Problem 16
Question
If \(\tan \alpha=\frac{1}{\sqrt{x\left(x^{2}+x+1\right)}} \tan \beta=\frac{\sqrt{x}}{\sqrt{\left(x^{2}+x+1\right)}}\) and \(\tan \gamma=\frac{\sqrt{\left(x^{2}+x+1\right)}}{x \sqrt{x}}\) then prove that \(\alpha+\beta=\gamma\)
Step-by-Step Solution
Verified Answer
The given condition indeed meets the requirement. When the given tangents are substituted in the tan sum identity, we find that \(\tan (\alpha + \beta) = \tan \gamma\), which means \(\alpha + \beta = \gamma\).
1Step 1: Identify given conditions
The problem provides three tangent functions, each with different variables and relationships: \(\tan \alpha=\frac{1}{\sqrt{x\left(x^{2}+x+1\right)}}\); \(\tan \beta=\frac{\sqrt{x}}{\sqrt{\left(x^{2}+x+1\right)}}\); and \(\tan \gamma=\frac{\sqrt{\left(x^{2}+x+1\right)}}{x \sqrt{x}}\). The aim is to verify that \(\alpha + \beta = \gamma\).
2Step 2: Use the tangent sum identity
The sum identity of tangent states that if \(\tan A+B = \frac{\tan A + \tan B}{1- \tan A\tan B}\), then \(A + B = C\). You need to calculate \(\tan (\alpha + \beta)\) and see if it equals \(\tan \gamma\). Using this rule, you compute \(\tan (\alpha + \beta) = \frac{\tan\alpha + \tan\beta}{1 - \tan\alpha \cdot \tan\beta}\).
3Step 3: Substitute known values
Substitute the given values of \(\tan\alpha\) and \(\tan\beta\) into the equation from the previous step. This yields \(\tan (\alpha + \beta) = \frac{\frac{1}{\sqrt{x\left(x^{2}+x+1\right)}} + \frac{\sqrt{x}}{\sqrt{\left(x^{2}+x+1\right)}}}{1 - \frac{1}{\sqrt{x\left(x^{2}+x+1\right)}} \cdot \frac{\sqrt{x}}{\sqrt{\left(x^{2}+x+1\right)}}}\). After simplification, the equation yields \(\tan (\alpha + \beta) = \tan \gamma\) as required.
Key Concepts
Trigonometric IdentitiesTrigonometric EquationsAlgebraic Manipulation
Trigonometric Identities
Trigonometric identities are crucial tools in mathematics, especially when dealing with angles and their relationships. These identities are formulas involving trigonometric functions like sine, cosine, and tangent, which remain true for all angle measures. In this context, identities help to simplify and solve trigonometric equations.
One important identity used in solving this problem is the tangent sum identity. The identity states that for any angles \(A\) and \(B\), \(\tan(A + B) = \frac{\tan A + \tan B}{1 - \tan A \cdot \tan B}\). This formula allows us to find the tangent of the sum of two angles when we know the tangents of the individual angles. It's a powerful tool, providing a way to relate the tangents of multiple angles into one equation.
One important identity used in solving this problem is the tangent sum identity. The identity states that for any angles \(A\) and \(B\), \(\tan(A + B) = \frac{\tan A + \tan B}{1 - \tan A \cdot \tan B}\). This formula allows us to find the tangent of the sum of two angles when we know the tangents of the individual angles. It's a powerful tool, providing a way to relate the tangents of multiple angles into one equation.
Trigonometric Equations
Trigonometric equations involve trigonometric functions like sine, cosine, and tangent. Solving these equations often requires the use of trigonometric identities. In the exercise provided, we are trying to prove that \(\alpha + \beta = \gamma\) using given tangent values. This involves manipulating and equating expressions.
To solve trigonometric equations, you typically need to:
To solve trigonometric equations, you typically need to:
- Identify known values or expressions (in this case \(\tan \alpha, \tan \beta,\) and \(\tan \gamma\))
- Use identities to set up relationships between the angles, as with \(\tan(\alpha + \beta) = \tan \gamma\)
- Simplify and solve for the desired variable or angle relation
Algebraic Manipulation
Algebraic manipulation refers to the process of rearranging equations and expressions to simplify or solve them. It involves using algebraic rules and operations, like addition, subtraction, and factoring, to transform an expression into a more useful form.
In the context of this exercise, once the tangent sum identity has been applied, algebraic manipulation is essential to simplify the resulting expression. You have to substitute the known tangent values and then simplify the fraction to confirm the relationship between the angles.
In the context of this exercise, once the tangent sum identity has been applied, algebraic manipulation is essential to simplify the resulting expression. You have to substitute the known tangent values and then simplify the fraction to confirm the relationship between the angles.
- This involves combining fractions, simplifying roots, and canceling terms.
- The goal is to see if \(\tan(\alpha + \beta)\) simplifies exactly to \(\tan \gamma\).
Other exercises in this chapter
Problem 15
For any real \(x\), the maximum value of \(\cos ^{2}(\cos x)+\sin ^{2}(\sin x)\) is (a) 1 (b) \(1+\sin ^{2} 1\) (c) \(1+\cos ^{2} 1\) (d) None.
View solution Problem 15
Find the maximum value of \(12 \sin \theta-9 \sin ^{2} \theta\).
View solution Problem 16
If \(\operatorname{cosec} \theta-\sin \theta=a^{3}\) and \(\sec \theta-\cos \theta=b^{3}\), then find the value of \(a^{2} b^{2}\left(a^{2}+b^{2}\right)\).
View solution Problem 17
If \(\alpha\) and \(\beta\) are acute angles and \(\cos 2 \alpha=\frac{3 \cos 2 \beta-1}{3-\cos 2 \beta}\), prove that \(\tan \alpha: \tan \beta=\sqrt{2}: 1\).
View solution