrm{H}_{5}\mathrm{Cl} \)) and methyl chloride (\( \mathrm{CH}_{3}\mathrm{Cl} \)).
Reactivity in Williamson's Synthesis
Williamson's synthesis is a method used to prepare ethers from alcohols and alkyl halides. The reactivity of different halides in this synthesis varies significantly.
- Allylic halides, like \( \mathrm{ClCH}_{2} \mathrm{CH}=\mathrm{CH}_{2} \), are more reactive and lead to successful ether formation.
- In contrast, primary alkyl halides like \( \mathrm{Br} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3} \) tend to be less reactive and might not be suitable for the synthesis.
- The success of Williamson's synthesis relies on the nucleophilic substitution reaction, where a nucleophile replaces a leaving group in an alkyl halide.
Nucleophilic Substitution Resistance
Nucleophilic substitution is an essential reaction in organic chemistry. However, not all compounds readily undergo this type of reaction.
- Ring systems like chlorobenzene display resistance towards nucleophilic substitution due to resonance stability and the strengthening of the carbon-halide bond.
- This stability makes chlorobenzene a poor candidate for reactions requiring nucleophilic attack, such as the attempted preparation of anisole using \( \mathrm{CH}_{3} \mathrm{ONa} \).
Drying Solvents with Sodium Metal
Sodium metal is commonly used to dry certain solvents by removing traces of water. However, the suitability of sodium varies among different solvents.
- Non-reactive solvents like diethyl ether and benzene can safely be dried with sodium as they do not react significantly with sodium metal.
- In contrast, alcohols like ethyl alcohol react vigorously with sodium, producing hydrogen gas, making sodium unsuitable for drying alcohols.
Other exercises in this chapter
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