Problem 16
Question
The uranium-235 radioactive decay series, beginning with \(_{92}^{235} \mathrm{U}\) and ending with \(_{82}^{207} \mathrm{Pb},\) occurs in the following sequence: \(\alpha, \beta, \alpha, \beta, \alpha, \alpha, \alpha, \alpha, \beta, \beta, \alpha .\) Write an equation for each step in this series.
Step-by-Step Solution
Verified Answer
The series starts with \(^{235}_{92}\text{U}\) and ends with \(^{207}_{82}\text{Pb}.\)
1Step 1: Understand Decay Processes
In radioactivity, an \(\alpha\) decay reduces the mass number by 4 and the atomic number by 2. A \(\beta\) decay keeps the mass number the same and increases the atomic number by 1.
2Step 2: Initial Nuclear Equation
The series starts with \(^{235}_{92}\text{U}.\) We will apply the decay steps sequentially, beginning with \(\alpha\) decay.
3Step 3: First Decay (Alpha)
From \(^{235}_{92}\text{U},\) apply \(\alpha\) decay to get \(^{231}_{90}\text{Th}.\)
4Step 4: Second Decay (Beta)
From \(^{231}_{90}\text{Th},\) apply \(\beta\) decay to get \(^{231}_{91}\text{Pa}.\)
5Step 5: Third Decay (Alpha)
From \(^{231}_{91}\text{Pa},\) apply \(\alpha\) decay to get \(^{227}_{89}\text{Ac}.\)
6Step 6: Fourth Decay (Beta)
From \(^{227}_{89}\text{Ac},\) apply \(\beta\) decay to get \(^{227}_{90}\text{Th}.\)
7Step 7: Fifth Decay (Alpha)
From \(^{227}_{90}\text{Th},\) apply \(\alpha\) decay to get \(^{223}_{88}\text{Ra}.\)
8Step 8: Sixth Decay (Alpha)
From \(^{223}_{88}\text{Ra},\) apply \(\alpha\) decay to get \(^{219}_{86}\text{Rn}.\)
9Step 9: Seventh Decay (Alpha)
From \(^{219}_{86}\text{Rn},\) apply \(\alpha\) decay to get \(^{215}_{84}\text{Po}.\)
10Step 10: Eighth Decay (Alpha)
From \(^{215}_{84}\text{Po},\) apply \(\alpha\) decay to get \(^{211}_{82}\text{Pb}.\)
11Step 11: Ninth Decay (Beta)
From \(^{211}_{82}\text{Pb},\) apply \(\beta\) decay to get \(^{211}_{83}\text{Bi}.\)
12Step 12: Tenth Decay (Beta)
From \(^{211}_{83}\text{Bi},\) apply \(\beta\) decay to get \(^{211}_{84}\text{Po}.\)
13Step 13: Eleventh Decay (Alpha)
From \(^{211}_{84}\text{Po},\) apply \(\alpha\) decay to reach the endpoint \(^{207}_{82}\text{Pb}.\)
Key Concepts
alpha decaybeta decayuranium-235 decaynuclear reactionstransmutation
alpha decay
Alpha decay is a fascinating process in nuclear physics where an unstable nucleus releases an alpha particle. An alpha particle is essentially a helium nucleus, consisting of two protons and two neutrons. This emission leads to two significant changes in the original atom's nucleus:
- The atomic number decreases by 2.
- The mass number decreases by 4.
beta decay
Beta decay is another crucial type of radioactive decay in nuclear physics. Unlike alpha decay, beta decay involves the transformation of a neutron into a proton within the nucleus, and the emission of an electron (or \(\beta\) particle). During this process:
- The atomic number increases by 1.
- The mass number remains unchanged.
uranium-235 decay
Uranium-235 decay is a process demonstrating a typical radioactive decay series. This specific series begins with uranium-235 (\(^{235}_{92}\mathrm{U}\)) and concludes with lead-207 (\(^{207}_{82}\mathrm{Pb}\)). The journey between these two points involves multiple decays:
- Alpha decays: 8 times, removing mass and reducing the atomic number by 2 each time.
- Beta decays: 3 times, maintaining mass but increasing the atomic number by 1 each time.
nuclear reactions
Nuclear reactions encompass the various processes in which the structure of an atom's nucleus changes. These reactions include both natural radioactive decay, like alpha and beta decay, and man-made processes like fission and fusion. Key features of nuclear reactions are:
- Involvement of changes to the nucleus, rather than the electron shell.
- Release or absorption of large amounts of energy.
transmutation
Transmutation refers to the conversion of one element or isotope into another through nuclear reactions, a process intrinsic to radioactive decay series. It occurs naturally, as witnessed in uranium-235 decay where this element steadily transforms into lead-207. Throughout this process:
- Alpha decays reduce atomic mass, shifting the element left on the periodic table.
- Beta decays increase atomic numbers, promoting a shift to the right.
Other exercises in this chapter
Problem 14
Complete the following nuclear equations. Write the mass number, atomic number, and symbol for the remaining particle. (a) \(^{111}_{47} \mathrm{Ag} \longrighta
View solution Problem 15
Complete the following nuclear equations. Write the mass number, atomic number, and symbol for the remaining particle. (a) \(_{10}^{19} \mathrm{Ne} \longrightar
View solution Problem 17
The thorium-232 radioactive decay series, beginning with \(^{232}_{90}\)Th and ending with \(^{208}_{82}\)Pb, occurs in the following sequence: \(\alpha, \beta,
View solution Problem 18
What particle is emitted in the following nuclear reactions? Write an equation for each reaction. (a) Gold-198 decays to mercury-198. (b) Radon-222 decays to po
View solution