Problem 16
Question
Use radical notation to write each expression. Simplify if possible. $$ (-32)^{1 / 5} $$
Step-by-Step Solution
Verified Answer
The simplified form is -2.
1Step 1: Understand Radical Notation
Radical notation involves writing expressions with roots using the radical symbol. The expression \((-32)^{1/5}\) is equivalent to saying "the fifth root of -32."
2Step 2: Convert to Radical Notation
Write the expression \((-32)^{1/5}\) using radical notation. The expression becomes \(\sqrt[5]{-32}\), which reads as "the fifth root of -32."
3Step 3: Calculate the Fifth Root
Determine the number that, when raised to the fifth power, results in -32. Since \((-2)^5 = -32\), the fifth root of \(-32\) is \(-2\).
4Step 4: Simplification
Since the fifth root of -32 is -2, the simplified form of the expression in radical notation is -2.
Key Concepts
Fifth RootsExpression SimplificationExponentiation Concepts
Fifth Roots
The concept of fifth roots is a fascinating part of mathematics that involves finding a number, which, when multiplied by itself five times, returns the original value you're interested in. Specifically, for any given number \(x\), the fifth root, often expressed as \(\sqrt[5]{x}\), refers to a number \(a\) such that \(a^5 = x\).
For a practical example, let's consider \((-32)\). When you take the fifth root of \(-32\), you are seeking a number that, when raised to the power of five, equals \(-32\). In this case, that number is \(-2\), because:
For a practical example, let's consider \((-32)\). When you take the fifth root of \(-32\), you are seeking a number that, when raised to the power of five, equals \(-32\). In this case, that number is \(-2\), because:
- \((-2) \times (-2) \times (-2) \times (-2) \times (-2) = -32\).
Expression Simplification
Simplifying expressions is a crucial skill in mathematics that involves reducing an expression to its simplest form. This often means finding a number or expression that is easier to work with or more understandable without changing the value of the original expression.
In the case of our example \((-32)^{1/5}\), you're simplifying the expression by calculating what \((-32)\) results in when expressed under the fifth root, which is
In the case of our example \((-32)^{1/5}\), you're simplifying the expression by calculating what \((-32)\) results in when expressed under the fifth root, which is
- First, express the power in radical notation: \((-32)^{1/5} = \sqrt[5]{-32}\).
- Then calculate the fifth root: \(\sqrt[5]{-32} = -2\).
Exponentiation Concepts
Exponentiation is a key concept in algebra that involves repeated multiplication of a base number. When dealing with expressions like \((-32)^{1/5}\), you are indeed leveraging the fractional exponent's relationship to roots.
In exponential terms, \(x^{1/n}\) denotes the \(n\)th root of \(x\). Therefore, the expression \((-32)^{1/5}\) can be reinterpreted in radical terms as the fifth root, \(\sqrt[5]{-32}\). This concept shows the powerful relationship between roots and exponents, where a fractional exponent is essentially an indicator of a root.
In exponential terms, \(x^{1/n}\) denotes the \(n\)th root of \(x\). Therefore, the expression \((-32)^{1/5}\) can be reinterpreted in radical terms as the fifth root, \(\sqrt[5]{-32}\). This concept shows the powerful relationship between roots and exponents, where a fractional exponent is essentially an indicator of a root.
- Fractional exponents connect directly to roots, allowing for flexible expression transformations.
- This relationship simplifies complex problems, making exponential expressions manageable.
Other exercises in this chapter
Problem 16
Use a calculator to approximate each square root to 3 decimal places. $$ \sqrt{56} $$
View solution Problem 16
Simplify. See Example 1. $$ \sqrt{-63} $$
View solution Problem 16
Rationalize each denominator. See Examples 1 through 3. $$ \frac{5}{\sqrt[3]{9}} $$
View solution Problem 16
Solve. \(\sqrt{2 x-3}=3-x\)
View solution