Problem 16
Question
In \(15-20,\) evaluate each logarithm to the nearest hundredth. $$ \ln 5+\ln 7 $$
Step-by-Step Solution
Verified Answer
The evaluated expression is approximately 3.56.
1Step 1: Apply Logarithm Product Rule
The expression given is \( \ln 5 + \ln 7 \). The product rule for logarithms states that \( \ln a + \ln b = \ln (a \cdot b) \). Therefore, apply the product rule: \( \ln 5 + \ln 7 = \ln (5 \cdot 7) \).
2Step 2: Compute the Product
Calculate the product inside the logarithm: \( 5 \times 7 = 35 \). Thus, the expression simplifies to \( \ln 35 \).
3Step 3: Evaluate the Natural Logarithm
Use a calculator to evaluate \( \ln 35 \) to the nearest hundredth. Upon calculation, \( \ln 35 \approx 3.56 \).
Key Concepts
Logarithm Product RuleNatural LogarithmEvaluating Logarithms
Logarithm Product Rule
Logarithms help us solve problems involving multiplication and division more easily. They do this by transforming those problems into addition and subtraction. One of the key tools in this transformation is the logarithm product rule.
The logarithm product rule states that the logarithm of a product is equal to the sum of the logarithms of its factors. Formally, this is expressed as
For example, if you have \( \ a = 5 \) and \( b = 7\), using this rule, you find
The logarithm product rule states that the logarithm of a product is equal to the sum of the logarithms of its factors. Formally, this is expressed as
- \( \ln a + \ln b = \ln (a \cdot b) \)
For example, if you have \( \ a = 5 \) and \( b = 7\), using this rule, you find
- \( \ \ \ \ \ \ \ \ \ln 5 + \ln 7 = \) \( \ln (5 \cdot 7) = \) \( \ln 35 \)
Natural Logarithm
Not all logarithms are created equal. The natural logarithm is special and quite common in mathematics, especially in calculus and exponential growth problems. A natural logarithm is a logarithm with base \(e\), where \(e\) is approximately \(2.71828\).
When evaluating expressions like \( \ln 5 \), you're working with natural logarithms, which are often abbreviated as \"ln\".
When evaluating expressions like \( \ln 5 \), you're working with natural logarithms, which are often abbreviated as \"ln\".
- These logarithms are tuned to the natural base \(e\) and are particularly useful for continuous growth processes, such as exponential growth or radioactive decay.
- The natural logarithm of any number represents the time needed to grow to that number with continuous compounding, starting from \(1\).
Evaluating Logarithms
Once you have a simplified expression using the product rule, like \( \ln 35 \), it's time to evaluate it.
This means finding its numerical value, usually with a calculator, especially when it's not a simple number. Calculators have built-in functions for natural logarithms, which makes evaluation easy.
This means finding its numerical value, usually with a calculator, especially when it's not a simple number. Calculators have built-in functions for natural logarithms, which makes evaluation easy.
- Enter the expression \( \ln 35 \) to get its approximate value.
- For this particular exercise, rounding it to the nearest hundredth gives you \( \ln 35 \approx 3.56 \).
Other exercises in this chapter
Problem 15
a. Write each expression as a single logarithm. b. Find the value of each expression. \(\log _{3} 1+\log _{3} 9\)
View solution Problem 15
In \(11-22,\) solve each equation for \(y\) in terms of \(x\) $$ x=(0.2)^{y} $$
View solution Problem 16
An investment of \(\$ 2,000\) receives 5\(\%\) interest annually. After how many years has the investment increased to at least \(\$ 2,500 ?\)
View solution Problem 16
Find \(x\) to the nearest hundredth. \(\log x+\log (x+2)=\log 3\)
View solution