Problem 16
Question
List the transformations needed to transform the graph of \(h(x)=2^{x}\) into the graph of the given function. $$g(x)=-5\left(2^{x-1}\right)+7$$
Step-by-Step Solution
Verified Answer
Answer: The transformations needed include a horizontal shift of 1 unit to the right, a vertical stretch by a factor of 5, a reflection across the x-axis, and a vertical shift of 7 units up.
1Step 1: Identify the base function
The base function here is h(x) = 2^x, an exponential function. We need to transform this function to get the desired function, g(x) = -5(2^(x-1)) + 7.
2Step 2: Identify horizontal shift
The given function is g(x) = -5(2^(x-1)) + 7. We can see that the exponent has been modified from x to (x-1). This is a horizontal shift of 1 unit to the right. So we write it as: Horizontal Shift = 1 unit to the right.
3Step 3: Identify vertical stretch/compression
Since the base function h(x) has been multiplied by -5, there is a vertical stretch by a factor of 5. This means that the graph of g(x) is 5 times taller than the graph of the base function h(x). So we write it as: Vertical Stretch/Compression = times 5.
4Step 4: Identify reflection
Because the -5 in g(x) = -5(2^(x-1)) + 7 is a negative value, there is a reflection across the x-axis. This change causes the graph to be flipped over the x-axis. So we write it as: Reflection across x-axis.
5Step 5: Identify vertical shift
In the given function, g(x) = -5(2^(x-1)) + 7, there is an added term of +7. This means that the graph has been shifted vertically up by 7 units. So we write it as: Vertical Shift = 7 units up.
Now, putting all the transformations together, we can describe the process of transforming the graph of h(x) = 2^x into the graph of g(x) = -5(2^(x-1)) + 7 as follows:
1. Horizontal Shift: 1 unit to the right
2. Vertical Stretch/Compression: times 5
3. Reflection: across x-axis
4. Vertical Shift: 7 units up
Key Concepts
Horizontal ShiftVertical StretchReflectionVertical Shift
Horizontal Shift
A horizontal shift refers to the movement of a graph along the x-axis. In the transformation of the function \(h(x) = 2^x\) into \(g(x) = -5(2^{x-1}) + 7\), we notice the change in the exponent from \(x\) to \(x-1\). This indicates a horizontal shift to the right.
- The "-1" inside the exponent means we are translating 1 unit to the right.
- This shift is crucial as it affects where the graph starts along the x-axis.
Vertical Stretch
A vertical stretch occurs when you multiply the function by a certain factor. In this instance, the original function, \(h(x) = 2^x\), is multiplied by -5, creating \(g(x) = -5(2^{x-1}) + 7\).
- This transformation scales the graph vertically by a factor of 5.
- Simply put, it makes the graph 5 times taller.
Reflection
Reflection refers to flipping a graph across a specific axis. In the function \(g(x) = -5(2^{x-1}) + 7\), the negative sign in front of the 5 indicates a reflection over the x-axis.
- This transformation inverts points on the graph of \(h(x) = 2^x\) downwards.
- All y-values of the graph change their signs due to this flip.
Vertical Shift
Vertical shifts are easier to spot as they involve adding or subtracting a constant outside the function. In the transformation from \(h(x) = 2^x\) to \(g(x) = -5(2^{x-1}) + 7\), the "+7" indicates a vertical shift upwards.
- Every point on the graph of the base function moves up by 7 units.
- It increases the height of the entire graph by a consistent amount, no matter the input \(x\).
Other exercises in this chapter
Problem 16
In Exercises \(11-16,\) let \(u=\ln x\) and \(v=\ln y .\) Write the given expression in terms of u and v. For example, $$\ln x^{3} y=\ln x^{3}+\ln y=3 \ln x+\ln
View solution Problem 16
Translate the given exponential statement into an equivalent logarithmic statement. $$10^{3}=1000$$
View solution Problem 17
Determine whether an exponential, power, or logarithmic model (or none or several of these) is appropriate for the data by determining which (if any) of the fol
View solution Problem 17
Factor the given expression. For example, $$x-x^{1 / 2}-2=\left(x^{1 / 2}-2\right)\left(x^{1 / 2}+1\right)$$ $$x^{2 / 3}+x^{1 / 3}-6$$
View solution