Problem 16
Question
Jupiter's moon Io has active volcanoes (in fact, it is the most volcanically active body in the solar system) that eject material as high as 500 km (or even higher) above the surface. Io has a mass of 8.93 \(\times\) 10\(^{22}\) kg and a radius of 1821 km. For this calculation, ignore any variation in gravity over the 500-km range of the debris. How high would this material go on earth if it were ejected with the same speed as on Io?
Step-by-Step Solution
Verified Answer
The material would reach approximately 91.6 km on Earth.
1Step 1: Calculate Escape Velocity on Io
The escape velocity on a celestial body can be calculated using the formula \( v = \sqrt{2g_i h} \), where \( g_i \) is the acceleration due to gravity on Io, and \( h \) is the maximum height reached by the material, which is 500 km. First, we need to calculate \( g_i \) using \( g_i = \frac{G M_i}{R_i^2} \). Given \( G = 6.674 \times 10^{-11} \text{ N m}^2/\text{kg}^2 \), \( M_i = 8.93 \times 10^{22} \text{ kg} \), and \( R_i = 1821 \text{ km} = 1.821 \times 10^6 \text{ m} \), we have:\[ g_i = \frac{6.674 \times 10^{-11} \cdot 8.93 \times 10^{22}}{(1.821 \times 10^6)^2} = 1.796 \text{ m/s}^2 \]
2Step 2: Calculate Initial Speed on Io
To find the initial speed \( v_i \) on Io, use the formula \( v_i = \sqrt{2g_i h} \). Substituting, we get:\[ v_i = \sqrt{2 \cdot 1.796 \cdot 500,000} = \sqrt{1,796,000} \approx 1341 \text{ m/s} \]
3Step 3: Calculate Maximum Height on Earth
On Earth, the same initial speed \( v_i \) would propel the debris to a different height due to Earth's stronger gravity. Use the formula \( h_e = \frac{v_i^2}{2g_e} \), where \( g_e = 9.81 \text{ m/s}^2 \). Calculate \( h_e \):\[ h_e = \frac{1341^2}{2 \cdot 9.81} = \frac{1797481}{19.62} \approx 91590 \text{ m} = 91.6 \text{ km} \]
Key Concepts
Gravity on IoInitial Speed CalculationMaximum Height Calculation on Earth
Gravity on Io
Io, one of Jupiter's moons, is known for its intense volcanic activity. This activity can cause materials to be ejected high above its surface. Understanding gravity on Io is crucial for calculating the maximum height materials can reach. To determine the gravity on Io (\( g_i \),), you can employ the gravitational formula:
- \( g_i = \frac{GM_i}{R_i^2} \)
- \( G \) is the gravitational constant \((6.674 \times 10^{-11} \, \text{N m}^2/\text{kg}^2) \)
- \( M_i \) is Io's mass \((8.93 \times 10^{22} \, \text{kg}) \)
- \( R_i \) is Io's radius \((1.821 \times 10^6 \, \text{m}) \)
Initial Speed Calculation
To understand how far materials ejected from Io can travel, it's imperative to calculate the initial speed. This is done using the formula:
- \( v_i = \sqrt{2g_ih} \)
- \( g_i \) is Io's gravity \( (1.796 \, \text{m/s}^2) \)
- \( h \) is the maximum ejected height \((500 \, \text{km} = 500,000 \, \text{m}) \)
Maximum Height Calculation on Earth
Once the initial speed is known, it's insightful to predict how high the debris would reach on Earth due to differences in gravitational strength. Earth's stronger gravity \(( g_e = 9.81 \, \text{m/s}^2)\) affects the maximum height the same speed can achieve. The formula used is:
- \( h_e = \frac{v_i^2}{2g_e} \)
Other exercises in this chapter
Problem 14
Rhea, one of Saturn's moons, has a radius of 764 km and an acceleration due to gravity of 0.265 m/s\(^2\) at its surface. Calculate its mass and average density
View solution Problem 15
Calculate the earth's gravity force on a 75-kg astronaut who is repairing the Hubble Space Telescope 600 km above the earth's surface, and then compare this val
View solution Problem 19
A planet orbiting a distant star has radius 3.24 \(\times\) 10\(^6\) m. The escape speed for an object launched from this planet's surface is 7.65 \(\times\) 10
View solution Problem 21
For a satellite to be in a circular orbit 890 km above the surface of the earth, (a) what orbital speed must it be given, and (b) what is the period of the orbi
View solution