Problem 16
Question
Solve the equation by factoring. $$ 7 x^{2}+28 x+28=0 $$
Step-by-Step Solution
Verified Answer
The solution to the equation \(7x^{2}+28x+28=0\) by factoring is \(x = -2\).
1Step 1: Rewrite the equation in standard form
Confirm that the given equation \( 7x^{2}+28x+28=0 \) is in a standard form which is \(ax^{2} + bx + c = 0 \)
2Step 2: Factor out the Greatest Common Factor (GCF)
In this equation, the GCF is 7. Factor out 7 from all terms of the equation to simplify which leads to \( 7(x^{2}+4x+4)= 0\)
3Step 3: Factor the quadratic
Factorize the quadratic \(x^2 + 4x + 4\). This equation factors to \( (x+2)^2\). This gives us \(7(x+2)^2 = 0\)
4Step 4: Use the Zero product property
The Zero product property states that if the product of multiple factors equals zero, then at least one of the factors must be zero. Set the factor \(x+2\) equal to zero and solve for x which gives \(x = -2\)
Key Concepts
Greatest Common FactorZero Product PropertySolving Quadratic Equations
Greatest Common Factor
When solving quadratic equations by factoring, the first crucial step is often to find the Greatest Common Factor (GCF). The GCF is the largest number that can evenly divide all terms in an equation. Identifying and factoring out the GCF makes the equation simpler and easier to manage. To find the GCF, examine each term:
- Inspect the coefficients and constant terms to determine their shared divisor.
- In our exercise, the equation is \(7x^2 + 28x + 28 = 0\).
- The terms are: 7, 28, and 28. Notice they all can be divided by 7.
Zero Product Property
Once you've factored out common terms and simplified the quadratic equation, the Zero Product Property comes into play. This property is an essential shortcut in mathematics, stating that if the product of multiple factors equals zero, then at least one factor must be zero. This rule allows us to set each factor containing the variable equal to zero.After factoring, the equation looks like this: \(7(x+2)^2 = 0\). Here, two factors are impacting the equation: the number 7 and the expression \((x+2)^2\). Based on the Zero Product Property:
- If \(A \cdot B = 0\), then \(A = 0\) or \(B = 0\), or both.
- Applying this, 7 is never 0, so we focus on \((x+2)^2 = 0\).
- Solve \((x+2)^2 = 0\) by setting \((x+2)\) to zero: \(x + 2 = 0\).
- This simplifies to find \(x = -2\).
Solving Quadratic Equations
Solving quadratic equations involves manipulating the equation into a form where finding solutions is straightforward. Factoring and using properties like the ones discussed simplifies even complex quadratics:The equation provided in the exercise \(7x^2 + 28x + 28 = 0\), though initially difficult, becomes manageable through systematic steps:
- First, confirm the equation is in standard form: \(ax^2 + bx + c = 0\).
- Identify the GCF, here it is 7, and factor it out to simplify the equation.
- Rewrite the equation: \(7(x^2 + 4x + 4) = 0\).
- Look at the simplified quadratic \(x^2 + 4x + 4\), which can directly factor into \((x + 2)^2\).
- Apply the Zero Product Property to solve: set \(x + 2 = 0\) which results in \(x = -2\).
Other exercises in this chapter
Problem 15
Use the FOIL pattern to find the product. $$ (w-3)(w+5) $$
View solution Problem 16
Solve the equation. $$ 3 b^{2}+26 b+35=0 $$
View solution Problem 16
Factor the expression completely. \(5 b^{3}-25 b^{2}-70 b\)
View solution Problem 16
Factor the trinomial. $$ x^{2}+8 x-9 $$
View solution