Problem 16
Question
Rewrite each sentence symbolically, where \(\mathrm{P}(x) : x\) is a 16 -bit machine, \(\mathrm{Q}(x) : x\) uses the ASCII" character set, and the UD \(=\) set of all computers. There exists a computer that is neither a 16 -bit machine nor uses the ASCIl character set.
Step-by-Step Solution
Verified Answer
The short answer for the given question is:
\(\exists x (\lnot\mathrm{P}(x) \land \lnot\mathrm{Q}(x))\)
1Step 1: Identify the given predicates
We are given \(\mathrm{P}(x): x\) is a 16-bit machine and \(\mathrm{Q}(x) : x\) uses the ASCII character set.
2Step 2: Identify the given UD
The UD (universal domain) is the set of all computers.
3Step 3: Use the existential quantifier
To express "there exists a computer," we use the existential quantifier ∃. In this case, the variable x represents a computer.
4Step 4: Express the negation of both conditions
To express that the computer is neither a 16-bit machine nor uses the ASCII character set, we will negate both predicates and use the conjunction ∧ to connect them. So, we have ¬P(x) ∧ ¬Q(x).
5Step 5: Combine the existential quantifier with the negated conditions
To complete the symbolic representation of the statement, we combine the existential quantifier and the negated conditions:
∃x (¬P(x) ∧ ¬Q(x))
This represents "There exists a computer (x) that is neither a 16-bit machine nor uses the ASCII character set."
Key Concepts
PredicatesExistential QuantifierNegationConjunctionUniversal Domain
Predicates
In symbolic logic, a predicate is a statement involving a variable that can be true or false depending on the value of the variable. It typically describes a property or a relation between entities. For example, in our exercise, we have two predicates:
Predicates are crucial in constructing logical expressions as they allow more complex conditions to be expressed about variables.
- \( P(x) \) represents the statement that "\( x \) is a 16-bit machine".
- \( Q(x) \) signifies the proposition that "\( x \) uses the ASCII character set".
Predicates are crucial in constructing logical expressions as they allow more complex conditions to be expressed about variables.
Existential Quantifier
The existential quantifier is a fundamental operator in logic used to indicate that a predicate holds true for at least one element in a specified domain.
It is symbolized by an inverted \( \forall \), which is \( \exists \). In the context of the problem, "there exists a computer..." is expressed as \( \exists x \).
This tells us that there is at least one computer within our specified domain, which is the set of all computers, for which the subsequent logical conditions are true.
It is symbolized by an inverted \( \forall \), which is \( \exists \). In the context of the problem, "there exists a computer..." is expressed as \( \exists x \).
This tells us that there is at least one computer within our specified domain, which is the set of all computers, for which the subsequent logical conditions are true.
Negation
Negation is a logical operation that converts a statement to its opposite in terms of truth value.
When negating a predicate, the operation is symbolized by \( eg \), which is placed before the predicate to indicate "not."
In this exercise, we negate both predicates because the statement involves a computer that "is neither a 16-bit machine nor uses the ASCII character set."
So we write it as \( eg P(x) \) and \( eg Q(x) \), indicating that the characteristics specified by \( P(x) \) and \( Q(x) \) are not true for the variable \( x \).
When negating a predicate, the operation is symbolized by \( eg \), which is placed before the predicate to indicate "not."
In this exercise, we negate both predicates because the statement involves a computer that "is neither a 16-bit machine nor uses the ASCII character set."
So we write it as \( eg P(x) \) and \( eg Q(x) \), indicating that the characteristics specified by \( P(x) \) and \( Q(x) \) are not true for the variable \( x \).
Conjunction
Conjunction is a binary operation used to combine two logical statements, which will be true if and only if both constituent statements are true.
The symbol for conjunction is \( \wedge \), representing the logical "and." In our exercise, the conjunction \( eg P(x) \wedge eg Q(x) \) signifies that both negated conditions are met for a particular computer \( x \).
Therefore, \( x \) must neither be a 16-bit machine nor use the ASCII character set, both conditions must hold simultaneously.
The symbol for conjunction is \( \wedge \), representing the logical "and." In our exercise, the conjunction \( eg P(x) \wedge eg Q(x) \) signifies that both negated conditions are met for a particular computer \( x \).
Therefore, \( x \) must neither be a 16-bit machine nor use the ASCII character set, both conditions must hold simultaneously.
Universal Domain
The universal domain, often abbreviated as UD, represents the set of all potential subjects or entities under discussion in a logical problem.
In this exercise, the universal domain is "the set of all computers," meaning that any variable \( x \) will refer to some computer.
This context helps us understand what kinds of objects our predicates and quantified statements (like those using \( \exists \)) are concerning.
The specification of the universal domain ensures that the logical expressions are evaluated in a consistent and relevant context.
In this exercise, the universal domain is "the set of all computers," meaning that any variable \( x \) will refer to some computer.
This context helps us understand what kinds of objects our predicates and quantified statements (like those using \( \exists \)) are concerning.
The specification of the universal domain ensures that the logical expressions are evaluated in a consistent and relevant context.
Other exercises in this chapter
Problem 16
Evaluate each boolean expression, where \(a=2, b=3, c=5,\) and \(d=7\). $$[\sim(b
View solution Problem 16
Prove each using the law of the contrapositive. If the square of an integer is odd, then the integer is odd.
View solution Problem 16
Prove each using the law of the contrapositive. If the square of an integer is odd, then the integer is odd.
View solution Problem 17
Use De Morgan's laws to evaluate each boolean expression, where \(x=2\) \(y=5,\) and \(z=3\) $$\sim|(x
View solution