Problem 16
Question
In Problems, find symmetric equations for the line through the given points. $$ (-5,-2,-4),(1,1,2) $$
Step-by-Step Solution
Verified Answer
Symmetric equation: \(\frac{x+5}{6} = \frac{y+2}{3} = \frac{z+4}{6}.\)
1Step 1: Identify Points
We are given two points in space: Point 1: \((-5, -2, -4)\) Point 2: \((1, 1, 2)\). We need to find the symmetric equation of the line that passes through these two points.
2Step 2: Find the Direction Vector
To find the direction vector, subtract the coordinates of the first point from the corresponding coordinates of the second point: \( \vec{d} = (1 - (-5), 1 - (-2), 2 - (-4)) = (6, 3, 6) \).
3Step 3: Write Parametric Equations
Using one point, say \((-5, -2, -4)\), and the direction vector \((6, 3, 6)\), write the parametric equations of the line:\[ x = -5 + 6t, \]\[ y = -2 + 3t, \]\[ z = -4 + 6t, \]where \(t\) is a parameter.
4Step 4: Write Symmetric Equations
Transform the parametric equations into symmetric form:Equate each parametric equation to the common parameter \(t\):\[ t = \frac{x + 5}{6} = \frac{y + 2}{3} = \frac{z + 4}{6}. \]These are the symmetric equations of the line through the points.
Key Concepts
Direction VectorParametric EquationsPoints in Space
Direction Vector
Understanding the concept of a direction vector is fundamental when dealing with lines in space. A direction vector provides a way to describe the direction and orientation of a line. It is essentially a vector that points from one point to another along the line. In our example, the direction vector was calculated using two given points,
• Point 1: (-5, -2, -4)
• Point 2: (1, 1, 2)
To find the direction vector, subtract the coordinates of the first point from the corresponding coordinates of the second point:\[\vec{d} = (1 - (-5), 1 - (-2), 2 - (-4)) = (6, 3, 6).\]This resulting vector (6, 3, 6) provides the orientation of the line. The direction vector is crucial not only in defining a line but also in constructing both parametric and symmetric equations. Without it, we wouldn’t know how the line stretches through space.
• Point 1: (-5, -2, -4)
• Point 2: (1, 1, 2)
To find the direction vector, subtract the coordinates of the first point from the corresponding coordinates of the second point:\[\vec{d} = (1 - (-5), 1 - (-2), 2 - (-4)) = (6, 3, 6).\]This resulting vector (6, 3, 6) provides the orientation of the line. The direction vector is crucial not only in defining a line but also in constructing both parametric and symmetric equations. Without it, we wouldn’t know how the line stretches through space.
Parametric Equations
Parametric equations are a set of equations that express the coordinates of the points on a geometric object as functions of a single parameter. This is particularly useful in three-dimensional space, as it allows us to track all points along a line efficiently.
In our case, the parameter trepresents how far along the line we are from a starting point. Using the point (-5, -2, -4) and the direction vector (6, 3, 6),we write the parametric equations for the line:
In our case, the parameter trepresents how far along the line we are from a starting point. Using the point (-5, -2, -4) and the direction vector (6, 3, 6),we write the parametric equations for the line:
- \(x = -5 + 6t\)
- \(y = -2 + 3t\)
- \(z = -4 + 6t\)
Points in Space
Points in space are fundamental elements in geometry, especially when it comes to understanding lines and other geometric shapes. In three-dimensional space, each point is defined by three coordinates, \(x, y, \)and \(z\),that tell us the position relative to an origin. In the original exercise provided, we started with two points:
- Point 1: (-5, -2, -4)
- Point 2: (1, 1, 2)
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