Problem 16
Question
Let \(f: \mathbb{C} \rightarrow \mathbb{C}\) be an entire function. Assume the existence of \(m \in \mathbb{N}_{0}\), and of the positive constants \(M\) and \(R\), such that for all \(z\) with \(|z| \geq \mathbb{R}\) the inequality \(|f(z)| \leq M|z|^{m}\) is satisfied. Show: \(f\) is a polynomial of degree \(\leq m .\) What does this mean in the case \(m=0 ?\)
Step-by-Step Solution
Verified Answer
\( f \) is a polynomial of degree \( \leq m \). If \( m = 0 \), \( f \) is constant.
1Step 1: Understanding the Problem
We are given an entire function \( f(z) \) that is bounded by a polynomial behavior as \( |z| \) becomes large. We need to prove that this function \( f(z) \) must itself be a polynomial.
2Step 2: Applying Liouville's Theorem
Liouville's theorem states that any bounded entire function must be constant. Here, \( f(z) \) is not bounded in the entire plane, but its growth is restricted by \( |f(z)| \leq M|z|^m \) for large \( |z| \). This suggests \( f \) does not grow too rapidly.
3Step 3: Use of Polynomial Growth Condition
The given condition implies that for large \( |z| \), the function \( f(z) \) behaves like a polynomial of degree \( m \) or less. This provides a restraint on the maximum power a term in the polynomial expansion of \( f(z) \) can have.
4Step 4: Considering the Entire Function Nature
Because \( f(z) \) is entire, it can be expressed as a power series that converges on the entire complex plane: \( f(z) = \sum_{n=0}^{abla} a_n z^n \). The growth condition implies that all coefficients \( a_n \) for \( n > m \) must be zero.
5Step 5: Applying the Maximum Modulus Principle
The maximum modulus principle for entire functions indicates \( f(z) \) should achieve its maximum at some boundary if it is not a constant. The growth constraint given aligns with such polynomial behavior.
6Step 6: Conclusion
Since \( |f(z)| \leq M|z|^m \) and increasing powers must be zero, \( f(z) \) simplifies to a polynomial of degree \( \leq m \). For \( m = 0 \), this indicates \( f(z) \) is a constant function because the highest degree of a polynomial is zero.
Key Concepts
Entire FunctionPolynomial GrowthMaximum Modulus Principle
Entire Function
An entire function, in the realm of complex analysis, is a function that is holomorphic, meaning that it is differentiable at every point on the complex plane. Differentiability in this context involves not just being able to take a derivative, but that the derivative itself must be continuous. Therefore, entire functions can be expressed as a power series that converges throughout the complex plane:
- They are infinitely differentiable everywhere on \( \mathbb{C}\).
- They can be represented by a Taylor series around any point in the complex plane.
Polynomial Growth
Polynomial growth refers to a situation where the magnitude of a function grows at a rate no faster than a polynomial with respect to its input at infinity. In the exercise, this growth is constrained by the inequality \(|f(z)| \leq M|z|^m\). This inequality suggests that for large values of \(|z|\), the function \(f(z)\) behaves like a polynomial of degree \(m\). This provides important insight into the behavior of the function:
- The coefficients for powers higher than \(m\) in its series expansion need to be zero.
- The said behavior prevents rapid, uncontrolled growth typically associated with non-polynomial functions like exponentials or logs for these inputs.
Maximum Modulus Principle
The maximum modulus principle is a pivotal concept in complex analysis applied to entire functions. The principle states that if an entire function achieves its maximum absolute value in any point in an open subset of its domain, under some conditions, that function must be constant. For the function \(f(z)\) we've been analyzing, even though not completely bounded in the classical sense, the given growth condition lays groundwork for applying this principle effectively:
- It dictates where on the boundary or at what point the maximum size (modulus) can occur.
- Combining this idea with polynomial growth, it suggests that the nature of polynomial constraints prevents \(f(z)\) from growing beyond the imposed behavior.
Other exercises in this chapter
Problem 15
Let \(f\) be an analytic function on an open set containing the closed disk \(\bar{U}_{r}(a)\). We assume \(|f(a)|
View solution Problem 15
Show: $$ \int_{0}^{\infty} \frac{\log ^{2} x}{1+x^{2}} d x=\frac{\pi^{3}}{8}, \quad \int_{0}^{\infty} \frac{\log x}{1+x^{2}} d x=0. $$
View solution Problem 16
Show: $$ \int_{0}^{\infty} \frac{x \sin x}{x^{2}+1} d x=\frac{\pi}{2 e} . $$
View solution Problem 17
Find all entire functions \(f\) with \(f(f(z))=z\) and \(f(0)=0\).
View solution