Problem 16
Question
Which of the following statements are true? (a) Si can form an ion with six fluorine atoms, \(\mathrm{SiF}_{6}^{2-}\), whereas carbon cannot. (b) Si can form three stable compounds containing two Si atoms each, \(\mathrm{Si}_{2} \mathrm{H}_{2}, \mathrm{Si}_{2} \mathrm{H}_{4},\) and \(\mathrm{Si}_{2} \mathrm{H}_{6}\) (c) In \(\mathrm{HNO}_{3}\) and \(\mathrm{H}_{3} \mathrm{PO}_{4}\) the central atoms, \(\mathrm{N}\) and \(\mathrm{P}\), have different oxidation states. (d) \(\mathrm{S}\) is more electronegative than Se.
Step-by-Step Solution
Verified Answer
Statements (a) and (d) are true; Statements (b) and (c) are false.
1Step 1: Understanding Ion Formation
Silicon (Si) can expand its octet and easily bond with six fluorine atoms, forming \(\mathrm{SiF}_{6}^{2-}\). Carbon, on the other hand, cannot extend its octet beyond four bonds due to lack of d-orbitals, hence cannot form \(\mathrm{CF}_{6}^{2-}\). Thus, the statement (a) is true.
2Step 2: Evaluating Silicon Compounds
Silicon can indeed form multiple hydrides. Known stable silicon hydrides including those that contain two silicon atoms are \(\mathrm{Si}_{2} \mathrm{H}_{6}\) (disilane). \(\mathrm{Si}_{2} \mathrm{H}_{2}\) and \(\mathrm{Si}_{2} \mathrm{H}_{4}\) are not stable. Consequently, statement (b) is false.
3Step 3: Analyzing Oxidation States
In \(\mathrm{HNO}_{3}\), nitrogen has an oxidation state of +5, while in \(\mathrm{H}_{3} \mathrm{PO}_{4}\), phosphorus has an oxidation state of +5 as well. Hence, statement (c) is false because their oxidation states are the same.
4Step 4: Electronegativity Comparison
Sulfur (S) is indeed more electronegative than Selenium (Se) due to its position higher up in the same group in the periodic table. Therefore, statement (d) is true.
Key Concepts
Ion FormationOxidation StatesElectronegativitySilicon Compounds
Ion Formation
Ion formation is a fundamental concept in chemistry that explains how atoms gain or lose electrons to form charged particles called ions. When atoms bond together, they often do so to achieve a more stable electronic configuration, often resembling that of noble gases. Silicon (
Si) is an interesting element because it can form complex ions by expanding its octet. This means that unlike carbon, which cannot exceed four bonds, silicon can form ions like
SiF_{6}^{2-}, where it bonds with six fluorine atoms. This is possible because silicon has empty d-orbitals that allow it to accommodate more electrons, expanding beyond the typical octet rule.
- Octet Expansion: Silicon has the capability to expand its octet by using its d-orbitals, allowing the formation of ions with more than eight electrons.
- Lack of d-Orbitals in Carbon: Carbon cannot expand beyond four bonds because it does not have available d-orbitals.
Oxidation States
Oxidation states, also known as oxidation numbers, are assigned to atoms within compounds to indicate the distribution of electrons among them. This concept helps in understanding electron transfer during chemical reactions. In acids like
HNO_{3} and
H_{3}PO_{4}, oxidation states provide insight into the chemical bonding and reactivity of different elements.
- Nitrogen and Phosphorus: In both HNO_{3} and H_{3}PO_{4}, the central atoms are nitrogen and phosphorus, respectively. Both these atoms exhibit an oxidation state of +5 in these compounds.
- Determining Oxidation States: This involves a set of rules, such as assigning a -2 oxidation state to oxygen, except in peroxides, and adjusting the sum to equal the charge of the molecule.
Electronegativity
Electronegativity is a measure of an atom's ability to attract and hold onto electrons in a chemical bond. It's a key concept that helps predict how atoms will interact in a molecule. For example, sulfur (S) is more electronegative than selenium (Se).
- Periodic Table Trend: Electronegativity typically increases across a period and decreases down a group in the periodic table.
- Sulfur vs. Selenium: Sulfur is located above selenium in the same group, thus it has a higher electronegativity, meaning it more effectively attracts electrons in bonds.
Silicon Compounds
Silicon exhibits versatile bonding, leading to the formation of a variety of compounds, some of which include silicon hydrides. However, not all conceivable silicon hydrides are stable.
- Stable Silicon Hydrides: Si_{2}H_{6}, also known as disilane, is a stable compound with two silicon atoms.
- Unstable Variants: Other hydrides like Si_{2}H_{2} and Si_{2}H_{4} are not stable because they do not exist under normal conditions due to their high reactivity and the lack of sufficient bonding stability.
Other exercises in this chapter
Problem 13
Consider the elements \(\mathrm{N}, \mathrm{F}\), Si, Rb, Te, and Ir. From this list, select the element that (a) is most electronegative, \((\mathbf{b})\) exhi
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(a) Give the names and chemical symbols for the three isotopes of hydrogen. (b) List the isotopes in order of decreasing natural abundance. (c) Which hydrogen i
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