Problem 16
Question
The lengths of two vectors a and \(b\) and the angle \(\theta\) between them are given. Find the length of their cross product, \(|\mathbf{a} \times \mathbf{b}|\). $$|\mathbf{a}|=0.12, \quad|\mathbf{b}|=1.25, \quad \theta=75^{\circ}$$
Step-by-Step Solution
Verified Answer
The magnitude of the cross product is approximately 0.1449.
1Step 1: Understand the Cross Product Formula
The magnitude of the cross product of two vectors \(\mathbf{a}\) and \(\mathbf{b}\) is given by the formula \(|\mathbf{a} \times \mathbf{b}| = |\mathbf{a}| \cdot |\mathbf{b}| \cdot \sin(\theta)\), where \(|\mathbf{a}|\) and \(|\mathbf{b}|\) are the magnitudes of the vectors, and \(\theta\) is the angle between them.
2Step 2: Convert Angle
Convert the angle \(\theta = 75^{\circ}\) to radians if necessary, but since the sine function can take degrees directly in many calculators, check your calculator settings. Otherwise, use the conversion: \(\theta_{rad} = \frac{75 \cdot \pi}{180}\).
3Step 3: Calculate Sine of Theta
Calculate \(\sin(75^{\circ})\) using a calculator. The sine of \(75^{\circ}\) is approximately \(0.9659\).
4Step 4: Plug Values into Cross Product Formula and Calculate
Now use the formula \(|\mathbf{a} \times \mathbf{b}| = |\mathbf{a}| \cdot |\mathbf{b}| \cdot \sin(\theta)\). Substitute \(|\mathbf{a}| = 0.12\), \(|\mathbf{b}| = 1.25\), and \(\sin(75^{\circ}) = 0.9659\) into the equation:\[|\mathbf{a} \times \mathbf{b}| = 0.12 \cdot 1.25 \cdot 0.9659.\]Calculate this expression to find the magnitude of the cross product.
5Step 5: Final Calculation
Calculate the product: \[0.12 \cdot 1.25 \cdot 0.9659 = 0.144885\]Thus, the magnitude of the cross product is approximately \(0.1449\).
Key Concepts
Vector MagnitudeSine FunctionAngle ConversionTrigonometry
Vector Magnitude
The magnitude of a vector is a measure of its length. Imagine a vector as an arrow pointing from one point to another in space. The magnitude corresponds to the length of this arrow. It provides a scalar (a single number) to represent the vector's size, without considering its direction. To calculate the magnitude of a vector \( \mathbf{a} \) with components \((a_1, a_2, a_3)\), you can use the formula:
- \( |\mathbf{a}| = \sqrt{a_1^2 + a_2^2 + a_3^2} \)
Sine Function
The sine function is a fundamental trigonometric function that appears in various math and physics problems. It relates the angle of a right triangle to the ratio of the length of the opposite side to the hypotenuse.For any angle \( \theta \) in degrees, the sine function is written as \( \sin(\theta) \). In our problem, we use \( \sin(75^\circ) \), which calculates to approximately \( 0.9659 \).
- The sine function is periodic, meaning it repeats its values in cycles.
- It ranges between \(-1\) and \(1\).
Angle Conversion
Angle conversion is the process of changing an angle from degrees to radians or vice versa. The standard unit of angular measure in mathematics is the radian. However, angles are often measured in degrees in practical problems, so conversion is common.To convert an angle from degrees to radians, use the formula:
- \( \theta_{rad} = \theta_{deg} \cdot \frac{\pi}{180} \)
Trigonometry
Trigonometry is the study of the relationships between the sides and angles of triangles. It is fundamental in understanding not just triangle properties but also periodic patterns and wave phenomena in physics and engineering. The cross product formula \( |\mathbf{a} \times \mathbf{b}| = |\mathbf{a}| \cdot |\mathbf{b}| \cdot \sin(\theta) \) is directly connected to trigonometric concepts.
- The formula shows how magnitudes and the sine of the angle between vectors affect their cross product.
- Understanding these relationships highlights how vectors combine in space to form new, perpendicular vectors.
Other exercises in this chapter
Problem 15
Determine whether the given vectors are perpendicular. $$\mathbf{u}=\langle 6,4\rangle, \quad \mathbf{v}=\langle- 2,3\rangle$$
View solution Problem 15
Express the vector with initial point \(P\) and terminal point \(Q\) in component form. $$P(5,3), \quad Q(1,0)$$
View solution Problem 16
A plane has normal vector \(n\) and passes through the point \(P\). (a) Find an equation for the plane. (b) Find the intercepts and sketch a graph of the plane.
View solution Problem 16
Find the vectors \(\mathbf{u}+\mathbf{v}, \mathbf{u}-\mathbf{v},\) and \(3 \mathbf{u}-\frac{1}{2} \mathbf{v}\) $$\mathbf{u}=\langle 0,1,-3\rangle, \quad v=\lang
View solution