Problem 161
Question
Which one of the following cyano complexes would exhibit the lowest value of paramagnetic behaviour? (a) \(\left[\mathrm{Cr}(\mathrm{CN})_{6}\right]^{3-}\) (b) \(\left[\mathrm{Mn}(\mathrm{CN})_{6}\right]^{3-}\) (c) \([\mathrm{Fe}(\mathrm{CN})]^{3-}\) (d) \(\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}\)
Step-by-Step Solution
Verified Answer
[Co(CN)_6]^{3-} exhibits the lowest paramagnetic behavior as it has zero unpaired electrons.
1Step 1: Understanding Paramagnetism
Paramagnetic behavior arises from unpaired electrons in the d orbitals of transition metals. The fewer the unpaired electrons, the lower the paramagnetic behavior. Hence, to identify which complex has the lowest paramagnetic behavior, we must find which has the fewest unpaired electrons.
2Step 2: Determining Electron Configuration
For each metal complex, determine the oxidation state of the metal and its electron configuration. Consider that CN- is a strong field ligand, which often causes pairing of electrons in the d orbitals due to a large crystal field splitting energy.
3Step 3: Evaluating [Cr(CN)6]^{3-}
In \([Cr(CN)6]^{3-}\), the oxidation state of Cr is +3. Cr^{3+} has an electron configuration of \[\text{3d}^3\text{4s}^0\text{4p}^0\] . With the 3 strong field CN^- ligands, all 3 electrons remain unpaired.
4Step 4: Evaluating [Mn(CN)6]^{3-}
For \([Mn(CN)6]^{3-}\), Mn is in the oxidation state of +3. Mn^{3+} has a configuration of \[\text{3d}^4\text{4s}^0\text{4p}^0\] . With strong field CN^-, these electrons fill to have 2 unpaired electrons.
5Step 5: Evaluating [Fe(CN)6]^{3-}
In \([Fe(CN)6]^{3-}\), Fe is +3. Fe^{3+} has \[\text{3d}^5\text{4s}^0\text{4p}^0\] . With strong field CN^- ligands, all electrons pair up resulting in 1 unpaired electron.
6Step 6: Evaluating [Co(CN)6]^{3-}
\([Co(CN)6]^{3-}\), Co is +3. Co^{3+} has \[\text{3d}^6\text{4s}^0\text{4p}^0\] . Due to strong field CN^- ligands, all electrons are paired, resulting in zero unpaired electrons.
7Step 7: Conclusion: Determining Lowest Paramagnetism
Among the complexes, [Co(CN)6]^{3-} has zero unpaired electrons, resulting in the lowest paramagnetic behavior.
Key Concepts
Crystal Field TheoryElectron Configuration in Coordination CompoundsTransition Metal Complexes
Crystal Field Theory
Crystal Field Theory (CFT) is a crucial model that helps us understand the behavior of transition metal complexes. It mainly focuses on the interaction between the central metal ion and the ligands surrounding it. When ligands approach a metal ion, they create an electric field that affects the metal's d orbitals. These orbitals, which usually have the same energy, split into different energy levels due to this interaction. The degree of splitting depends on various factors but is most significantly influenced by the strength of the ligands.
Ligands are classified as either strong or weak field, based on their ability to cause the splitting of metal d orbitals. Strong field ligands like cyanide (\(\text{CN}^-\)) lead to a large gap in energy, often resulting in paired electrons within these orbitals. This leads to lower paramagnetic behavior because fewer or no unpaired electrons remain. In the context of transition metal complexes:
Ligands are classified as either strong or weak field, based on their ability to cause the splitting of metal d orbitals. Strong field ligands like cyanide (\(\text{CN}^-\)) lead to a large gap in energy, often resulting in paired electrons within these orbitals. This leads to lower paramagnetic behavior because fewer or no unpaired electrons remain. In the context of transition metal complexes:
- Strong field ligands can force electrons to pair up, reducing the number of unpaired ones.
- Weak field ligands lead to less pairing, leaving more unpaired electrons.
Electron Configuration in Coordination Compounds
The electron configuration of transition metals in coordination compounds plays a vital role in determining their magnetic properties. Transition metal ions typically contain unfilled d orbitals, and their electron arrangements can vary based on ligand interaction.
When considering coordination compounds, it is essential to determine the oxidation state of the metal ion to establish the correct electron configuration. For instance:
When considering coordination compounds, it is essential to determine the oxidation state of the metal ion to establish the correct electron configuration. For instance:
- Chromium in \([Cr(CN)_6]^{3-}\) has an oxidation state of +3, leading to an electron configuration of \([Ar] 3d^3\).
- Manganese in \([Mn(CN)_6]^{3-}\) is also +3, resulting in \([Ar] 3d^4\).
- Similarly, iron and cobalt in their respective complexes are in the +3 oxidation state, with configurations \([Ar] 3d^5\) for iron and \([Ar] 3d^6\) for cobalt.
Transition Metal Complexes
Transition metal complexes are fascinating chemical entities comprising a central metal atom or ion surrounded by molecules or ions, known as ligands. These complexes exhibit a range of interesting properties due to the unique behavior of transition metals, principally their variable oxidation states and ability to form colored compounds.
The property of paramagnetism in transition metal complexes arises from unpaired electrons in the metal's d orbitals. The number of unpaired electrons is influenced by the ligand field strength. Cyanide (\(\text{CN}^-\)) is notable for being a strong field ligand in these contexts, which usually results in fewer unpaired electrons:
The property of paramagnetism in transition metal complexes arises from unpaired electrons in the metal's d orbitals. The number of unpaired electrons is influenced by the ligand field strength. Cyanide (\(\text{CN}^-\)) is notable for being a strong field ligand in these contexts, which usually results in fewer unpaired electrons:
- In the discussed complexes, cobalt forms \([Co(CN)_6]^{3-}\) with no unpaired electrons, hence exhibiting the least paramagnetism.
- Other metals like chromium, manganese, and iron in similar complexes retain more unpaired electrons, contributing to their paramagnetic behavior.
Other exercises in this chapter
Problem 159
The IUPAC name of the coordination compound \(\mathrm{K}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\) is (a) potassium hexacyanoferrate (II) (b) potassium hex
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Which of the following compounds shows optical isomerism? (a) \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}\) (b) \(\left[\mathrm{ZnCl}_{4}\ri
View solution Problem 162
The value of 'spin only' magnetic moment for one of the following configurations is \(2.84 \mathrm{BM}\). The correct one is (a) \(\mathrm{d}^{4}\) (in strong l
View solution Problem 163
The IUPAC name for the complex \(\left[\mathrm{Co}\left(\mathrm{NO}_{2}\right)\left(\mathrm{NH}_{3}\right)_{5}\right]\) \(\mathrm{Cl}_{2}\) is [2006] (a) nitrit
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