Problem 16
Question
Plot the point given in polar coordinates and then give three different expressions for the point such that (a) \(r<0\) and \(0 \leq \theta \leq 2 \pi\) (b) \(r>0\) and \(\theta \leq 0\) (c) \(r>0\) and \(\theta \geq 2 \pi\) $$ (-\pi,-\pi) $$
Step-by-Step Solution
Verified Answer
Expressions: (-π, π), (π, 0), (π, 3π).
1Step 1: Understanding Polar Coordinates
Polar coordinates are expressed as \(r, \theta\), where \(r\) represents the radius (distance from the origin) and \(\theta\) represents the angle from the positive x-axis. In the point \((-\pi, -\pi)\), \(r = -\pi\) and \(\theta = -\pi\) radians.
2Step 2: Convert to Cartesian Coordinates
To better understand polar coordinates, convert \((-\pi, -\pi)\) into Cartesian coordinates using \(x = r \cos \theta\) and \(y = r \sin \theta\). Here, \(x = (-\pi) \cdot \cos(-\pi) = \pi\) and \(y = (-\pi) \cdot \sin(-\pi) = 0\). Thus, in Cartesian coordinates, the point is \((\pi, 0)\).
3Step 3: Expressing (a) \((r < 0, 0 \leq \theta \leq 2\pi)\)
We need to express the point with a negative radius and positive angle. Since \(\theta\) is \(-\pi\), add \(2\pi\) to it to shift it within the range: \(-\pi + 2\pi = \pi\). The point is represented as \((-\pi, \pi)\).
4Step 4: Expressing (b) \((r > 0, \theta \leq 0)\)
For a positive radius and non-positive angle, invert the radius and adjust the angle. The radius becomes positive \((\pi)\), and we shift \(\theta\) by adding \(\pi\) (to reach zero). Thus, the point is \(\pi, 0 \).
5Step 5: Expressing (c) \((r > 0, \theta \geq 2\pi)\)
Finally, for a positive radius and angle greater than or equal to \(2\pi\), add \(2\pi\) to our current \(\theta\). With \(r = \pi\) (positive) and \(\theta = -\pi + 4\pi = 3\pi\), the point is \(\pi, 3\pi\).
Key Concepts
Cartesian coordinatesradiusangleangle conversion
Cartesian coordinates
Cartesian coordinates are a fundamental concept in mathematics, useful for plotting points on a two-dimensional plane. Here, any location is identified using an ordered pair \(x, y\), which represents the horizontal and vertical distances from an origin point. This system is particularly intuitive as it relates directly to our everyday understanding of space.
- x-coordinate: The horizontal distance from the origin. It tells how far left or right a point is from the vertical axis.
- y-coordinate: The vertical distance from the origin. It indicates how far up or down a point is from the horizontal axis.
radius
In polar coordinates, the radius \(r\) is essential. It defines the distance from the origin to a specific point in the plane. This is not much different from the radius of a circle, which is the consistent distance from the center to any point on its boundary.
- A positive radius means that the point is in the intended direction from the origin.
- A negative radius flips the direction through the origin to the other side of the circle.
angle
In polar coordinates, the angle \(\theta\) is just as crucial as the radius. It determines the direction from the positive x-axis where the radius extends. Angles in polar coordinates are generally measured in radians, a natural choice in mathematics for measuring circular shapes.
- Angles help define the rotational placement of a point.
- Typically, angles in polar coordinates are represented starting from 0, going counterclockwise around the unit circle.
angle conversion
Converting angles in polar coordinates often involves shifting the angle \(\theta\) by full circular turns (usually represented as \(2\pi\) in radians). This conversion is key for re-expressing points.
- A subtraction or addition of \(2\pi\) moves the angle around by a full circle.
- When dealing with negative angles, adding \(2\pi\) helps to convert them into an equivalent positive angle.
- This flexibility allows points to be expressed uniquely based on constraints provided, such as ensuring \(0 \leq \theta \leq 2\pi\) or other specified ranges.
Other exercises in this chapter
Problem 16
Graph the following equations. $$ r=\frac{6}{3-\cos \left(\theta+\frac{\pi}{4}\right)} $$
View solution Problem 16
Solve for the remaining side(s) and angle(s), if possible, using any appropriate technique. $$ \beta=7^{\circ}, \gamma=170^{\circ}, c=98.6 $$
View solution Problem 17
In Exercises \(1-20\), plot the set of parametric equations by hand. Be sure to indicate the orientation imparted on the curve by the parametrization. $$ \left\
View solution Problem 17
In Exercises \(1-20\), use the pair of vectors \(\vec{v}\) and \(\vec{w}\) to find the following quantities. $$ \vec{v}=\left\langle\frac{1}{2}, \frac{\sqrt{3}}
View solution