Problem 16
Question
Let \(\left(X, d_{X}\right)\) and \(\left(Y, d_{y}\right)\) be metric spaces, \(S \subset X, p \in X\) a cluster point of \(S,\) and let \(f: S \rightarrow Y\) be a function. Prove that \(f: S \rightarrow Y\) is continuous at \(p\) if and only if $$ \lim _{x \rightarrow p} f(x)=f(p) $$
Step-by-Step Solution
Verified Answer
The function \( f \) is continuous at \( p \) if and only if \( \lim_{x \to p} f(x) = f(p) \).
1Step 1: Define Continuity at a Point
To prove the statement, we start by defining what it means for a function \( f: S \rightarrow Y \) to be continuous at a point \( p \). A function \( f \) is continuous at a point \( p \) if for every \( \epsilon > 0 \), there exists a \( \delta > 0 \) such that for all \( x \in S \), if \( 0 < d_X(x, p) < \delta \), then \( d_Y(f(x), f(p)) < \epsilon \).
2Step 2: Define the Limit Condition
The statement \( \lim_{x \to p} f(x) = f(p) \) means that for every \( \epsilon > 0 \), there exists a \( \delta > 0 \) such that for all \( x \in S \setminus \{p\} \), if \( d_X(x, p) < \delta \), then \( d_Y(f(x), f(p)) < \epsilon \). This aligns with the definition of continuity at \( p \).
3Step 3: Prove the 'If' Direction
Assume that \( \lim_{x \to p} f(x) = f(p) \). By definition, for every \( \epsilon > 0 \), there exists a \( \delta > 0 \) such that whenever \( x \in S \setminus \{p\} \) and \( d_X(x, p) < \delta \), it follows that \( d_Y(f(x), f(p)) < \epsilon \). This matches the condition for continuity at \( p \), establishing that \( f \) is continuous at \( p \).
4Step 4: Prove the 'Only If' Direction
Assume that \( f \) is continuous at \( p \). By the definition of continuity, for every \( \epsilon > 0 \), there exists a \( \delta > 0 \) such that whenever \( x \in S \) and \( 0 < d_X(x, p) < \delta \), then \( d_Y(f(x), f(p)) < \epsilon \). Since continuity already implies the limit condition for points \( x \in S \setminus \{p\} \), it follows that \( \lim_{x \to p} f(x) = f(p) \).
5Step 5: Conclusion
Both directions have been proved, showing that \( f \) is continuous at \( p \) if and only if \( \lim_{x \to p} f(x) = f(p) \). Thus, the equivalence of continuity at a point and the limit condition is established.
Key Concepts
Understanding Metric SpacesLimit of a FunctionUnderstanding Cluster Points
Understanding Metric Spaces
To fully grasp the concept of metric spaces, it's essential to understand what they are. A metric space is a set equipped with a metric, which is a function that defines a distance between any two elements of the set. Think of it like a framework to measure how far apart two points are from each other. In mathematical terms, a metric space consists of a set \(X\) and a metric \(d_X(x, y)\) that satisfies the following conditions for all points \(x, y, z \in X\):
- \(d_X(x, y) \geq 0\) (non-negativity) with \(d_X(x, y) = 0\) if and only if \(x = y\).
- \(d_X(x, y) = d_X(y, x)\) (symmetry).
- \(d_X(x, z) \leq d_X(x, y) + d_X(y, z)\) (triangle inequality).
Limit of a Function
The limit of a function at a given point captures the idea of a function approaching a specific value as the input approaches a certain point. Formally, suppose we have a function \(f: S \rightarrow Y\) and a point \(p \in X\). We say the limit of \(f(x)\) as \(x\) approaches \(p\) is \(f(p)\), denoted as \(\lim_{x \to p} f(x) = f(p)\), if the function value \(f(x)\) gets arbitrarily close to \(f(p)\) as \(x\) gets arbitrarily close to \(p\).
This is formally defined such that for every \(\epsilon > 0\), there exists a \(\delta > 0\) for which:
This is formally defined such that for every \(\epsilon > 0\), there exists a \(\delta > 0\) for which:
- If \(0 < d_X(x, p) < \delta\), then \(d_Y(f(x), f(p)) < \epsilon\).
Understanding Cluster Points
A cluster point is a concept used to describe a type of "limit point" for a set. Given a subset \(S \subset X\) in a metric space, a point \(p \in X\) is considered a cluster point of \(S\) if every neighborhood around \(p\) contains at least one point from \(S\) different from \(p\) itself. This implies that \(p\) can be "approached" by points from \(S\).
To visualize this, think of the concept in terms of proximity:
To visualize this, think of the concept in terms of proximity:
- No matter how small an epsilon-neighborhood you take around \(p\), there will always be some point from \(S\) within this neighborhood.
- This defines \(p\)'s characteristic as a cluster point because points in \(S\) seemingly "gather" around \(p\).
Other exercises in this chapter
Problem 16
Let \((X, d)\) be a metric space. Show that there exists a bounded metric \(d^{\prime}\) such that \(\left(X, d^{\prime}\right)\) has the same open sets, that i
View solution Problem 16
Prove Proposition 7.4.6. That is, let \((X, d)\) be a complete metric space and \(E \subset X\) a closed set. Show that \(E\) with the subspace metric is a comp
View solution Problem 17
Let \((X, d)\) be a metric space. a) Prove that for every \(x \in X,\) there either exists \(a \delta>0\) such that \(B(x, \delta)=\\{x\\}\), or \(B(x, \delta)\
View solution Problem 17
Let \((X, d)\) be an incomplete metric space. Show that there exists a closed and bounded set \(E \subset X\) that is not compact.
View solution