Problem 16
Question
Use the product rule to simplify the expressions in Exercises \(13-22\). In Exercises \(17-22,\) assume that variables represent nonnegative real numbers. $$\sqrt{125 x^{2}}$$
Step-by-Step Solution
Verified Answer
The simplified form of the expression \(\sqrt{125 x^{2}}\) is \(5x\sqrt{5}\).
1Step 1: Identification
Identify the terms inside the square root, \(125\) and \(x^{2}\). Both are perfect squares.
2Step 2: Breaking down the square roots
Separate the square root of each term. This stems from the rule \(\sqrt{ab} = \sqrt{a} \cdot \sqrt{b}\). Hence, we have \(\sqrt{125} \cdot \sqrt{x^{2}}\).
3Step 3: Simplification
Calculating the square root of each term separately, we have: \( \sqrt{125} = 5\sqrt{5} \) and the \(\sqrt{x^{2}} = x\) (because we are assuming x to be a nonnegative real number according to the exercise instructions).
Key Concepts
Square RootsSimplificationNonnegative Real Numbers
Square Roots
Square roots are a mathematical operation that seeks to find a number which, when multiplied by itself, will equal the original number. The symbol used to represent a square root is \( \sqrt{\cdot} \). For instance, the square root of 9 is 3, because \( 3 \times 3 = 9 \). The concept of square roots is especially useful in simplifying expressions, as it allows us to break down more complex numbers into simpler factors.
When dealing with square roots, especially in algebraic expressions, it is often useful to express the square root of a product of variables and numbers separately, which is derived from the product rule for square roots. The product rule states:
When dealing with square roots, especially in algebraic expressions, it is often useful to express the square root of a product of variables and numbers separately, which is derived from the product rule for square roots. The product rule states:
- \( \sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b} \)
Simplification
Simplification is the process of reducing a mathematical expression to its simplest form, making it easier to work with. In algebra, simplification often involves factoring, canceling terms, and applying rules like the product rule for square roots.
For the expression \( \sqrt{125 x^2} \), simplification involves:
For the expression \( \sqrt{125 x^2} \), simplification involves:
- Breaking down \( \sqrt{125} \) into \( 5\sqrt{5} \). This is because 125 can be factored into \( 5 \times 5 \times 5 \), which simplifies to \( 5 \times \sqrt{5} \).
- Recognizing that \( \sqrt{x^2} = x \), given that \( x \) is a nonnegative real number.
Nonnegative Real Numbers
Nonnegative real numbers include all positive numbers and zero, essentially every number that is not negative. These numbers are frequently assumed in algebraic expressions to avoid complexities related to negatives and arithmetic involving undefined operations.
In the context of square roots, assuming variables are nonnegative helps us simplify expressions such as \( \sqrt{x^2} \) easily. This is because for nonnegative \( x \), the expression \( \sqrt{x^2} \) simplifies directly to \( x \) without needing to consider additional cases or absolute value symbols.
In the context of square roots, assuming variables are nonnegative helps us simplify expressions such as \( \sqrt{x^2} \) easily. This is because for nonnegative \( x \), the expression \( \sqrt{x^2} \) simplifies directly to \( x \) without needing to consider additional cases or absolute value symbols.
- Nonnegative numbers range from 0 to positive infinity: \( [0, \infty) \).
Other exercises in this chapter
Problem 15
Evaluate each exponential expression in Exercises 1–22. $$\left(2^{2}\right)^{3}$$
View solution Problem 16
Multiply or divide as indicated. $$\frac{6 x+9}{3 x-15} \cdot \frac{x-5}{4 x+6}$$
View solution Problem 16
Factor by grouping. $$ x^{3}-x^{2}-5 x+5 $$
View solution Problem 16
Find each product. $$(x+5)\left(x^{2}-5 x+25\right)$$
View solution