Problem 16
Question
In Exercises \(1-20\), plot the set of parametric equations by hand. Be sure to
indicate the orientation imparted on the curve by the parametrization.
$$
\left\\{\begin{array}{l}
x=\sec (t) \\
y=\tan (t)
\end{array} \text { for } \frac{\pi}{2}
Step-by-Step Solution
Verified Answer
Plot the curve with vertical asymptotes at \( x = \pm \infty \) and indicate leftwards orientation from \( t = \frac{\pi}{2} \) to \( t = \frac{3\pi}{2} \).
1Step 1: Understand the Parametric Equations
The parametric equations given are \( x = \sec(t) \) and \( y = \tan(t) \). The range for \( t \) is from \( \frac{\pi}{2} \) to \( \frac{3\pi}{2} \). These equations describe a curve in the Cartesian plane.
2Step 2: Analyze Behavior of Secant and Tangent
In the range given, \( \sec(t) = \frac{1}{\cos(t)} \) and \( \tan(t) = \frac{\sin(t)}{\cos(t)} \). Note that in this interval, \( \cos(t) \) goes from 0 to -1 and back to 0, so \( x = \sec(t) \) will have vertical asymptotes at the endpoints \( t = \frac{\pi}{2} \) and \( t = \frac{3\pi}{2} \). Meanwhile, \( y = \tan(t) \) will show increasing behavior from negative infinity to positive infinity over this interval.
3Step 3: Plot Key Points and Asymptotes
Identify key points and asymptotes in the interval: at \( t = \frac{\pi}{2} \), \( x \) and \( y \) are not defined; as \( t \) approaches \( \pi \), \( \cos(t) = -1 \) so \( x = -1 \) and \( y = 0 \). Finally, as \( t \) approaches \( \frac{3\pi}{2} \), \( x \) and \( y \) again approach infinity, and \( x \) becomes undefined due to the asymptote.
4Step 4: Draw the Curve
On a Cartesian plane, draw vertical dashed lines (asymptotes) at \( x = \infty \) and \( x = -\infty \). Start plotting from the lower range towards higher values, tracing the curve along these key points. The curve moves from right to left because \( x \) decreases as \( t \) goes from just above \( \frac{\pi}{2} \) to approach \( \frac{3\pi}{2} \).
5Step 5: Indicating the Orientation
Indicate the curve's orientation by drawing arrows on the curve. The arrows should point from larger values of \( x \) (positive infinity) to \( x = -1 \) at \( t = \pi \), continuing to \( x \) reaching negative infinity. This shows the direction of increasing \( t \).
Key Concepts
Secant FunctionTangent FunctionAsymptotesCurve Plotting
Secant Function
The secant function, denoted as \( \sec(t) \), is defined as the reciprocal of the cosine function: \( \sec(t) = \frac{1}{\cos(t)} \). This relationship means whenever the cosine function approaches zero, the secant function grows towards infinity. Consequently, the secant function has vertical asymptotes where \( \cos(t) = 0 \). These asymptotes appear at critical points such as \( t = \frac{\pi}{2} \) and \( t = \frac{3\pi}{2} \) for the interval given in the problem.
Important properties of the secant function to remember:
Important properties of the secant function to remember:
- Defined for all angles \( t \), except where \( \cos(t) = 0 \).
- As \( \cos(t) \) approaches zero, \( \sec(t) \) tends towards infinity.
- The function has periodic vertical asymptotes, aligning with the zeros of \( \cos(t) \).
Tangent Function
The tangent function, expressed as \( \tan(t) \), is defined by the ratio \( \tan(t) = \frac{\sin(t)}{\cos(t)} \). This definition leads to certain behaviors, particularly undefined points and asymptotic tendencies when \( \cos(t) = 0 \). The tangent function will exhibit vertical asymptotes at the points where \( \cos(t) = 0 \), similar to the secant function. However, the tangent function is bound to display unique characteristics in its behavior.
Key features of the tangent function include:
Key features of the tangent function include:
- The function is undefined at points where \( \sin(t) \) and \( \cos(t) \) are orthogonal (\( \cos(t) = 0 \)).
- As \( \cos(t) \) approaches zero from either direction, \( \tan(t) \) can increase or decrease towards infinity.
- The periodic pattern mirrors that of the sine and cosine functions, creating a cycle of undefined points and peaks.
Asymptotes
Asymptotes are lines that a graph approaches but never touches, serving an essential role in understanding the behavior of certain functions. In the context of the secant and tangent functions, vertical asymptotes occur in places where the denominator of a fraction in the function approaches zero. This causes the function value to increase or decrease without bounds. More specifically:
- Vertical asymptotes appear at \( x = \infty \) or \( x = -\infty \) when \( \cos(t) = 0 \) in both \( \sec(t) \) and \( \tan(t) \).
- Between these asymptotes, the function will change dramatically, forming essential landmarks for graph drawing.
Curve Plotting
Curve plotting with parametric equations involves visualizing a pair of equations simultaneously to form a pattern in the Cartesian plane. With parametric equations like \( x = \sec(t) \) and \( y = \tan(t) \), plotting requires understanding how each component evolves over a parameter \( t \).
The procedural steps for plotting such curves involve:
The procedural steps for plotting such curves involve:
- Calculate values for \( x \) and \( y \) over the specified range of \( t \).
- Identify key points where significant changes happen, such as the function going to infinity.
- Locate the asymptotes to understand where the graph will have interruptions.
- Trace the curve ensuring the orientation is respected, marking direction using arrows.
Other exercises in this chapter
Problem 15
Solve for the remaining side(s) and angle(s), if possible, using any appropriate technique. $$ \alpha=42^{\circ}, b=117, c=88 $$
View solution Problem 15
Plot the point given in polar coordinates and then give three different expressions for the point such that (a) \(r0\) and \(\theta \leq 0\) (c) \(r>0\) and \(\
View solution Problem 16
Find the component form of the vector \(\vec{v}\) using the information given about its magnitude and direction. Give exact values. \(\|\vec{v}\|=2 \sqrt{3} ;\)
View solution Problem 16
In Exercises \(1-20\), plot the graph of the polar equation by hand. Carefully label your graphs. Limaçon: \(r=3-5 \cos (\theta)\)
View solution