Problem 16
Question
The reaction of zinc with dilute and concentrated nitric acid, respectively, produces: (a) \(\mathrm{NO}\) and \(\mathrm{N}_{2} \mathrm{O}\) (b) \(\mathrm{NO}_{2}\) and \(\mathrm{N}_{2} \mathrm{O}\) (c) \(\mathrm{N}_{2} \mathrm{O}\) and \(\mathrm{NO}_{2}\) (d) \(\mathrm{NO}_{2}\) and \(\mathrm{NO}\)
Step-by-Step Solution
Verified Answer
Option (d) NO₂ and NO.
1Step 1: Understanding the Reaction of Zinc with Nitric Acid
The reaction of zinc (Zn) with nitric acid (HNO₃) depends on the concentration of the acid. Typically, dilute nitric acid acts as an oxidizing agent producing nitrogen monoxide (NO), while concentrated nitric acid usually leads to the production of nitrogen dioxide (NO₂). Both reactions produce zinc nitrate and other by-products like water.
2Step 2: Examining the Reaction of Zinc with Dilute Nitric Acid
When zinc reacts with dilute nitric acid, the primary oxidation product formed is nitrogen monoxide (NO). The chemical equation for this reaction is: \[ 3 ext{Zn} + 8 ext{HNO}_3
ightarrow 3 ext{Zn(NO}_3)_2 + 4 ext{H}_2 ext{O} + 2 ext{NO} \] This indicates that NO is the major gas evolved in this reaction.
3Step 3: Examining the Reaction of Zinc with Concentrated Nitric Acid
In this case, zinc reacts with concentrated nitric acid to form nitrogen dioxide (NO₂) as the main nitrogen oxide product. The equation is: \[ ext{Zn} + 4 ext{HNO}_3
ightarrow ext{Zn(NO}_3)_2 + 2 ext{H}_2 ext{O} + 2 ext{NO}_2 \] This indicates that NO₂ is the major gas evolved in this reaction.
4Step 4: Matching Reactions with Given Options
From the analysis above, with dilute nitric acid, the product is NO, and with concentrated nitric acid, the product is NO₂. Looking at the options, the reaction that matches these products is: (d) NO₂ and NO.
Key Concepts
Oxidizing AgentsNitric Acid ConcentrationNitrogen Oxides Formation
Oxidizing Agents
An oxidizing agent is a chemical substance that gains electrons and, in the process, causes another substance to lose electrons. In the reaction between zinc and nitric acid, nitric acid acts as an oxidizing agent. This means that the nitric acid takes electrons away from zinc, allowing zinc to be oxidized.
Zinc, being a metal, is keen to lose electrons and readily donates them to the nitric acid. This electron transfer results in changes for both substances involved:
- The zinc (Zn) is converted into zinc ions (Zn²⁺), which integrate into the zinc nitrate (Zn(NO₃)₂) compound.
- The nitric acid (HNO₃) is reduced and forms by-products, such as nitrogen oxides, which can vary depending on the concentration of the acid.
Nitric Acid Concentration
The concentration of nitric acid is a key factor in determining the outcome of its reaction with zinc. Nitric acid can be found in either a dilute or concentrated form, and each produces distinct products when reacting with metals like zinc.
When dilute nitric acid is used, the less aggressive environment leads to the production of nitrogen monoxide (
O). This less oxidizing condition does not fully oxidize nitrogen in the nitric acid.
In contrast, concentrated nitric acid has a greater oxidizing ability. This results in the formation of nitrogen dioxide (
NO₂), which is a reddish-brown gas. The differences in products highlight how merely altering the concentration of an oxidizing agent like nitric acid can result in different types of nitrogen oxides. This is not just an academic point; it's essential for industrial and laboratory applications where specific reactions are desired.
Nitrogen Oxides Formation
Nitrogen oxides are compounds consisting of nitrogen and oxygen, and they are a significant outcome in reactions involving nitric acid. In the context of zinc reacting with nitric acid, we typically observe two nitrogen oxides: nitrogen monoxide (
O) and nitrogen dioxide (
NO₂).
- In the presence of dilute nitric acid, nitrogen monoxide ( O) is formed. This colorless gas can be further oxidized in the air to form nitrogen dioxide.
- With concentrated nitric acid, nitrogen dioxide ( NO₂) is directly formed. This gas is notable for its brownish color and is commonly associated with photochemical smog.
Other exercises in this chapter
Problem 14
Which of the following ions does not liberate hydrogen gas on reaction with dilute acids ? (a) \(\mathrm{Ti}^{2+}\) (b) \(\mathrm{V}^{2+}\) (c) \(\mathrm{Cr}^{2
View solution Problem 15
Which of the following combination will produce \(\mathrm{H}_{2}\) gas? (a) Fe metal and conc. \(\mathrm{HNO}_{3}\) (b) Cu metal and conc. \(\mathrm{HNO}_{3}\)
View solution Problem 17
Which of the following compounds is metallic and ferromagnetic? (a) \(\mathrm{VO}_{2}\) (b) \(\mathrm{MnO}_{2}\) (c) \(\mathrm{TiO}_{2}\) (d) \(\mathrm{CrO}_{2}
View solution Problem 18
The transition metal ions responsible for colour in ruby and emerald are, respectively: (a) \(\mathrm{Co}^{3+}\) and \(\mathrm{Cr}^{3+}\) (b) \(\mathrm{Co}^{3+}
View solution