Problem 16
Question
Simplify the quantities using \(m(z)=z^{2}\). $$m(z)-m(z-h)$$
Step-by-Step Solution
Verified Answer
The simplified expression is \(2zh - h^2\).
1Step 1: Apply the function to each term
First, we apply the given function \( m(z) = z^2 \) to each part of the expression \( m(z) - m(z-h) \). This results in two expressions: \( m(z) = z^2 \) and \( m(z-h) = (z-h)^2 \). Thus, our expression becomes \( z^2 - (z-h)^2 \).
2Step 2: Expand the Square of the Binomial
Next, we expand the expression \((z-h)^2\) using the formula \((a-b)^2 = a^2 - 2ab + b^2\). Applying this, we have \((z-h)^2 = z^2 - 2zh + h^2\).
3Step 3: Simplify the Expression
Substitute the expanded form \((z-h)^2 = z^2 - 2zh + h^2\) back into the original expression \(z^2 - (z-h)^2\). This gives \[ z^2 - (z^2 - 2zh + h^2) \]. Simplify the expression by distributing the negative sign: \[ z^2 - z^2 + 2zh - h^2 \]. The \(z^2\) terms cancel out, leaving \[ 2zh - h^2 \].
Key Concepts
Binomial ExpansionAlgebraic SimplificationFunction Transformation
Binomial Expansion
In calculus, binomial expansion plays a key role when we need to expand expressions involving terms raised to a power. An expression of the form
Remember, practicing these expansions with a variety of binomial combinations sharpens your skills and aids in more advanced calculus concepts.
- \((a-b)^2\)
- \((a-b)^2 = a^2 - 2ab + b^2\)
Remember, practicing these expansions with a variety of binomial combinations sharpens your skills and aids in more advanced calculus concepts.
Algebraic Simplification
Algebraic simplification involves reducing expressions to their simplest form. It is an integral part of calculus, as it allows complex formulas to be expressed more conveniently. In the provided exercise, once we expanded the binomial expression, our task was to simplify the overall equation by eliminating unnecessary terms. The expanded form of the expression was
- \(z^2 - (z^2 - 2zh + h^2)\)
- \(2zh - h^2\)
Function Transformation
Function transformation is the alteration of a function's formula to achieve a different graphical representation or to simplify an expression. It often involves shifting, stretching, or compressing a function's graph. In this particular exercise, we encountered a basic transformation where the function \(m(z) = z^2\) was applied to create new expressions, specifically \(m(z-h) = (z-h)^2\). Function transformation enables us to look at functions and their output from different perspectives. By understanding how transformations work, like shifting or compressing, it becomes easier to predict changes and adapt equations.
- Shifting involves moving a graph horizontally or vertically, as seen with \((z-h)^2\).
- In calculus, working with transformations is crucial for visualizing and understanding how functions behave under various conditions.
Other exercises in this chapter
Problem 16
In Exercises \(11-16,\) which function dominates as \(x \rightarrow \infty ?\) $$\sqrt{x} \text { or } \ln x$$
View solution Problem 16
Which of the following are continuous functions of time? (a) The quantity of gas in the tank of a car on a journey between New York and Boston. (b) The number o
View solution Problem 16
Find a linear function that generates the values in Table 1.3 $$\begin{array}{r|r|r|r|r|r}\hline x & 5.2 & 5.3 & 5.4 & 5.5 & 5.6 \\\\\hline y & 27.8 & 29.2 & 30
View solution Problem 16
Solve for \(x\) using logs. $$10^{x+3}=5 e^{7-x}$$
View solution