Problem 16
Question
\(f(x)=\left\\{\begin{aligned} 5-2 x & \text { if } x<3 \\ 3 x-10 & \text { if } 3 \leq x \end{aligned}\right.\)
Step-by-Step Solution
Verified Answer
For \(x = 2\), \(f(2) = 1\). For \(x \geq 3\), \(f(4)=2\).
1Step 1: Analyze the given piecewise function
The function is given as: \[ f(x) = \begin{cases} 5 - 2x & \text{if } x < 3 \ 3x - 10 & \text{if } x \geq 3 \end{cases} \] This indicates that the function has different expressions based on the value of \(x\). When \(x < 3\), use the equation \(5 - 2x\). When \(x \geq 3\), use the equation \(3x - 10\).
2Step 2: Evaluate the function at specific points
Choose points for evaluation from both domains. For example: - To find \(f(2)\), since \(2 < 3\), use \(5 - 2(2)\). - To find \(f(4)\), since \(4 \geq 3\), use \(3(4) - 10\).
3Step 3: Calculate using the appropriate expressions
Substitute the values: - For \(f(2)\), calculate: \[ f(2) = 5 - 2(2) = 5 - 4 = 1 \] - For \(f(4)\), calculate: \[ f(4) = 3(4) - 10 = 12 - 10 = 2 \]
4Step 4: Summarize the findings
Using the piecewise function, we evaluated two points: - \(f(2) = 1\) - \(f(4) = 2\)
Key Concepts
Function EvaluationDomain-Specific CalculationsStep-by-Step Solution
Function Evaluation
Understanding piecewise functions starts with function evaluation. A piecewise function is defined by different expressions for different ranges of the independent variable, typically denoted as x.
In the provided exercise, the function is:
\[ f(x) = \begin{cases} 5 - 2x & \text{if } x < 3 \ 3x - 10 & \text{if } x \geq 3 \end{cases} \]
This means:
Function evaluation involves determining which part of the piecewise function to use based on the value of x. The key is to carefully assess which condition x fulfills and then apply the corresponding equation. This ensures accurate calculation of function values for specific points.
In the provided exercise, the function is:
\[ f(x) = \begin{cases} 5 - 2x & \text{if } x < 3 \ 3x - 10 & \text{if } x \geq 3 \end{cases} \]
This means:
- Use the formula \(5 - 2x\) when \(x\) is less than 3.
- Use the formula \(3x - 10\) when \(x\) is 3 or greater.
Function evaluation involves determining which part of the piecewise function to use based on the value of x. The key is to carefully assess which condition x fulfills and then apply the corresponding equation. This ensures accurate calculation of function values for specific points.
Domain-Specific Calculations
Calculating values for piecewise functions involves domain-specific processes where you must match conditions to the correct expressions. Let's break it down using the given function.
When we need to find \(f(2)\):
Similarly, for \(f(4)\):
These simple steps ensure correct domain-specific calculations, making sure each value is correctly evaluated according to its appropriate function range.
When we need to find \(f(2)\):
- First, identify which part of the function to use. Since \(2 < 3\), we use the expression \(5 - 2x\).
- Substitute \(x = 2\) into the expression: \[ f(2) = 5 - 2(2) \]
- Solve the equation: \[ f(2) = 5 - 4 = 1 \]
Similarly, for \(f(4)\):
- Since \(4 \geq 3\), use the expression \(3x - 10\).
- Substitute \(x = 4\) into the expression: \[ f(4) = 3(4) - 10 \]
- Solve the equation: \[ f(4) = 12 - 10 = 2 \]
These simple steps ensure correct domain-specific calculations, making sure each value is correctly evaluated according to its appropriate function range.
Step-by-Step Solution
Let's walk through the solution using a step-by-step approach to make things clearer:
Step 1: Analyze the given piecewise function to understand its structure. The function is:
\[ f(x) = \begin{cases} 5 - 2x & \text{if } x < 3 \ 3x - 10 & \text{if } x \geq 3 \end{cases} \]
Step 2: Choose points for evaluation to cover different parts of the function. For instance, pick \(x = 2\) and \(x = 4\).
Step 3: Calculate using the appropriate expressions.
Phew! We just evaluated the function at two different points. This is critical for understanding how piecewise functions change behavior depending on the values of x.
Step 4: Summarize the findings. Using the piecewise function, we've determined:
Simplified approaches like this ensure a strong grasp of evaluating piecewise functions. Keep practicing these steps to master the concept!
Step 1: Analyze the given piecewise function to understand its structure. The function is:
\[ f(x) = \begin{cases} 5 - 2x & \text{if } x < 3 \ 3x - 10 & \text{if } x \geq 3 \end{cases} \]
Step 2: Choose points for evaluation to cover different parts of the function. For instance, pick \(x = 2\) and \(x = 4\).
- To find \(f(2)\), since \(2 < 3\), use \(5 - 2(2)\).
- To find \(f(4)\), since \(4 \geq 3\), use \(3(4) - 10\).
Step 3: Calculate using the appropriate expressions.
- For \(f(2)\), substitute \(x = 2\): \[ f(2) = 5 - 2(2) = 1 \]
- For \(f(4)\), substitute \(x = 4\): \[ f(4) = 3(4) - 10 = 2 \]
Phew! We just evaluated the function at two different points. This is critical for understanding how piecewise functions change behavior depending on the values of x.
Step 4: Summarize the findings. Using the piecewise function, we've determined:
- \(f(2) = 1\)
- \(f(4) = 2\)
Simplified approaches like this ensure a strong grasp of evaluating piecewise functions. Keep practicing these steps to master the concept!
Other exercises in this chapter
Problem 15
\(f(x)=(x+1)^{3}(x-2)^{2}\)
View solution Problem 15
The demand equation for a certain commodity is \(x+p=14\), where \(x\) is the number of units produced daily and \(p\) is the number of hundreds of dollars in t
View solution Problem 16
Given \(f(x)=x^{r}-r x+k\), where \(r>0\) and \(r \neq 1\), prove that (a) if \(01, f\) has a relative minimum value at \(1 .\)
View solution Problem 17
\(f(x)= \begin{cases}2 x+9 & \text { if } x \leq-2 \\ x^{2}+1 & \text { if }-2
View solution