Problem 16
Question
In Exercises \(15-22,\) find the indicated term of the arithmetic sequence with first term, \(a_{1},\) and common difference, \(d\) Find \(a_{16}\) when \(a_{1}=9, d=2\)
Step-by-Step Solution
Verified Answer
The 16th term of the arithmetic sequence is 39.
1Step 1: Substitute the values into the formula
Put the given values into the formula \(a_{n} = a_{1} + (n-1)d\). Here, \(a_{1} = 9\), \(d = 2\) and \(n = 16\). So we get \(a_{16} = 9 + (16-1)2\).
2Step 2: Solve the equation
Now perform the operations. This gives \(a_{16} = 9 + 15 \times 2\).
3Step 3: Calculate the final value
Finally after performing the multiplication and addition, you get \(a_{16} = 39\).
Key Concepts
Common Difference in Arithmetic SequencesThe First Term of an Arithmetic SequenceUsing the Arithmetic Sequence Formula
Common Difference in Arithmetic Sequences
In arithmetic sequences, the **common difference** refers to the consistent amount that separates consecutive terms. This difference is key to ensuring that each term in the sequence follows a predictable pattern. For example, in the problem provided, we have a common difference, denoted by the symbol \(d\), which equals 2. This means that every term in the sequence increases by 2 units from the previous term.
This concept can be identified by:
This concept can be identified by:
- Subtracting any term from the following term within the sequence.
- Knowing the first term and the common difference allows us to determine each subsequent term.
The First Term of an Arithmetic Sequence
The **first term** of an arithmetic sequence is often represented by \(a_1\) and serves as the starting point for the sequence. It is the value from which all other terms in the sequence are derived based on the common difference. In the exercise example, the first term, \(a_1\), is given as 9.
Here's how it functions:
Here's how it functions:
- The first term sets the sequence's initial position.
- All subsequent terms are built upon the value of this first term plus increments of the common difference.
Using the Arithmetic Sequence Formula
The **arithmetic sequence formula** is a simple yet powerful tool to calculate any term in the sequence by applying a straightforward calculation. The general formula for finding the \(n\)-th term of an arithmetic sequence is \(a_n = a_1 + (n-1)d\), where \(a_1\) is the first term, \(d\) represents the common difference, and \(n\) is the term number you need to find. For the exercise, substituting the values \(a_1 = 9\), \(d = 2\), and \(n = 16\), simplifies the formula to \(a_{16} = 9 + (16-1) \, 2\).
This formula allows for:
This formula allows for:
- Efficient calculation of any term without listing all previous terms.
- Identifying patterns within the sequence by analyzing term positions and values.
Other exercises in this chapter
Problem 16
In Exercises 9-30, use the Binomial Theorem to expand each binomial and express the result in simplified form. $$(3 x+1)^{4}$$
View solution Problem 16
In Exercises 11-24, use mathematical induction to prove that each statement is true for every positive integer \(n.\) $$2+7+12+\dots+(5 n-3)=\frac{n(5 n-1)}{2}$
View solution Problem 16
Use the formula for the general term (the nth term) of a geometric sequence to find the indicated term of each sequence with the given first term, a1, and commo
View solution Problem 17
You are dealt one card from a standard 52-card deck. Find the probability of being dealt a queen.
View solution