Problem 16
Question
The number of dibromo derivatives of propane are (a) 5 (b) 4 (c) 3 (d) 2
Step-by-Step Solution
Verified Answer
There are 4 dibromo derivatives of propane.
1Step 1: Understand Propane Structure
Propane (\[\text{C}_3\text{H}_8\]) is a saturated hydrocarbon with a linear chain of three carbon atoms.
2Step 2: Consider Possible Positions for Bromine
Examine the possible positions on the propane molecule where bromine atoms can be substituted; these are onto different carbon atoms.
3Step 3: Generate Substitution Variants
Consider bromination at each carbon atom. For propane, the first carbon (\[\text{C}_1\]) and the last carbon (\[\text{C}_3\]) are equivalent due to symmetry, allowing substitution at equivalent positions.
4Step 4: Count Isomers with Replacement
Replace two hydrogens with two bromines:
- 1,1-dibromopropane
- 2,2-dibromopropane
- 1,2-dibromopropane
- 1,3-dibromopropane
This gives four different dibromo isomers.
Key Concepts
Propane StructureBromine SubstitutionIsomer CountingOrganic Chemistry Reactions
Propane Structure
Propane, with the chemical formula \(\text{C}_3\text{H}_8\), is a simple, yet fundamental, saturated hydrocarbon. It consists of three carbon atoms linked in a straight chain, each one forming single bonds with hydrogen atoms to complete their valence shells. The structure is straightforward:
- The first carbon atom is bonded to three hydrogens and one of the intermediate carbons.
- The middle carbon connects to two other carbons and two hydrogens.
- The last carbon mirrors the first with three hydrogens and a connection to the adjacent carbon.
Bromine Substitution
Bromine substitution in organic chemistry refers to the replacement of hydrogen atoms with bromine atoms in a molecule. Propane can undergo a substitution reaction where bromine atoms replace one or more hydrogen atoms attached to the carbon backbone. In the case of propane:
- Substitution typically occurs at carbon atoms which can host more bromine atoms, thereby creating different molecules.
- The outer carbon atoms (\(\text{C}_1\) and \(\text{C}_3\)) are equivalent due to the symmetry of the propane molecule. This symmetry simplifies potential substitution patterns, as replacing hydrogen on these carbons can yield equivalent results.
Isomer Counting
Isomers are molecules with the same molecular formula but different arrangements of atoms in space. Counting isomers involves identifying all the different possible molecular configurations that a compound like a dibromo derivative of propane can form.
For dibromo derivatives of propane:
- Four distinct isomers arise from different bromine substitution patterns.
- These isomers include 1,1-dibromopropane, 2,2-dibromopropane, 1,2-dibromopropane, and 1,3-dibromopropane.
- Each arrangement is unique based on the position of the bromine atoms relative to the carbon chain.
Organic Chemistry Reactions
Organic chemistry often examines the transformation of molecules through various reactions. Substitution reactions, like those involving bromine and propane, are key examples of how organic compounds can be transformed. These reactions typically involve the breaking of a bond in an organic molecule and formation of a new bond with a different atom or group.
Key aspects in the context of propane include:
- Substitution reaction mechanisms might proceed through radical processes, especially with bromine, which can form under ultraviolet light or heat.
- These reactions are harnessed to synthesize different molecules selectively, like the dibromo derivatives studied here.
Other exercises in this chapter
Problem 14
Chlorobenzene on heating with \(\mathrm{NH}_{3}\) under pressure in the presence of cuprous chloride gives (a) nitrobenzen (b) aniline (c) benzamide (d) 0 - and
View solution Problem 15
The most reactive halide towards \(\mathrm{SN}_{1}\) reaction is (a) sec-butyl chloride (b) tert-butyl chloride (c) n-butyl chloride (d) allyl chloride
View solution Problem 18
1,1 -dibromoethane when heated with zinc dust produces (a) ethyl bromide (b) ethene (c) vinyl bromide (d) 2 -butene
View solution Problem 19
The order of reactivity of alkyl halides towards elimination reaction is (a) \(1^{\circ}>2^{\circ}>3^{\circ}\) (b) \(2^{\circ}>1^{\circ}>3^{\circ}\) (c) \(3^{\c
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