Problem 162
Question
The value of 'spin only' magnetic moment for one of the following configurations is \(2.84 \mathrm{BM}\). The correct one is \([\mathbf{2 0 0 5}]\) (a) \(\mathrm{d}^{4}\) (in strong ligand field) (b) \(\mathrm{d}^{4}\) (in weak ligand field) (c) \(\mathrm{d}^{3}\) (in weak as well as in strong fields) (d) \(\mathrm{d}^{5}\) (in strong ligand field)
Step-by-Step Solution
Verified Answer
The correct configuration is \( \mathrm{d}^{4} \) in a strong ligand field (option a).
1Step 1: Understand Spin Only Magnetic Moment
The spin-only magnetic moment (_{ ext{spin}}) is given by the formula, \( \mu_S = \sqrt{n(n + 2)} \), where \( n \) is the number of unpaired electrons. We are looking for a configuration with a magnetic moment of \(2.84 \mathrm{BM}\).
2Step 2: Calculate Spin Only Magnetic Moment for Each Option
- For option (a) \( \mathrm{d}^{4} \) strong field: A strong ligand field pairs electrons, resulting in 2 unpaired electrons. \( \mu_S = \sqrt{2(2 + 2)} = \sqrt{8} = 2.83 \mathrm{BM}\).- For option (b) \( \mathrm{d}^{4} \) weak field: Weak field typically results in 4 unpaired electrons. \( \mu_S = \sqrt{4(4 + 2)} = \sqrt{24} = 4.90 \mathrm{BM}\).- For option (c) \( \mathrm{d}^{3} \): Both strong and weak fields lead to 3 unpaired electrons. \( \mu_S = \sqrt{3(3 + 2)} = \sqrt{15} = 3.87 \mathrm{BM}\).- For option (d) \( \mathrm{d}^{5} \) strong field: A strong field pairs electrons, resulting in 1 unpaired electron. \( \mu_S = \sqrt{1(1 + 2)} = \sqrt{3} = 1.73 \mathrm{BM}\).
3Step 3: Compare With Given Magnetic Moment
Match the calculated magnetic moments with the given value of \(2.84 \mathrm{BM}\). The magnetic moment closest to this value is from option (a), which is approximately \(2.83 \mathrm{BM}\).
4Step 4: Determine the Correct Configuration
Since option (a) \( \mathrm{d}^{4} \) in a strong ligand field yields a magnetic moment closely matching \(2.84 \mathrm{BM}\), this is the correct answer.
Key Concepts
Unpaired ElectronsLigand Field Theoryd-Orbital Configuration
Unpaired Electrons
When considering the spin-only magnetic moment, the key idea is the number of unpaired electrons present in the configuration of a compound. Unpaired electrons are those electrons in an atomic or molecular configuration that do not have a corresponding electron with an opposite spin in the same orbital. These unpaired electrons contribute significantly to the magnetic properties of an atom or molecule.
A basic understanding of these concepts is essential because:
A basic understanding of these concepts is essential because:
- Unpaired electrons generate a magnetic moment due to their spin, resulting in paramagnetism.
- Paired electrons tend to cancel each other’s magnetic effects out, leading to diamagnetism.
Ligand Field Theory
Ligand field theory (LFT) is an important concept used to describe the effect of ligands on the distribution of electrons in transition metal complexes. It provides a more accurate depiction of the energy differences among d-orbitals and helps predict the properties of complexes.
Ligand field varies in strength:
Ligand field varies in strength:
- Strong Field Ligands: They exert a strong effect on the metal d-orbitals, often leading to pairing of electrons, reducing the number of unpaired electrons. This drastically affects the magnetic properties.
- Weak Field Ligands: They produce a relatively weak effect, often retaining more unpaired electrons, which increases magnetic moments.
d-Orbital Configuration
The d-orbital configuration refers to how electrons are distributed in the five d-orbitals of a transition metal. This configuration significantly influences the magnetic and other chemical properties of the substance.
When transition metals form complexes, their d-orbital configurations can be modified substantially by the presence of ligands. Depending on the field strength of these ligands:
When transition metals form complexes, their d-orbital configurations can be modified substantially by the presence of ligands. Depending on the field strength of these ligands:
- In a strong ligand field, electrons may be forced to pair up in lower-energy orbitals due to energy splitting, reducing the number of unpaired electrons.
- Conversely, in a weak ligand field, electrons typically remain unpaired to avoid pairing energy costs, resulting in a higher count of unpaired electrons and a larger magnetic moment.
Other exercises in this chapter
Problem 160
Which of the following compounds shows optical isomerism? (a) \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}\) (b) \(\left[\mathrm{ZnCl}_{4}\ri
View solution Problem 161
Which one of the following cyano complexes would exhibit the lowest value of paramagnetic behaviour? (a) \(\left[\mathrm{Cr}(\mathrm{CN})_{6}\right]^{3-}\) (b)
View solution Problem 163
The IUPAC name for the complex \(\left[\mathrm{Co}\left(\mathrm{NO}_{2}\right)\left(\mathrm{NH}_{3}\right)_{5}\right]\) \(\mathrm{Cl}_{2}\) is [2006] (a) nitrit
View solution Problem 164
Nickel \((\mathrm{Z}=28)\) combines with a uninegative monodentate ligand \(\mathrm{X}^{-}\)to form a paramagnetic complex \(\left[\mathrm{Ni} \mathrm{X}_{4}\ri
View solution