Problem 16
Question
Indicate the principal type of solute-solvent interaction in each of the following solutions and rank the solutions from weakest to strongest solute- solvent interaction: (a) KCl in water, (b) \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\) in benzene \(\left(\mathrm{C}_{6} \mathrm{H}_{6}\right),\) (c) methanol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right)\) in water.
Step-by-Step Solution
Verified Answer
The principal type of solute-solvent interaction for each solution is:
(a) KCl in water: Ion-dipole interaction
(b) \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\) in benzene: London Dispersion Forces (LDFs)
(c) methanol in water: Hydrogen bonding
The solutions are ranked from weakest to strongest solute-solvent interaction as: \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\) in benzene (LDFs) < methanol in water (hydrogen bonding) < KCl in water (ion-dipole).
1Step 1: Identify the principal type of solute-solvent interaction for each solution
The three solutions given are:
(a) KCl in water
(b) \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\) in benzene \(\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)\)
(c) methanol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right)\) in water
For (a), KCl is an ionic compound and water is a polar solvent. The principal interaction in this case is ion-dipole interaction.
For (b), \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\) and benzene are nonpolar compounds, so the principal interaction in this case is London Dispersion Forces (LDFs).
For (c), methanol and water are both polar molecules, and both can form hydrogen bonds. Thus, the principal interaction in this case is hydrogen bonding.
2Step 2: Rank the solutions based on solute-solvent interaction strength
We have three types of interactions in the given solutions:
1. Ion-Dipole interaction (KCl in water)
2. London Dispersion Forces (LDFs) (\(\mathrm{CH}_{2} \mathrm{Cl}_{2}\) in benzene)
3. Hydrogen Bonding (methanol in water)
In general, hydrogen bonding is stronger than dipole-dipole interactions, and dipole-dipole interactions are stronger than London Dispersion Forces. Ion-dipole interactions are even stronger than hydrogen bonds. So, we can rank them as follows:
Weakest interaction: \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\) in benzene (LDFs)
Middle-strength interaction: methanol in water (hydrogen bonding)
Strongest interaction: KCl in water (ion-dipole)
Thus, the solutions are ranked from weakest to strongest solute-solvent interaction as: \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\) in benzene < methanol in water < KCl in water.
Key Concepts
Ion-Dipole InteractionsLondon Dispersion ForcesHydrogen Bonding
Ion-Dipole Interactions
Ion-dipole interactions are strong forces that occur between an ion and a polar molecule. These interactions are a key concept in understanding how ionic compounds dissolve in polar solvents, like water.
When an ionic compound such as potassium chloride (KCl) is added to water, the positive ends of the water molecules are attracted to the chloride ions (Cl⁻), while the negative ends are attracted to the potassium ions (K⁺).
When an ionic compound such as potassium chloride (KCl) is added to water, the positive ends of the water molecules are attracted to the chloride ions (Cl⁻), while the negative ends are attracted to the potassium ions (K⁺).
- This orientation creates a strong association because water, a polar molecule, has a permanent dipole due to its hydrogen and oxygen atoms.
- The strength of ion-dipole interactions depends on the charge density of the ion and the polarity of the solvent molecule.
London Dispersion Forces
London Dispersion Forces (LDFs) are the weakest type of intermolecular forces. Despite being weak, they are universal and act between all atoms and molecules, regardless of their polarity.
In solutions like dichloromethane (\(\mathrm{CH}_{2} \mathrm{Cl}_{2}\)) in benzene, LDFs are the primary source of interaction.
In solutions like dichloromethane (\(\mathrm{CH}_{2} \mathrm{Cl}_{2}\)) in benzene, LDFs are the primary source of interaction.
- LDFs occur because electrons in atoms are constantly moving, creating temporary dipoles that induce dipoles in neighboring atoms or molecules.
- The strength of these forces increases with larger and more massive atoms or molecules due to their increased polarizability.
Hydrogen Bonding
Hydrogen bonding is a special type of dipole-dipole attraction that occurs when hydrogen is bonded to a highly electronegative atom, such as oxygen, nitrogen, or fluorine. This creates a strong dipole due to the large difference in electronegativities of the hydrogen and its bonded partner.
In a solution like methanol (\(\mathrm{CH}_{3} \mathrm{OH}\)) in water, hydrogen bonds form between the hydrogen of methanol and the oxygen of water molecules.
In a solution like methanol (\(\mathrm{CH}_{3} \mathrm{OH}\)) in water, hydrogen bonds form between the hydrogen of methanol and the oxygen of water molecules.
- Hydrogen bonds are significantly stronger than other dipole-dipole interactions, making them critical in biological systems and many chemical properties.
- This interaction contributes to the high boiling point and solubility of substances like water and alcohols.
Other exercises in this chapter
Problem 14
Indicate whether each statement is true or false: (a) NaCl dissolves in water but not in benzene \(\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)\) because benzene
View solution Problem 15
Indicate the type of solute-solvent interaction (Section 11.2\()\) that should be most important in each of the following solutions: (a) \(\mathrm{CCl}_{4}\) in
View solution Problem 17
An ionic compound has a very negative \(\Delta H_{\text { soln in water. }}\) (a) Would you expect it to be very soluble or nearly insoluble in water? (b) Which
View solution Problem 18
When ammonium chloride dissolves in water, the solution becomes colder. (a) Is the solution process exothermic or endothermic? (b) Why does the solution form?
View solution