Problem 16
Question
Solve each triangle. Round lengths to the nearest tenth and angle measures to the nearest degree. $$a=7, c=3, B=90^{\circ}$$
Step-by-Step Solution
Verified Answer
The values are approximately: \(b \approx 6.3\), \(A \approx 48^{\circ}\), and \(C \approx 42^{\circ}\)
1Step 1: Find length of side b
We apply the Pythagorean theorem \( a^2 = b^2 + c^2 \). Isolate \( b \) to obtain \( b = \sqrt{a^2 - c^2} \). Substituting \( a = 7 \) and \( c = 3 \) into the equation gives \( b = \sqrt{7^2 - 3^2} = \sqrt{40} \approx 6.3 \) to the nearest tenth.
2Step 2: Find angle A
We use the tangent trigonometric ratios which is \(\tan(\theta) = \frac{opposite}{adjacent}\). Since angle A is opposite side a and adjacent to side b, the formula becomes \( \tan(A) = \frac{a}{b} \). Therefore \(A = \arctan(\frac{a}{b})\). Substituting \( a = 7 \) and \( b = 6.3 \) into the equation gives \( A = \arctan(\frac{7}{6.3})\), which is approximately \(48^{\circ}\) when rounded to the nearest degree.
3Step 3: Find angle C
Because the sum of angles in a triangle equals \(180^{\circ}\), we subtract the known angles from \(180^{\circ}\) to find angle C. So, \( C = 180^{\circ} - A - B \). Substituting \( A = 48^{\circ} \) and \( B = 90^{\circ} \) into the equation gives \( C = 180^{\circ} - 48^{\circ} - 90^{\circ} = 42^{\circ}\).
Key Concepts
Pythagorean theoremtangent functionangle sum propertyright angle
Pythagorean theorem
The Pythagorean Theorem is a fundamental principle in geometry, especially useful in solving right triangles.
It establishes a relationship between the lengths of the sides of a right triangle.
It establishes a relationship between the lengths of the sides of a right triangle.
- The theorem states: \[ a^2 = b^2 + c^2 \]where \(a\) is the hypotenuse (the longest side), and \(b\) and \(c\) are the other two sides.
- In our exercise, given \(a = 7\) and \(c = 3\), we need to find side \(b\).
tangent function
The tangent function is one of the primary trigonometric functions used to find angles and sides in right triangles.
It is specifically helpful when you know two sides of the triangle and need to find an angle.
It is specifically helpful when you know two sides of the triangle and need to find an angle.
- The tangent ratio is defined as:\[ \tan(\theta) = \frac{opposite}{adjacent} \]
- In the given triangle, angle \(A\) is opposite side \(a = 7\) and adjacent to side \(b = 6.3\).
angle sum property
The angle sum property is a basic yet powerful tool for working with triangles.This property tells us that the sum of all interior angles in any triangle is always \(180^{\circ}\).
This holds true for all triangles, including right triangles.
This holds true for all triangles, including right triangles.
- In a right triangle, one angle is always \(90^{\circ}\).
- To find the remaining angle \(C\), given angles \(A\) and \(B\), you use the formula:\[ C = 180^{\circ} - A - B \]
right angle
Right angles are central to understanding right triangles and trigonometry.A right angle measures exactly \(90^{\circ}\) and signifies perpendicularity between two lines or edges.
In a right triangle:
In a right triangle:
- One of the triangle's three angles is always a right angle, setting the framework for Pythagorean relations and trigonometric calculations.
- This right angle affects the two remaining angles, ensuring their measures sum up to \(90^{\circ}\). Hence, if one angle is found, the other can be quickly calculated using the angle sum property.
Other exercises in this chapter
Problem 16
Test for symmetry and then graph each polar equation. $$r=1+\sin \theta$$
View solution Problem 16
Let $$\mathbf{u}=2 \mathbf{i}-\mathbf{j}, \quad \mathbf{v}=3 \mathbf{i}+\mathbf{j}, \quad \text { and } \quad \mathbf{w}=\mathbf{i}+4 \mathbf{j}$$ Find each spe
View solution Problem 16
In Exercises \(13-20\), let v be the vector from initial point \(P_{1}\) to terminal point \(P_{2} .\) Write \(\mathbf{v}\) in terms of \(\mathbf{i}\) and \(\ma
View solution Problem 16
In Exercises \(11-26,\) plot each complex number. Then write the complex number in polar form. You may express the argument in degrees or radians. $$ -3 i $$
View solution