Problem 16
Question
In Exercises \(13-22,\) one term and the common ratio r of a geometric sequence are given. Find the sixth term and a formula for the nth term. $$a_{1}=-6, r=\frac{2}{3}$$
Step-by-Step Solution
Verified Answer
Answer: The sixth term of the geometric sequence is -192/243, and the general formula for the nth term is \(a_n = -6 (\frac{2}{3})^{(n-1)}\).
1Step 1: Identify the given values
The first term \(a_1\) is given as \(-6\), and the common ratio \(r\) is given as \(\frac{2}{3}\).
2Step 2: Find the sixth term using the formula
To find the sixth term, \(a_6\), we need to use the formula \(a_n = a_1 \cdot r^{(n-1)}\) and substitute \(n=6\), \(a_1 = -6\), and \(r = \frac{2}{3}\):
\(a_6 = -6 (\frac{2}{3})^{(6-1)} = -6 (\frac{2}{3})^{5}\)
Now, calculate the value of \(a_6\):
\(a_6 = -6 (\frac{2^5}{3^5}) = -6 (\frac{32}{243}) = -\frac{192}{243}\)
So, the sixth term, \(a_6\), is \(-\frac{192}{243}\).
3Step 3: Find the formula for the nth term
Now we can write the formula for the nth term, \(a_n\), using the given values of \(a_1\) and \(r\):
\(a_n = -6 (\frac{2}{3})^{(n-1)}\)
So, the general formula for the nth term of the geometric sequence is \(a_n = -6 (\frac{2}{3})^{(n-1)}\).
Key Concepts
nth term formulacommon ratiosequence term calculation
nth term formula
In the realm of geometric sequences, finding the nth term is a fundamental skill. A geometric sequence is an ordered list of numbers in which each term after the first is found by multiplying the previous term by a certain number, called the common ratio. To express this relationship in mathematical terms, we use the nth term formula:
- The formula is: \(a_n = a_1 \cdot r^{(n-1)}\)
- Here, \(a_n\) represents the nth term you're trying to find.
- \(a_1\) is the first term of the sequence.
- \(r\) is the common ratio.
- \(n\) is the term number of the sequence you're looking for.
common ratio
The common ratio in a geometric sequence is a pivotal concept. It is the fixed number that you multiply each term by to get to the next term. It defines the pattern and progression of the sequence. Here's how it works:
- The common ratio, denoted as \(r\), remains constant throughout the sequence.
- If \(r > 1\), each term will be larger than the previous one; the sequence is increasing.
- If \(0 < r < 1\), each term will be smaller than the previous one; the sequence is decreasing.
- If \(r = 1\), all terms in the sequence are the same.
- If \(r < 0\), terms will alternate between positive and negative.
sequence term calculation
To calculate a specific term in a geometric sequence, you'll use the nth term formula, as we've explored. Let's break it down further with an example calculation:
- You start with the formula: \(a_n = a_1 \cdot r^{(n-1)}\)
- Suppose you know that \(a_1 = -6\) and the common ratio \(r = \frac{2}{3}\).
- To find the 6th term (as requested in an exercise), substitute \(n = 6\) into the formula.
- That gives you: \(a_6 = -6 \cdot \left(\frac{2}{3}\right)^{5}\)
- Calculate \(\left(\frac{2}{3}\right)^5\), which is \(\frac{32}{243}\).
- Then multiply: \(-6 \times \frac{32}{243} = -\frac{192}{243}\).
Other exercises in this chapter
Problem 15
Write the first five terms of the sequence whose nth term is given. Use them to decide whether the sequence is arithmetic. If it is, list the common difference.
View solution Problem 15
Find a formula for the nth term of the sequence whose first few terms are given. $$-1,1,-1,1,-1,1, \ldots$$
View solution Problem 16
Use mathematical induction to prove that each of the given statements is true for every positive integer \(n .\) 5 is a factor of \(2^{4 n-2}+1\)
View solution Problem 16
Evaluate the expression. $$\left(\begin{array}{l}6 \\\0\end{array}\right)-\left(\begin{array}{l}6 \\\1\end{array}\right)+\left(\begin{array}{l}6 \\\2\end{array}
View solution