Problem 16
Question
use the fact that if \(\boldsymbol{A}=\left[\begin{array}{ll}{\boldsymbol{a}} & {\boldsymbol{b}} \\ {\boldsymbol{c}} & {\boldsymbol{d}}\end{array}\right],\) then \(A^{-1}=\frac{1}{a d-b c}\left[\begin{array}{cc}{d} & {-b} \\ {-c} & {a}\end{array}\right]\) to find the inverse of each matrix, if possible. Check that \(A A^{-1}=I_{2}\) and \(A^{-1} A=I_{2}\) $$ A=\left[\begin{array}{ll} {2} & {-6} \\ {1} & {-2} \end{array}\right] $$
Step-by-Step Solution
Verified Answer
The inverse of the matrix \( A = \[ \[2, -6\], \[1, -2\] \] \) is \( A^{-1} = \[ \[-0.2, 0.6\], \[-0.1, 0.2\] \] \).
1Step 1: Apply the formula
The matrix \( A = \[ \[2, -6\], \[1, -2\] \] \). According to the formula, first calculate the denominator, which is ad-bc. In this case, a=2, b=-6, c=1 and d=-2. Hence, ad-bc=(2*-2)-(-6*1)=4+6=10. The denominator is not equal to zero, hence an inverse exists. Apply the formula to find the inverse matrix. This results in \( A^{-1} = 1/10 \[ \[-2, 6\], \[-1, 2\] \] = \[ \[-0.2, 0.6\], \[-0.1, 0.2\] \] \).
2Step 2: Verify the inverse matrix
Multiply the original matrix A with its inverse. If the resulting matrix is the identity matrix \( I_2 = \[ \[1, 0\], \[0, 1\] \] \), then the inverse matrix is correct. Starting with \( A A^{-1} \), multiply each element with corresponding element in the inverse matrix and sum the products:\( A A^{-1}= \[ \[2, -6\], \[1, -2\] \] * \[ \[-0.2, 0.6\], \[-0.1, 0.2\] \] = \[ \[1, 0\], \[0, 1\] \] \).Next, multiply \( A^{-1}A \) to further validate the inverse:\( A^{-1}A = \[ \[-0.2, 0.6\], \[-0.1, 0.2\] \] * \[ \[2, -6\], \[1, -2\] \] = \[ \[1, 0\], \[0, 1\] \] \).In both cases, the result is the identity matrix, validating the calculated inverse.
Key Concepts
2x2 matrixinverse matrix verificationdeterminant calculation
2x2 matrix
A 2x2 matrix is a simple, yet powerful, mathematical tool used widely in linear algebra. It consists of two rows and two columns and can be expressed as:
Understanding the layout and functionality of a 2x2 matrix is crucial because it forms the basis for more complex matrices and operations.
- \( \boldsymbol{A} = \left[ \begin{array}{cc} a & b \ c & d \end{array} \right] \).
Understanding the layout and functionality of a 2x2 matrix is crucial because it forms the basis for more complex matrices and operations.
inverse matrix verification
Once an inverse matrix is calculated, checking its accuracy is crucial. The verification involves ensuring that multiplying the matrix by its inverse yields the identity matrix. The identity matrix for a 2x2 array is:
- \( I_2 = \left[ \begin{array}{cc} 1 & 0 \ 0 & 1 \end{array} \right] \)
- \( A \times A^{-1} = I_2 \)
- \( A^{-1} \times A = I_2 \)
- \( \left[ \begin{array}{cc} 1 & 0 \ 0 & 1 \end{array} \right] \)
determinant calculation
Calculating the determinant is an essential step in identifying whether a matrix can have an inverse. The determinant of a 2x2 matrix \( \boldsymbol{A} = \left[ \begin{array}{cc} a & b \ c & d \end{array} \right] \) is given by:
- \( \,det(A) = ad - bc \)
- \( 2 \times (-2) - (-6) \times 1 = -4 + 6 = 2 \)
Other exercises in this chapter
Problem 16
Perform each matrix row operation and write the new matrix. $$ \left[\begin{array}{rrr|r} {1} & {-1} & {5} & {-6} \\ {3} & {3} & {-1} & {10} \\ {1} & {3} & {2}
View solution Problem 16
Use Cramer’s Rule to solve each system. $$\left\\{\begin{array}{l}{3 x+2 y=2} \\\\{2 x+2 y=3}\end{array}\right.$$
View solution Problem 16
Use Gaussian elimination to find the complete solution to each system of equations, or show that none exists. $$ \left\\{\begin{array}{r} {3 x+2 y-z=5} \\ {x+2
View solution Problem 17
Let $$ A=\left[\begin{array}{rr} {-3} & {-7} \\ {2} & {-9} \\ {5} & {0} \end{array}\right] \text { and } B=\left[\begin{array}{rr} {-5} & {-1} \\ {0} & {0} \\ {
View solution