Problem 16
Question
Use the given conditions to write an equation for each line in point-slope form and slope-intercept form. Slope \(--5,\) passing through \((-4,-2)\)
Step-by-Step Solution
Verified Answer
The equation of the line in point-slope form is \(y + 2 = -5(x + 4)\) and in slope-intercept form is \(y = -5x - 22\).
1Step 1: Apply the Point-Slope Form
First, plug the given point \((-4, -2)\) and the slope \(-5\) into the point-slope formula \(y - y1 = m(x - x1)\). Thus, the equation becomes \(y - (-2) = -5(x - (-4))\).
2Step 2: Simplify the Equation
Next, simplify the above equation to get the equation of the line in point-slope form. This results in \(y + 2 = -5(x + 4)\).
3Step 3: Apply the Slope-Intercept Form
Now, rearrange the formula from step 2 to match the format of the slope-intercept form \(y = mx + b\). Doing so, you get \(y = -5x - 20 - 2\) which simplifies to \(y = -5x - 22\).
Key Concepts
Point-Slope FormSlope-Intercept FormEquation of a Line
Point-Slope Form
The Point-Slope Form is a useful way to write the equation of a line when you're given a point on the line and the slope. It is formulated as \(y - y_1 = m(x - x_1)\), where \(m\) represents the slope and \((x_1, y_1)\) is a specific point on the line. This form is particularly handy because it directly utilizes the given data: a point and a slope, making it quicker to form an equation.
- Start with identifying the slope \(m\) and the point \((x_1, y_1)\).
- Plug these values into the formula.
Slope-Intercept Form
After you have a line's equation in point-slope form, you can rearrange it into slope-intercept form, \(y = mx + b\). This form is incredibly popular because it directly shows the slope \(m\) and the y-intercept \(b\), the point where the line crosses the y-axis.
- Start with your point-slope equation.
- Distribute the slope through any parentheses.
- Solve for \(y\) to put the equation in \(y = mx + b\) form.
Equation of a Line
The equation of a line can be expressed in multiple forms, each useful for different scenarios. Whether you're working with the point-slope form or converting it to the slope-intercept form, you're describing the same line through numbers. This versatility helps in various applications from graphing to solving real-world problems.
- Point-slope form is great for constructing an equation with specific points and slope.
- Slope-intercept form provides a clean view of how the line behaves with respect to the axes.
Other exercises in this chapter
Problem 16
Find the average rate of change of the function from \(x_{1}\) to \(x_{2}\) \(f(x)-x^{2}-2 x\) from \(x_{1}-3\) to \(x_{2}-6\)
View solution Problem 16
Find the distance between each pair of points. If necessary, round answers to two decimals places. $$(2 \sqrt{3}, \sqrt{6})\( and \)(-\sqrt{3}, 5 \sqrt{6})$$
View solution Problem 16
Find the domain of each function. $$ f(x)-\frac{1}{\frac{4}{x-2}-3} $$
View solution Problem 17
The functions are all one-to-one. For each function, a. Find an equation for \(f^{-1}(x),\) the inverse function. b. Verify that your equation is correct by sho
View solution