Problem 16
Question
In Exercises 11-18, find the standard form of the equation of the ellipse with the given characteristics and center at the origin. Foci: \((\pm2, 0); \quad\) major axis of length \(10\)
Step-by-Step Solution
Verified Answer
The standard form of the equation of the ellipse with the given characteristics and center at the origin is \(\frac{x^2}{25} + \frac{y^2}{21} = 1\).
1Step 1: Determine the Value for Semi-Major Axis length
Firstly, half the length of the major axis is the value of \(a\). In this case, the major axis has a length of \(10\), so the semi-major axis length will be \(a = \frac{10}{2} = 5\).
2Step 2: Determine the Value for \(c\) - distance from the center to each focus
The foci are given by the points \((\pm2, 0)\). The distance of focal points from the center represents \(c\). Thus, \(c = 2\).
3Step 3: Calculate the Value for Semi-Minor Axis Length
Now you can determine \(b\), the semi-minor axis length. The relationship between the variables \(a\), \(b\), and \(c\) is \(c^2 = a^2 - b^2\). Plugging in the known values, the formula is rearranged to solve for \(b^2\), giving \(b^2 = a^2 - c^2\), and by substituting the known values we get \(b = \sqrt{5^2 - 2^2} = \sqrt{21}\).
4Step 4: Write the Standard Form of Ellipse
With the values of \(a\) and \(b\) known, you can substitute these values into the standard form of an ellipse, \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\), giving the final equation as \(\frac{x^2}{25} + \frac{y^2}{21} = 1\).
Key Concepts
Standard Form of an EllipseSemi-Major Axis of an EllipseFoci of an EllipseSemi-Minor Axis of an Ellipse
Standard Form of an Ellipse
The standard form of an ellipse is a way of expressing its equation that makes it easier to understand and visualize. For an ellipse centered at the origin, the standard form is written as follows:
\[ \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \]
Where:
\[ \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \]
Where:
- \(a\) is the length of the semi-major axis.
- \(b\) is the length of the semi-minor axis.
Semi-Major Axis of an Ellipse
The semi-major axis of an ellipse is one of its most crucial elements. It represents half of the longest diameter of the ellipse. In our example, the total length of the major axis is given as \(10\).
To find the semi-major axis, simply halve this length:
\[ a = \frac{10}{2} = 5 \]
The semi-major axis runs from the center of the ellipse to a point on its longest perimeter, and it's labeled by \(a\).
Understanding the semi-major axis helps determine the ellipse's size and shape. When \(a\) is larger, your ellipse stretches wider along its major direction, defining the ellipse's overall orientation.
To find the semi-major axis, simply halve this length:
\[ a = \frac{10}{2} = 5 \]
The semi-major axis runs from the center of the ellipse to a point on its longest perimeter, and it's labeled by \(a\).
Understanding the semi-major axis helps determine the ellipse's size and shape. When \(a\) is larger, your ellipse stretches wider along its major direction, defining the ellipse's overall orientation.
Foci of an Ellipse
The foci of an ellipse are two special points located along its major axis. These points are crucial in the geometric definition of an ellipse, as they help dictate the shape and spread of it. For an ellipse centered at the origin, the foci's coordinates are given as \((\pm c, 0)\) when the major axis is horizontal.
In the given problem, the foci are \((\pm2, 0)\). Thus, the distance from the center to each focus is:
\[ c = 2 \]
The foci play an important role in ensuring that the total distance from any point on the ellipse to the two foci is constant. Understanding the foci is essential to grasping how ellipses behave geometrically. They help manage the `bending` of the ellipse beyond the center point.
In the given problem, the foci are \((\pm2, 0)\). Thus, the distance from the center to each focus is:
\[ c = 2 \]
The foci play an important role in ensuring that the total distance from any point on the ellipse to the two foci is constant. Understanding the foci is essential to grasping how ellipses behave geometrically. They help manage the `bending` of the ellipse beyond the center point.
Semi-Minor Axis of an Ellipse
The semi-minor axis is the half-length of the shortest diameter of an ellipse. Even though it is shorter than the semi-major axis, it is as significant for describing the ellipse's geometry. The semi-minor axis is perpendicular to the major axis and intersects at the ellipse's center.
To find it, recall the formula relating \(a\), \(b\), and \(c\) given by:
\[ c^2 = a^2 - b^2 \]
Plug in the known values to solve for \(b\):
\[ b^2 = 5^2 - 2^2 = 21 \]
\[ b = \sqrt{21} \]
This calculation shows how far the ellipse stretches in its minor direction. Like \(a\), \(b\) defines the ellipse's spread, but it's more about how 'tall' or 'short' the ellipse appears in its perpendicular span.
To find it, recall the formula relating \(a\), \(b\), and \(c\) given by:
\[ c^2 = a^2 - b^2 \]
Plug in the known values to solve for \(b\):
\[ b^2 = 5^2 - 2^2 = 21 \]
\[ b = \sqrt{21} \]
This calculation shows how far the ellipse stretches in its minor direction. Like \(a\), \(b\) defines the ellipse's spread, but it's more about how 'tall' or 'short' the ellipse appears in its perpendicular span.
Other exercises in this chapter
Problem 16
In Exercises 13-26, rotate the axes to eliminate the \(xy\)-term in the equation. Then write the equation in standard form. Sketch the graph of the resulting eq
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In Exercises 9-22, find the center, vertices, foci, and the equations of the asymptotes of the hyperbola, and sketch its graph using the asymptotes as an aid. \
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In Exercises 13-18, find the inclination \(\theta\) (in radians and degrees) of the line with a slope of \(m\). \(m = 2\)
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In Exercises 15-28, identify the conic and sketch its graph. \(r=\dfrac{5}{1+\sin\ \theta}\)
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