Problem 16
Question
Use the Laws of Logarithms to expand the expression. $$ \log _{5} \frac{x}{2} $$
Step-by-Step Solution
Verified Answer
\( \log_{5} x - \log_{5} 2 \)
1Step 1: Recognize the Logarithmic Property
Identify the logarithmic property needed for expansion. Here, we use the Quotient Rule for logarithms, which states that \( \log_b \frac{m}{n} = \log_b m - \log_b n \).
2Step 2: Apply the Quotient Rule
Apply the quotient rule to the expression \( \log_{5} \frac{x}{2} \). This gives us: \( \log_{5} x - \log_{5} 2 \).
3Step 3: Simplify Final Expression
The expression \( \log_{5} x - \log_{5} 2 \) is already as simplified as possible using the laws of logarithms for this context.
Key Concepts
Quotient RuleLogarithmic PropertiesLogarithmic Expansion
Quotient Rule
The Quotient Rule is one of the fundamental properties in the study of logarithms. It comes into play when you are dealing with a logarithm of a division, like \( \log_b \frac{m}{n} \). The rule indicates that the logarithm of a quotient is equivalent to the difference between the logarithms of the numerator and the denominator. So in mathematical terms, \( \log_b \frac{m}{n} = \log_b m - \log_b n \). This property simplifies calculations by transforming division into subtraction, which is often more straightforward to work with.
- It's not just a practical tool for simplification; it's vital for expanding expressions involving logarithms.
- It aligns with the basic principles of logarithms, where addition aligns with multiplication and subtraction aligns with division.
Logarithmic Properties
Logarithmic properties are essential rules that help you manipulate and simplify expressions involving logarithms. They are based on the idea that logarithms are the inverses of exponential functions. Here's a quick reminder of some basic properties:
- The Product Rule: \( \log_b (mn) = \log_b m + \log_b n \)
- The Power Rule: \( \log_b (m^n) = n \cdot \log_b m \)
- The Quotient Rule: This was covered in detail above, \( \log_b \frac{m}{n} = \log_b m - \log_b n \).
Logarithmic Expansion
Logarithmic expansion involves breaking down a more complex logarithmic expression into simpler parts to make it easier to work with or understand. This process utilizes the properties of logarithms, especially the ones like the Quotient Rule, Product Rule, and Power Rule. When you expand a logarithmic expression, you are essentially transforming the expression into a sum or difference of simpler logarithms.
The original exercise was a great example. We used logarithmic expansion to transform \( \log_{5} \frac{x}{2} \) into \( \log_{5} x - \log_{5} 2 \).
This is beneficial because:
The original exercise was a great example. We used logarithmic expansion to transform \( \log_{5} \frac{x}{2} \) into \( \log_{5} x - \log_{5} 2 \).
This is beneficial because:
- It allows for easier computation, especially with more complicated numbers.
- It provides a clear visual representation of the relationship between the components of the logarithm.
- It aids in identifying properties that can simplify solving equations.
Other exercises in this chapter
Problem 16
The mass \(m(t)\) remaining after \(t\) days from a 40-g sample of thorium- 234 is given by $$m(t)=40 e^{-0.0277 t}$$ (a) How much of the sample will remain aft
View solution Problem 16
Find the solution of the exponential equation, correct to four decimal places. $$ e^{3-5 x}=16 $$
View solution Problem 16
\(15-24\) Evaluate the expression. $$ \begin{array}{llll}{\text { (a) } \log _{5} 5^{4}} & {\text { (b) } \log _{4} 64} & {\text { (c) } \log _{9} 9}\end{array}
View solution Problem 17
The half-life of strontium-90 is 28 years. How long will it take a 50-mg sample to decay to a mass of 32 mg?
View solution