Problem 16
Question
Solve the system. $$\left\\{\begin{array}{r} x-5 y=2 \\ 3 x-15 y=6 \end{array}\right.$$
Step-by-Step Solution
Verified Answer
The system has infinitely many solutions: \((x, y) = (5y + 2, y)\).
1Step 1: Write the System of Equations
The given system of equations is:1. \( x - 5y = 2 \)2. \( 3x - 15y = 6 \)
2Step 2: Notice the Relationship Between Equations
Observe that the second equation \( 3x - 15y = 6 \) is actually a multiple of the first equation \( x - 5y = 2 \). If you multiply the first equation by 3, you get:\( 3(x - 5y) = 3 \times 2 \)This simplifies to:\( 3x - 15y = 6 \), which is identical to the second equation.
3Step 3: Conclusion - Dependent System
Since the second equation is simply a multiple of the first, the system of equations is dependent, meaning there are infinitely many solutions. The two equations are effectively the same line.
4Step 4: Express General Solution
We can express the general solution in terms of one variable. If we solve the first equation for \( x \), we have:\( x = 5y + 2 \)Thus, the solution set is all pairs \( (x, y) \) such that \( x = 5y + 2 \).
Key Concepts
Dependent SystemsInfinite SolutionsEquation MultiplicationGeneral Solution Expression
Dependent Systems
A system of linear equations is called "dependent" if the equations are not truly independent of each other. This means one equation can be derived from another by multiplication or any simple algebraic manipulation. In our given system, \( x - 5y = 2 \) and \( 3x - 15y = 6 \), the second equation is merely the first equation multiplied by 3, indicating that these two lines are actually the same geometrically. When graphed, dependent systems appear as a single line where both equations overlap, leading to infinitely many solutions since any point on the line is a solution to both equations.
Dependent systems reflect scenarios where the given equations describe the same constraint or relationship between variables, rendering one of them redundant.
Dependent systems reflect scenarios where the given equations describe the same constraint or relationship between variables, rendering one of them redundant.
Infinite Solutions
When dealing with dependent systems, they always result in infinite solutions. This is because dependent equations represent the same line on a graph. Thus, rather than intersecting at a single point (as independent systems with unique solutions would), they coincide completely.
For the system \( x - 5y = 2 \) and \( 3x - 15y = 6 \), every (\(x, y\)) pair that satisfies one equation will satisfy the other, as they are different expressions of the same line. This results in infinitely many solutions, because there is not just one unique point but an entire line of points that solve both equations simultaneously.
For the system \( x - 5y = 2 \) and \( 3x - 15y = 6 \), every (\(x, y\)) pair that satisfies one equation will satisfy the other, as they are different expressions of the same line. This results in infinitely many solutions, because there is not just one unique point but an entire line of points that solve both equations simultaneously.
- This concept is crucial as it signifies that there are multiple ways to fulfill the conditions the equations describe, reflecting potential flexibility in real-world situations.
Equation Multiplication
Equation multiplication is a simple yet powerful technique used to reveal relationships between equations. By multiplying an equation by a constant, we do not change its set of solutions, only its appearance.
In our exercise, multiplying the first equation \( x - 5y = 2 \) by 3 transforms it into \( 3x - 15y = 6 \), making it identical to the second equation. This transformation helps identify dependent systems by showing that the equations are not unique, but rather parallel representations of the same relationship.
In our exercise, multiplying the first equation \( x - 5y = 2 \) by 3 transforms it into \( 3x - 15y = 6 \), making it identical to the second equation. This transformation helps identify dependent systems by showing that the equations are not unique, but rather parallel representations of the same relationship.
- This technique is essential to recognize and understand, particularly in solving systems where equations might initially seem different but actually convey the same information.
General Solution Expression
Expressing a general solution involves finding a formula that represents all possible solutions of a system with infinite solutions. Since the equations are dependent, we can express any variable in terms of one of the other variables.
For our system, isolating \( x \) in \( x - 5y = 2 \), we get \( x = 5y + 2 \). This equation expresses \( x \) entirely as a function of \( y \), allowing us to describe the entire solution set with a single statement.
This expression is very useful because:
For our system, isolating \( x \) in \( x - 5y = 2 \), we get \( x = 5y + 2 \). This equation expresses \( x \) entirely as a function of \( y \), allowing us to describe the entire solution set with a single statement.
This expression is very useful because:
- It succinctly encapsulates all the possible solutions.
- It can be used to easily find solutions by substituting any real number for \( y \), reflecting the infinite number of solutions.
Other exercises in this chapter
Problem 16
Find the determinant of the matrix. $$\left[\begin{array}{rrr} 2 & 7 & -3 \\ 1 & 0 & 4 \\ 4 & -1 & -2 \end{array}\right]$$
View solution Problem 16
Use matrices to solve the system. $$\left\\{\begin{aligned} 5 x+2 y-z &=10 \\ y+z &=-3 \end{aligned}\right.$$
View solution Problem 16
Sketch the graph of the system of Inequalities. $$\left\\{\begin{aligned}3 x-4 y & \geq 12 \\\x-2 y & \leq 2 \\\x & \geq 9 \\\y & \leq 5\end{aligned}\right.$$
View solution Problem 17
Find the partial fraction decomposition. \(\frac{x^{2}+x-6}{\left(x^{2}+1\right)(x-1)}\)
View solution