Problem 16
Question
In this exercise we derive a kind of Jensen inequality for the minimum. a. Let \(a\) and \(b\) be real numbers. Show that $$ \min \\{a, b\\}=\frac{1}{2}(a+b-|a-b|) . $$ b. Let \(X\) and \(Y\) be independent random variables with the same distribution and finite expectation. Deduce from a that $$ \mathrm{E}[\min \\{X, Y\\}]=\mathrm{E}[X]-\frac{1}{2} \mathrm{E}[|X-Y|] $$ c. Show that $$ \mathrm{E}[\min \\{X, Y\\}] \leq \min \\{\mathrm{E}[X], \mathrm{E}[Y]\\} $$ Remark: this is not so interesting, since \(\min \\{\mathrm{E}[X], \mathrm{E}[Y]\\}=\mathrm{E}[X]=\mathrm{E}[Y]\), but we will see in the exercises of Chapter 11 that this inequality is also true for \(X\) and \(Y\), which do not have the same distribution.
Step-by-Step Solution
Verified Answer
Jensen's inequality for minima is derived through expressing minimum of values using an absolute difference, and expectation properties.
E[\min{X,Y}] = E[X] - 0.5E[|X-Y|], which adheres to E[\min{X,Y}] \leq \min{E[X],E[Y]}. E[X] = E[Y] by assumption here.
1Step 1: Expression for Minimum of Two Numbers
To show that \( \min \{a, b\} = \frac{1}{2}(a+b-|a-b|) \), we start by considering the definition of minimum. If \(a \leq b\), then \(\min\{a, b\} = a\), and if \(b < a\), then \(\min\{a, b\} = b\). To express the minimum in a single formula, note that \(|a-b| = a-b\) when \(a \geq b\) and \(|a-b| = b-a\) when \(a < b\). Substitute \(|a-b|\) accordingly into the expression \(\frac{1}{2}(a+b-|a-b|)\):- If \(a \geq b\), we have: \(\frac{1}{2}(a+b-(a-b)) = \frac{1}{2}(2b) = b\).- If \(a < b\), we have: \(\frac{1}{2}(a+b-(b-a)) = \frac{1}{2}(2a) = a\).In both cases, \(\frac{1}{2}(a+b-|a-b|)\) gives the result of \(\min\{a, b\}\).
2Step 2: Apply to Independent Random Variables
Given that \(X\) and \(Y\) are independent random variables with the same distribution and finite expectation, use the result from part a: \(\min\{X, Y\} = \frac{1}{2}(X+Y-|X-Y|)\). Take the expectation of both sides:\[ \mathrm{E}[\min \{X, Y\}] = \mathrm{E}\left[\frac{1}{2}(X+Y-|X-Y|)\right] \].Using linearity of expectation:\[ \mathrm{E}[\min \{X, Y\}] = \frac{1}{2}(\mathrm{E}[X] + \mathrm{E}[Y] - \mathrm{E}[|X-Y|]) \].Since \(X\) and \(Y\) have the same distribution, \(\mathrm{E}[X] = \mathrm{E}[Y]\), thus:\[ \mathrm{E}[\min \{X, Y\}] = \mathrm{E}[X] - \frac{1}{2} \mathrm{E}[|X-Y|] \].
3Step 3: Derive Jensen Inequality for Minima
Using the result from Step 2, \( \mathrm{E}[\min \{X, Y\}] = \mathrm{E}[X] - \frac{1}{2} \mathrm{E}[|X-Y|] \), we need to show that this is \(\leq \min \{\mathrm{E}[X], \mathrm{E}[Y]\}\). Since \(\mathrm{E}[X] = \mathrm{E}[Y]\) by assumption, this inequality simplifies to:\[ \mathrm{E}[\min \{X, Y\}] \leq \mathrm{E}[X] \].The term \(\frac{1}{2} \mathrm{E}[|X-Y|]\) is non-negative, as expectation of absolute values is always non-negative, fulfilling the Jensen Inequality for Minima under given conditions.
Key Concepts
Expectation of Random VariablesIndependent Random VariablesAbsolute Value Function
Expectation of Random Variables
The expectation of a random variable is a fundamental concept in probability and statistics. It is often associated with the 'average' or 'mean' value that a random variable can assume. When we are dealing with a random variable, which essentially is a mathematical object representing uncertainty, the expectation gives us a single number that characterizes its central tendency.
Let's consider a random variable, denoted as \(X\). The expectation of this random variable, denoted as \(\mathrm{E}[X]\), is calculated based on the probability distribution of \(X\). If \(X\) is a discrete random variable, the expectation is computed as:
Let's consider a random variable, denoted as \(X\). The expectation of this random variable, denoted as \(\mathrm{E}[X]\), is calculated based on the probability distribution of \(X\). If \(X\) is a discrete random variable, the expectation is computed as:
- \(\mathrm{E}[X] = \sum x_i P(X = x_i)\), where \(x_i\) are the possible values of \(X\) and \(P(X = x_i)\) is the probability of \(X\) taking the value \(x_i\).
- \(\mathrm{E}[X] = \int x f(x) dx\), where \(f(x)\) is the probability density function of \(X\).
Independent Random Variables
Independent random variables play a crucial role in statistical analysis. Two random variables, \(X\) and \(Y\), are said to be independent if the occurrence of one does not affect the probability of the occurrence of the other. This means that whatever happens with one variable does not sway our expectations or probabilities regarding the other.
Mathematically, this independence is expressed as:
Mathematically, this independence is expressed as:
- \(P(X = x, Y = y) = P(X = x) \cdot P(Y = y)\) for all possible values \(x\) and \(y\).
- \(\mathrm{E}[X + Y] = \mathrm{E}[X] + \mathrm{E}[Y]\)
Absolute Value Function
The absolute value function is a simple yet powerful mathematical tool. When dealing with inequalities and expectations, especially in the context of random variables, the absolute value can quantify the magnitude of deviations or distances without regard to direction.
The absolute value of a number \(a\) is denoted as \(|a|\) and is defined as:
This absolute difference is crucial in deriving certain inequalities, such as the modified Jensen's Inequality for minimum, where the expectation of this absolute value acts almost like a 'penalty' or adjustment to the general expectation, revealing fine insights into stochastic relationships between variables. Understanding and employing the absolute value function, therefore, is key to manipulating and interpreting these probabilistic expressions accurately.
The absolute value of a number \(a\) is denoted as \(|a|\) and is defined as:
- \(|a| = a \) if \(a \geq 0\)
- \(|a| = -a \) if \(a < 0\)
This absolute difference is crucial in deriving certain inequalities, such as the modified Jensen's Inequality for minimum, where the expectation of this absolute value acts almost like a 'penalty' or adjustment to the general expectation, revealing fine insights into stochastic relationships between variables. Understanding and employing the absolute value function, therefore, is key to manipulating and interpreting these probabilistic expressions accurately.
Other exercises in this chapter
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