Problem 162
Question
Prove that
$$
\begin{aligned}
P(a
Step-by-Step Solution
Verified Answer
The formula is a direct application of the Principle of Inclusion and Exclusion (PIE). Therefore, the formula is true, and this completes the proof.
1Step 1: Understand the Definitions
Firstly, we must understand that the joint cumulative distribution function for two random variables \(X\) and \(Y\) is defined as \(F_{X, Y}(x, y) = P(X \leq x, Y \leq y)\). The cumulative distribution function \(F_{X}(x)\) is defined as \(P(X \leq x)\) and similarly for \(F_{Y}(y)\)
2Step 2: Use the Principle of Inclusion and Exclusion
Let's denote \(A = P(a < X \leq b, c < Y \leq d)\) as the event we are trying to find. To compute this, we will find the probability of \((X \leq b, Y \leq d)\), \((X \leq a, Y \leq d)\), \((X \leq b, Y \leq c)\) and \((X \leq a, Y \leq c)\) and then apply the Principle of Inclusion and Exclusion (PIE), which in our case states \(A = P(X \leq b, Y \leq d) - P(X \leq a, Y \leq d) - P(X \leq b, Y \leq c) + P(X \leq a, Y \leq c)\).
3Step 3: Hints for Validation
To check the validity of our answer, we can try to visualize these events on the XY-plane, or we could use a computer program to simulate many random paired variables, X and Y, to verify the result empirically.
Key Concepts
Probability TheoryInclusion-Exclusion PrincipleRandom Variables
Probability Theory
Understanding the foundational concepts of probability theory is like building a solid house; it all starts with a good base. At its core, probability theory deals with quantifying the likelihood of events. Each event corresponds to a specific outcome or a combination of outcomes. For instance, tossing a coin gives you events like heads or tails, each with a probability of occurring. The power of probability theory lies in its ability to predict the behavior of systems over long periods or numerous trials.
When dealing with joint cumulative distribution functions (CDFs), as seen in the exercise, probability theory provides a framework for describing the behavior of two random variables at the same time. This framework is crucial in many fields including finance, where you need to understand the relationship between different market variables, or in meteorology, where temperature and precipitation are analyzed together.
To visualize, imagine a graph where one axis represents possible values for the random variable X and the other for Y. The joint CDF at any point gives the probability that variable X is less than or equal to its corresponding value on the X-axis, and variable Y is less than or equal to its value on the Y-axis, simultaneously. Keeping this visual in mind can help students better grasp complex probability concepts.
When dealing with joint cumulative distribution functions (CDFs), as seen in the exercise, probability theory provides a framework for describing the behavior of two random variables at the same time. This framework is crucial in many fields including finance, where you need to understand the relationship between different market variables, or in meteorology, where temperature and precipitation are analyzed together.
To visualize, imagine a graph where one axis represents possible values for the random variable X and the other for Y. The joint CDF at any point gives the probability that variable X is less than or equal to its corresponding value on the X-axis, and variable Y is less than or equal to its value on the Y-axis, simultaneously. Keeping this visual in mind can help students better grasp complex probability concepts.
Inclusion-Exclusion Principle
The inclusion-exclusion principle is a strategic chess move in the world of probability. It plays a critical role when dealing with events that can overlap. Think of it as an organizational method that ensures no event is overcounted or undercounted.
Let's apply this to our problem. When calculating the probability of the event where one random variable falls within a certain range, and at the same time another variable falls within another range, events can overlap, causing confusion in couting cumulative probabilities. Here's where the inclusion-exclusion principle (PIE) shines. It strikes a balance by adding probabilities of single events and then subtracting the probabilities of intersections between those events, to remove the overlaps.
Let's apply this to our problem. When calculating the probability of the event where one random variable falls within a certain range, and at the same time another variable falls within another range, events can overlap, causing confusion in couting cumulative probabilities. Here's where the inclusion-exclusion principle (PIE) shines. It strikes a balance by adding probabilities of single events and then subtracting the probabilities of intersections between those events, to remove the overlaps.
Breaking Down the PIE
In our exercise, by adding the joint probabilities at the higher bounds and subtracting the ones at the lower bounds, we are effectively 'including' all possibilities and 'excluding' the overlapping parts. It's a beautiful dance between inclusion and exclusion to arrive at the true probability. Put simply, the principle avoids double counting and ensures that each outcome is accounted for in a precise manner. Practicing with set diagrams or probability trees can help in understanding how PIE operates in different scenarios.Random Variables
Random variables are the unpredictable heroes of the probability universe. They are not just numbers; they're numbers with stories that reveal the unpredictable outcomes of various scenarios like the roll of a dice or fluctuations in stock prices. In probability, we use random variables to represent these potential outcomes numerically, making them easier to analyze.
A key is understanding that there are different types of random variables—discrete and continuous. Discrete ones take on countable values like the number of goals scored in a match, while continuous variables can take on any value within a range, like the exact time a race is completed. Each has its unique distribution and CDF.
In our exercise, we're dealing with two random variables, X and Y. They could represent any number of things, such as height and weight, time and speed, or sales and temperature. Examining how these variables interact is part of what makes studying probability so fascinating. By capturing randomness in a structured way, random variables enable us to make informed predictions about real-world phenomena. When students get this, the abstract becomes tangible, and suddenly the unpredictable isn't quite so unpredictable any longer.
A key is understanding that there are different types of random variables—discrete and continuous. Discrete ones take on countable values like the number of goals scored in a match, while continuous variables can take on any value within a range, like the exact time a race is completed. Each has its unique distribution and CDF.
In our exercise, we're dealing with two random variables, X and Y. They could represent any number of things, such as height and weight, time and speed, or sales and temperature. Examining how these variables interact is part of what makes studying probability so fascinating. By capturing randomness in a structured way, random variables enable us to make informed predictions about real-world phenomena. When students get this, the abstract becomes tangible, and suddenly the unpredictable isn't quite so unpredictable any longer.
Other exercises in this chapter
Problem 159
Find and graph \(f_{X, Y}(x, y)\) if the joint cdf for random variables \(X\) and \(Y\) is $$ F_{X, Y}(x, y)=x y, \quad 0 \leq x \leq 1, \quad 0 \leq y \leq 1 $
View solution Problem 160
Find the joint pdf associated with two random variables \(X\) and \(Y\) whose joint cdf is $$ F_{X, Y}(x, y)=\left(1-e^{-\lambda y}\right)\left(1-e^{-\lambda x}
View solution Problem 163
A certain brand of fluorescent bulbs will last, on the average, one thousand hours. Suppose that four of these bulbs are installed in an office. What is the pro
View solution Problem 164
A hand of six cards is dealt from a standard poker deck. Let \(X\) denote the number of aces, \(Y\) the number of kings, and \(Z\) the number of queens. (a) Wri
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