Problem 16
Question
In \(11-22,\) solve each triangle, that is, find the measures of the remaining three parts of the triangle to the nearest integer or the nearest degree. In \(\triangle P Q R, p=12, \mathrm{m} \angle Q=80,\) and \(\mathrm{m} \angle R=30\)
Step-by-Step Solution
Verified Answer
Angle P is 70°, side q is approximately 13, and side r is approximately 6.
1Step 1: Identify Known and Unknown Elements
We know side \( p = 12 \), angle \( \angle Q = 80^\circ \), and angle \( \angle R = 30^\circ \). We need to find angle \( \angle P \), and the sides \( q \) and \( r \).
2Step 2: Find Angle P
Using the fact that the sum of the angles in a triangle is \( 180^\circ \), we calculate \( \angle P \) as follows: \[ \angle P = 180^\circ - \angle Q - \angle R = 180^\circ - 80^\circ - 30^\circ = 70^\circ \].
3Step 3: Apply Sine Law for Side q
Using the sine law: \[ \frac{q}{\sin Q} = \frac{p}{\sin P} \] gives \[ q = \frac{12 \times \sin 80^\circ}{\sin 70^\circ}. \] Calculate \( q \) using \( \sin(80^\circ) \approx 0.9848 \) and \( \sin(70^\circ) \approx 0.9397 \), thus \( q \approx \frac{12 \times 0.9848}{0.9397} \approx 12.58 \), and round to the nearest integer: \( q \approx 13 \).
4Step 4: Apply Sine Law for Side r
Similarly, applying the sine law for side \( r \): \[ \frac{r}{\sin R} = \frac{p}{\sin P} \] gives \[ r = \frac{12 \times \sin 30^\circ}{\sin 70^\circ}, \] where \( \sin(30^\circ) = 0.5 \). Calculate \( r \) as \( r \approx \frac{12 \times 0.5}{0.9397} \approx 6.39 \), and round to the nearest integer: \( r \approx 6 \).
Key Concepts
Triangle SolvingSine LawAngle Sum PropertyTriangle Sides Calculation
Triangle Solving
Solving a triangle means to find the missing parts of it, given certain known values. In our exercise, we have a triangle \(PQR\) with known side \(p\) and angles \(\angle Q\) and \(\angle R\). To solve this triangle, we must find the missing angle \(\angle P\) and the two sides \(q\) and \(r\). It's like playing detective with numbers and rules. We use given information and mathematical principles to uncover the unknown pieces of the puzzle. This process involves understanding and implementing key concepts such as the angle sum property and the sine law.
Sine Law
The Sine Law is a powerful tool that helps relate the sides and angles in a triangle. It's particularly useful when we have a combination of known angles and sides, like in our exercise. The Sine Law is given by the equation: \[ \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} \] This equation tells us that the ratio between the length of a side and the sine of its opposite angle is the same for each side of the triangle.
- For side \(q\), we use: \( \frac{q}{\sin Q} = \frac{p}{\sin P} \)
- For side \(r\), we use: \( \frac{r}{\sin R} = \frac{p}{\sin P} \)
Angle Sum Property
The Angle Sum Property is a fundamental rule for triangles that states the sum of a triangle's interior angles always equals \( 180^\circ \). This property is essential when we have two angles and need to find the third, as in our exercise for \(\angle P\). Here’s how it works in practice:
- Start with the equation: \( \angle P + \angle Q + \angle R = 180^\circ \)
- Knowing \(\angle Q = 80^\circ\) and \(\angle R = 30^\circ\), substitute these values into the equation.
- Solve for \(\angle P\): \[ \angle P = 180^\circ - 80^\circ - 30^\circ = 70^\circ \]
Triangle Sides Calculation
Calculating the sides of a triangle using known elements involves applying methods like the Sine Law when dealing with non-right triangles. In the given problem, once we determine all angles, we use the Sine Law to find the unknown sides.
- For side \(q\), calculate using: \[ q = \frac{12 \times \sin 80^\circ}{\sin 70^\circ} \] We approximate \(\sin 80^\circ \approx 0.9848\) and \(\sin 70^\circ \approx 0.9397\), leading to \(q \approx 13\) after rounding.
- For side \(r\), calculate using: \[ r = \frac{12 \times \sin 30^\circ}{\sin 70^\circ} \] With \(\sin 30^\circ = 0.5\), we find \(r \approx 6\) after rounding.
Other exercises in this chapter
Problem 15
In \(14-19,\) find, to the nearest tenth, the measure of the third side of each triangle. In \(\triangle P Q R, p=126, q=214,\) and \(\mathrm{m} \angle R=42\)
View solution Problem 15
The coordinates of a point are given. a. Find the distance of the point from the origin. Express approximate distances to the nearest hundredth. b. Find the mea
View solution Problem 16
The base of an isosceles triangle measures 14.5 centimeters and the vertex angle measures 110 degrees. a. Find the measure of one of the congruent sides of the
View solution Problem 16
In \(13-18,\) find, to the nearest degree, the measure of each angle of the triangle with the given measures of the sides. $$ 11,11,15 $$
View solution