Problem 16
Question
\(\left|z_{1}+z_{2}\right|=\left|z_{1}\right|+\left|z_{2}\right|\) is possible if (A) \(z_{2}=\bar{z}_{1}\) (B) \(z_{2}=\frac{1}{z_{1}}\) (C) \(\arg z_{1}=\arg z_{2}\) (D) \(\left|z_{1}\right|=\left|z_{2}\right|\)
Step-by-Step Solution
Verified Answer
Option C: \(\arg z_1 = \arg z_2\) ensures the equality holds.
1Step 1: Recognize the Formula of Equality
The given equation \(\left|z_{1}+z_{2}\right|=\left|z_{1}\right|+\left|z_{2}\right|\) indicates that the magnitudes or moduli of the complex numbers \(z_1\) and \(z_2\) add up linearly. This is true if and only if the two complex numbers are non-negative real multiples of each other, meaning they are on the same line through the origin in the complex plane.
2Step 2: Analyze Each Option
Review each option to determine which one meets the condition that the real parts of \(z_1\) and \(z_2\) are proportional and in the same direction:- **Option A**: \(z_2 = \bar{z_1}\) could potentially make \(z_1\) and \(z_2\) directions opposite unless purely real.- **Option B**: \(z_2 = \frac{1}{z_1}\) might not ensure real number multiplication as \(z_1\) and \(\frac{1}{z_1}\) would typically not be linearly related.- **Option C**: \(\arg z_{1} = \arg z_{2}\) implies the arguments are equal, thus showing they are in the same direction.- **Option D**: \(|z_1| = |z_2|\) indicates equal lengths, but does not assure directionality.
3Step 3: Select the Correct Option
Option C, \(\arg z_{1} = \arg z_{2}\), ensures both the direction and proportionality necessary for \( \left|z_{1}+z_{2}\right|=\left|z_{1}\right|+\left|z_{2}\right| \). This holds true as two vectors being in the same direction implies they are positively scaled, which meets the condition required by the triangle inequality condition being an equality.
Key Concepts
Complex PlaneMagnitude EqualityTriangle Inequality
Complex Plane
The complex plane is a fundamental concept in mathematics, particularly when dealing with complex numbers. Imagine a regular graph with an x-axis and y-axis, but instead, you're plotting complex numbers. Here, the x-axis represents the real part of the complex number, while the y-axis represents the imaginary part. This way of representing complex numbers allows us to see them as points or vectors in a two-dimensional plane.
A complex number such as \( z = a + bi \) can be plotted, with \( a \) as the horizontal component and \( b \) as the vertical component.
A complex number such as \( z = a + bi \) can be plotted, with \( a \) as the horizontal component and \( b \) as the vertical component.
- The distance from the origin to the point representing the complex number is called the magnitude.
- The angle from the positive x-axis to the line connecting the origin to the point is called the argument.
Magnitude Equality
Magnitude equality in the context of complex numbers refers to a situation where two complex numbers have the same length or distance from the origin. The magnitude (or modulus) of a complex number \( z = a + bi \) is calculated using the formula \( |z| = \sqrt{a^2 + b^2} \).
For the equality \( \left|z_1+z_2\right| = \left|z_1\right| + \left|z_2\right| \) to hold true, specific conditions must be met. This relation means that the magnitudes add up linearly, which is a special case of the triangle inequality.
For the equality \( \left|z_1+z_2\right| = \left|z_1\right| + \left|z_2\right| \) to hold true, specific conditions must be met. This relation means that the magnitudes add up linearly, which is a special case of the triangle inequality.
- This equality occurs only if the complex numbers \( z_1 \) and \( z_2 \) align in the same direction.
- Essentially, they should be non-negative real multiples of one another.
Triangle Inequality
The triangle inequality is a crucial geometric concept that holds true in any metric space, including the complex plane. In simple terms, it states that the length of the sum of two sides of a triangle is always greater than or equal to the length of the third side. For complex numbers, this is mathematically expressed as:
- \( \left|z_1 + z_2\right| \leq \left|z_1\right| + \left|z_2\right| \)
- The inequality becomes an equality if and only if \( z_1 \) and \( z_2 \) are in the same direction (i.e., aligned).
- Think of the triangle as being reduced to a straight line where the two vectors are added without any angular deviation.
Other exercises in this chapter
Problem 14
If \(\frac{2 z_{1}}{3 z_{2}}\) is purely imaginary number, then \(\left|\frac{z_{1}-z_{2}}{z_{1}+z_{2}}\right|^{4}\) is equal to (A) \(\frac{3}{2}\) (B) 1 (C) \
View solution Problem 15
If \(x^{6}=(4-3 i)^{5}\), then the product of all of its roots is (where \(\left.\theta=-\tan ^{-1}(3 / 4)\right)\) (A) \(5^{5}(\cos 5 \theta+i \sin 5 \theta)\)
View solution Problem 17
If \(z=x+i y, x, y\) real, then \(|x|+|y| \leq k|z|\), where \(k\) is equal to (A) 1 (B) \(\sqrt{2}\) (C) \(\sqrt{3}\) (D) None of these
View solution Problem 18
If \((1+i)(1+2 i)(1+3 i) \ldots(1+n i)=\alpha+i \beta\) then \(2 \times 5\) \(\times 10 \ldots\left(1+n^{2}\right)=\) (A) \(\alpha-i \beta\) (B) \(\alpha^{2}-\b
View solution