Problem 16
Question
State whether each equation represents a direct, joint, or inverse variation. Then name the constant of variation. \(\frac{n}{m}=1.5\)
Step-by-Step Solution
Verified Answer
The equation represents a direct variation, and the constant of variation is 1.5.
1Step 1: Identify the form of the given equation
We have the equation \( \frac{n}{m} = 1.5 \). This can be rewritten as \( n = 1.5m \).
2Step 2: Determine the type of variation
The equation \( n = 1.5m \) is in the form of \( y = kx \), which represents a direct variation because one variable is directly proportional to the other.
3Step 3: Identify the constant of variation
In the equation \( n = 1.5m \), the constant of variation, \( k \), is the coefficient of \( m \), which is 1.5.
Key Concepts
Constant of VariationInverse VariationJoint Variation
Constant of Variation
The constant of variation is a crucial concept in understanding different types of variable relationships in mathematics. It is represented by the symbol \( k \). In direct variation equations, which take the form \( y = kx \), the constant \( k \) signifies the rate at which \( y \) changes with respect to \( x \).
In our example, \( \frac{n}{m} = 1.5 \) translates into \( n = 1.5m \). Here, the constant of variation is \( 1.5 \). This means that for every unit increase in \( m \), \( n \) increases by 1.5 units.
Constant of variation provides a fixed multiplier that helps define the proportionality between variables:
In our example, \( \frac{n}{m} = 1.5 \) translates into \( n = 1.5m \). Here, the constant of variation is \( 1.5 \). This means that for every unit increase in \( m \), \( n \) increases by 1.5 units.
Constant of variation provides a fixed multiplier that helps define the proportionality between variables:
- In direct variation, if one variable doubles, the other also doubles, provided \( k \) remains positive.
- It ensures predictability and uniformity in the relationship between the variables.
Inverse Variation
Inverse variation describes a scenario where one variable increases as the other decreases. In mathematical terms, this relationship is expressed as \( y = \frac{k}{x} \), where \( k \) is the constant of variation. Here, unlike direct variation, \( y \) and \( x \) are inversely related.
It's important not to confuse inverse variation with direct variation. While in direct variation, both variables move in the same direction, in inverse variation:
Inverse variation is often found in real-life scenarios such as the inverse relationship between speed and travel time when distance is constant.
It's important not to confuse inverse variation with direct variation. While in direct variation, both variables move in the same direction, in inverse variation:
- When \( x \) increases, \( y \) decreases.
- When \( x \) decreases, \( y \) increases.
Inverse variation is often found in real-life scenarios such as the inverse relationship between speed and travel time when distance is constant.
Joint Variation
Joint variation combines direct variation with more than one variable. When a variable is directly proportional to the product of two or more other variables, it is considered to involve joint variation. A common form this takes is \( z = kxy \), where \( z \) varies jointly with \( x \) and \( y \) and \( k \) is the constant of variation.
In joint variation:
In joint variation:
- Both \( x \) and \( y \) affect \( z \), meaning that changes in either one will influence \( z \).
- All variables increase or decrease simultaneously based on the same constant factor \( k \).
- This concept is applicable to scenarios like calculating the volume of a prism, where the volume is jointly proportional to the area of the base and the height.
Other exercises in this chapter
Problem 16
Solve each equation or inequality. Check your solutions. $$ \frac{2}{y+2}-\frac{y}{2-y}=\frac{y^{2}+4}{y^{2}-4} $$
View solution Problem 16
Identify the type of function represented by each equation. Then graph the equation. \(y=-1.5\)
View solution Problem 16
Determine the equations of any vertical asymptotes and the values of \(x\) for any holes in the graph of each rational function. $$ f(x)=\frac{x-5}{x^{2}-4 x-5}
View solution Problem 16
Simplify each expression. $$ \frac{x-\frac{x}{2}}{x+\frac{x}{8}} $$
View solution